12341234 . 5678 - 56785678 .1234

= 1234.10001 . 5678 - 5678.10001.1234

= 0

Đề thiếu z

Ta có: \(\dfrac{1}{10001}=\dfrac{1234}{x}=\dfrac{y}{45674567}=\dfrac{2345}{t}\)

\(\Rightarrow\left\{{}\begin{matrix}x=1234.10001=12341234\\y=\dfrac{45674567}{10001}=4567\\t=2345.10001=23452345\end{matrix}\right.\)

Vì 1/10001 = 1234/x => x = 10001.1234 = 12341234

Vì 1/10001 = y/45674567 => y = y.10001 = 45674567 <=>

y = 4567

Vì 1/10001 = 2345/t => t = 10001.2345 = 23452345

Vậy...

Answer:

\(\frac{1}{10001}=\frac{1234}{x}=\frac{y}{45674567}=\frac{2345}{t}\)

\(\Rightarrow\hept{\begin{cases}x=1234.10001=12341234\\y=45674567:10001=4567\\t=2345.10001=23452345\end{cases}}\)

sao ko ai trả lời zậy

4567 + 1234 -4567 -4

 = 4567 - 4567 + 1234 - 4

= 0+ 1230

= 1230

\(4567+\left(1234-4567\right)-4\)

\(=4567+1234-4567-4\)

\(=\left(4567-4567\right)+\left(1234-4\right)\)

\(=0+1230\)

\(=1230\)

Trả lời: 

4567 + ( 1234 - 4567 ) - 4 

= 4567 + 1234 - 4567 - 4 

= ( 4567 - 4567 ) + ( 1234 - 4 ) 

= 0 + 1230

= 1230

a,b đều =0

bạn trình bày ra luôn nhé

a,12341234 nhân 5678 - 56785678 nhân 1234

  = 1234 x 5678 x 10001 - 1234 x 5678 x 10001

= 0

b,(1+3+5+....+97+99)nhân(3737 nhân 38 - 3838 nhân 37)

= (38 x 37  x 101 -  37 x 38x 101)

= 0:(1+3+5+....+97+99)

= 0

a) Ta có: \(4567+1234-4567-\left(-66\right)\)

\(=4567-4567+1234+66\)

\(=1234+66=1300\)

b) Ta có: \(2004-15+54-2004-54\)

\(=\left(2004-2004\right)+\left(54-54\right)-15\)

\(=0+0-15\)

\(=-15\)

c) Ta có: \(-45789-357-45789+57\)

\(=-91578-300=-91878\)

4567 + 1234 = 5801

5801 :)))

bag

5081

k minh nha

a.... ko bit

có đáp án rùi mà

a ukm ha

\(1)5-(1997-2005)+1997\)

\(=5-1997+2005+1997\)

\(=(-1997+1997)+(5+2005)\)

\(=0+2010\)

\(=2010\)

\(2)4567+(1234-4567)-4\)

\(=4567+1234-4567-4\)

\(=(4567-4567)+(1234-4)\)

\(=0+1230\)

\(=1230\)