\(8\frac{1}{5}\times\left(11\frac{94}{1591}-6\frac{38}{1517}\right)\div8\frac{11}{43}\)
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Thực hiện phép tính : \(8\frac{1}{5}\times \left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\\ =8\frac{1}{5}.5\frac{60}{1763}:8\frac{11}{43}\\ =41\frac{12}{43}:8\frac{11}{43}\\ =5\)
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giá trị biểu thức A=\(8\frac{1}{5}\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
8 la hon so ma
6 cung la hon so
11 cung lka hon so
bai nay co giao lop em day roi nhung em moi lop 4 thoi
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Tính
\(a,\frac{5}{6}+6\frac{5}{6}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(b,1\frac{1}{6}+6\frac{5}{6}.\left(10\frac{133}{2173}-5\frac{23}{1643}\right):41\frac{12}{31}\)
Tớ ko bít phải làm sao bây giờ ?
tô ? ko ? bít ?
-_-! ai thick tích cu !
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mk chỉ tính đc kết quả phần a) thôi..
a, = 5
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Xem thêm câu trả lời
Tính: \(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{37.11.15.37}\right)\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(\frac{1,6:\left(1\frac{3}{5}.1,25\right)}{0,64-\frac{1}{25}}-\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-2\frac{1}{4}\right).2\frac{2}{17}}+0,6.0,5:\frac{2}{5}\)
Tínha)frac{5}{6}+6frac{5}{6}.(11frac{94}{1591}-6frac{38}{1517}):8frac{11}{43}b) 1frac{1}{6}+6frac{5}{6}.left(10frac{133}{2173}-5frac{23}{1643}right):41frac{12}{31}c)frac{0,8:left(frac{4}{5}.1,25right)}{0,64-frac{1}{25}}+frac{left(1,08-frac{2}{25}right):frac{4}{7}}{left(6frac{5}{9}-3frac{1}{4}right).2frac{2}{17}}-left(1,2.0,5right):frac{4}{5}
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Tính
a)\(\frac{5}{6}\)+\(6\frac{5}{6}\).(\(11\frac{94}{1591}-6\frac{38}{1517}\)):\(8\frac{11}{43}\)
b) \(1\frac{1}{6}+6\frac{5}{6}.\left(10\frac{133}{2173}-5\frac{23}{1643}\right):41\frac{12}{31}\)
c)\(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{17}}-\left(1,2.0,5\right):\frac{4}{5}\)
1.
b) \(B=8\dfrac{1}{5}.\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
c) \(C=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)
\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)
\(=5\)
c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)
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tính N = \(8\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
\(N=8\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
\(N=\dfrac{41}{5}\left(\dfrac{17595}{1591}-\dfrac{9140}{1517}\right):\dfrac{355}{43}\)
\(N=\dfrac{41}{5}.\dfrac{8875}{1763}:\dfrac{355}{43}\)
\(N=\dfrac{1775}{43}:\dfrac{355}{43}\)
\(N=5.\)
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