\(\dfrac{12}{18}=\dfrac{24}{36}=\dfrac{72}{108}=\dfrac{12+24+72}{18+36+108}=\dfrac{12-24+72}{18-36+108}\)

tất cả các tỉ số bạn nêu đều bằng 2/3

Ta có: \(\dfrac{-5}{x}=\dfrac{-y}{8}=\dfrac{-18}{72}\)

\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{-5}{x}=-\dfrac{18}{72}=\dfrac{-1}{4}\\\dfrac{-y}{8}=\dfrac{-18}{72}=\dfrac{-1}{4}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=20\\y=2\end{matrix}\right.\)

Vậy: (x,y)=(20;2)

\(\dfrac{-5}{x}=\dfrac{-y}{8}=\dfrac{-18}{72}\) 

+)\(\dfrac{-5}{x}=\dfrac{-18}{72}\) 

\(\Rightarrow x=\dfrac{-5.72}{-18}=20\) 

+)\(\dfrac{-y}{8}=\dfrac{-18}{72}\) 

\(\Rightarrow-y=\dfrac{-18.8}{72}=-2\) 

\(\Rightarrow y=2\)

\(N=\frac{1}{3.6}+\frac{1}{6.9}+...+\frac{1}{30.33}\)

=\(\frac{1}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+...+\frac{1}{30}-\frac{1}{33}\right)\)

=\(\frac{1}{3}\left(\frac{1}{3}-\frac{1}{33}\right)=\frac{10}{33}\)

\(M=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{4970}\)

\(M=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{70.71}\)

\(M=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{70}-\frac{1}{71}\)

\(M=1-\frac{1}{71}\)

\(M=\frac{70}{71}\)

\(N=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)

\(N=\frac{1}{3.6}+\frac{1}{6.9}+\frac{1}{9.12}+...+\frac{1}{30.33}\)

\(N=\frac{1}{3}.\left(\frac{3}{3.6}+\frac{3}{6.9}+\frac{3}{9.12}+...+\frac{3}{30.33}\right)\)

\(N=\frac{1}{3}.\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{30}-\frac{1}{33}\right)\)

\(N=\frac{1}{3}.\left(\frac{1}{3}-\frac{1}{33}\right)\)

\(N=\frac{1}{3}.\frac{10}{33}\)

\(N=\frac{10}{99}\)

-18/72=-2/8=-4/16. Suy ra x=-4 

-5/x=-2/8.Suy ra -5.8=-2.x

-40=-2x

x=20

\(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)

\(\Rightarrow360-5x=3x-54\)

\(\Rightarrow-5x-3x=-54-360\)

\(\Rightarrow-8x=-414\)

\(\Rightarrow x=207\)

\(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow\frac{\left(72-x\right).5}{15}=\frac{3\left(x-18\right)}{15}\)

\(\Rightarrow\left(72-x\right).5=3\left(x-18\right)\)

\(\Rightarrow360-5x=3x-54\)

\(\Rightarrow-3x-5x=-360-54\)

\(\Rightarrow-8x=-414\)

\(\Rightarrow x=51,75\)

+) Vì \(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)

     \(5.72-5x=3x-3.18\)

      \(360-5x=3x-54\)

       \(-5x-3x=-54-360\)

       \(-8x=-414\)

              \(x=-414:\left(-8\right)\)

              \(x=51,75\)

      Vậy x = 51,75

\(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Leftrightarrow5\left(7x-2\right)=3\left(x-18\right)\)

\(\Leftrightarrow360-5x=3x-54\)

\(\Leftrightarrow360=3x-54+5x\)

\(\Leftrightarrow360=8x-54\)

\(\Leftrightarrow8x-54=360\) (chuyển vế)

\(\Leftrightarrow8x=360+54\)

\(\Leftrightarrow8x=414\)

\(\Leftrightarrow x=\frac{414}{8}=\frac{207}{4}\)

\(\Rightarrow x=\frac{207}{4}\)

X= 0,300323265 nha

<=> (x-18/74 - 1)+(x-20/72 - 1)+(x-22/70 - 1) = 0

<=> x-92/74 + x-92/72 + x-92/70 = 0

<=> (x-92).(1/74+1/72+1/70) = 0

<=> x-92 = 0 ( vì 1/74 + 1/72 + 1/70 > 0 )

<=> x=92

Vậy S = {92}

Tk mk nha

Ta có :

\(\frac{x-18}{74}+\frac{x-20}{72}+\frac{x-22}{70}=3\)

\(\Leftrightarrow\)\(\left(\frac{x-18}{74}-1\right)+\left(\frac{x-20}{72}-1\right)+\left(\frac{x-22}{70}-1\right)=3-3\)

\(\Leftrightarrow\)\(\frac{x-92}{74}+\frac{x-92}{72}+\frac{x-92}{70}=0\)

\(\Leftrightarrow\)\(\left(x-92\right)\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)=0\)

Vì \(\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)\ne0\)

\(\Rightarrow\)\(x-92=0\)

\(\Rightarrow\)\(x=92\)

Vậy \(x=92\)

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