Fill in the blanks with thr correct verb form of past simple: have, enjoy, be(x4), play(x2), clap

Yesterday, there (0) ......was........a concert at school. Everyone in the audience (1) ..........had.......... programmes about the concert.

Kate and Janes (2) ........were........ on the stage frist. They (3) .....played........ the recorder. Tom (4) ............was..........next to on the stage. He (5)...........played......... his trumpet.

The audience (6) .........claped....... at the end. They all (7) .......enjoyed...........the concert. It (8) ......was....... fantastic.

Fill in the blanks with thr correct verb form of past simple: have, enjoy, be(x4), play(x2), clap

Yesterday, there (0) .......was.......a concert at school. Everyone in the audience (1) ..........had.......... programmes about the concert.

Kate and Janes (2) ......were.......... on the stage frist. They (3) .....played........ the recorder. Tom (4) ..........was............next to on the stage. He (5).......played............. his trumpet.

The audience (6) ......claped.......... at the end. They all (7) ...enjoyed...............the concert. It (8) .....was........ fantastic.

Bài 1 ; Hoàn thành câu sau đúng dạng thì quá khứ đơn 

1 . It / be / cloudy / yesterday .

=> It was cloudy yesterday .

2. How / you / get there ?

=> How did you get there ?

3. I / play / football / last / Sunday .

=> I played football last Sunday.

2.were

3.played

4.was

5.played

6.was

7.played

8.was

b: \(=x\left(x-3\right)\left(x^2+3x+9\right)\)

a/ 2x^2 (x – 1) + 4x (1 – x)

= 2x^2(x  – 1) – 4x (x – 1)

= (x – 1)( 2x^2 – 4x)

=2x(x – 1)(x – 2)

x2 , x3... = x^2, x^3

giúp mik gấp ạ

a. (x + 1)(1 + x - 2x + 3x - 4x) - (x - 1)(1 + x + 2x + 3x + 4x)

= (x + 1)(1 - 2x) - (x - 1)( 1 + 10x)

= x - 2x² + 1 - 2x - x - 10x² + 1 + 10x

= x - 2x - x + 10x - 2x² - 10x² + 1 + 1

= 8x - 8x² + 2

= -8x + 8x + 2

= -(-8x + 8x + 2)

= 8x² - 8x - 2

= 8x² - 4x - 4x - 2

= 4x(2x - 1) - 2(2x + 1)

mình xin ý b

b. (2b2 - 2 - 5b + 6b3)(3 + 3b2 - b)

= (4b - 2 - 5b + 18b)(3 + 6b - b)

= (17b - 2)(3 + 5b)

= 51b + 85b² - 6 + 10b

= 85b² + 51b + 10b - 6

= \(51b\left(\dfrac{5}{3}+1\right)+6\left(\dfrac{5}{3}-1\right)\)

Bạn ghi rõ lại đề đi bạn, khó hiểu quá

a. 

$x^2-y^2-2x+2y=(x^2-y^2)-(2x-2y)=(x-y)(x+y)-2(x-y)=(x-y)(x+y-2)$

b.

$x^2(x-1)+16(1-x)=x^2(x-1)-16(x-1)=(x-1)(x^2-16)=(x-1)(x-4)(x+4)$

c.

$x^2+4x-y^2+4=(x^2+4x+4)-y^2=(x+2)^2-y^2=(x+2-y)(x+2+y)$

d.

$x^3-3x^2-3x+1=(x^3+1)-(3x^2+3x)=(x+1)(x^2-x+1)-3x(x+1)$

$=(x+1)(x^2-4x+1)$

e.

$x^4+4y^4=(x^2)^2+(2y^2)^2+2.x^2.2y^2-4x^2y^2$

$=(x^2+2y^2)^2-(2xy)^2=(x^2+2y^2-2xy)(x^2+2y^2+2xy)$

f.

$x^4-13x^2+36=(x^4-4x^2)-(9x^2-36)$

$=x^2(x^2-4)-9(x^2-4)=(x^2-9)(x^2-4)=(x-3)(x+3)(x-2)(x+2)$

g.

$(x^2+x)^2+4x^2+4x-12=(x^2+x)^2+4(x^2+x)-12$

$=(x^2+x)^2-2(x^2+x)+6(x^2+x)-12$

$=(x^2+x)(x^2+x-2)+6(x^2+x-2)=(x^2+x-2)(x^2+x+6)$

$=[x(x-1)+2(x-1)](x^2+x+6)=(x-1)(x+2)(x^2+x+6)$

h.

$x^6+2x^5+x^4-2x^3-2x^2+1$

$=(x^6+2x^5+x^4)-(2x^3+2x^2)+1$

$=(x^3+x^2)^2-2(x^3+x^2)+1=(x^3+x^2-1)^2$

\(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}=\left(x-1\right)^2\)