25 x X - 100 = 6 x X + 20
bÝ rồi
cau1 :120-(100+x)=25
cau2: 5(x+23)+6=96
cau3: 100-(25+x)=40
cau4: 35-9(x+2)=45
cau1 :120-(100+x)=25
100+x=120-25
100+x=95
x=-5
cau2: 5(x+23)+6=96
5(x+23)+6=96
5(x+23)=90
x+23=18
x=-5
cau3: 100-(25+x)=40
25+x=100-40
25+x=60
x=35
cau4: 35-9(x+2)=45
9(x+2)=-10
x+2=-10/9
x=-28/9
Áp dụng tính chất của phép nhân, tính theo mẫu:
Mẫu: 24 x 25 = 6 x 4 x 25 = 6 x 100 = 600
a) 35 x 8 c) 24 x 125
b) 36 x 5 d) 5 x 48
Đơn giản biểu thức, rồi tìm x :
a) x+22+(-14)+52=25
b) (-90)-(p+10)+100-25=50
c) 4-(27-3)=x-(13-4)
Tim x:
a) 6 x X - 5 = 613 b) 12 x X + 3 x X = 30
C) 125 - 25 x (X - 1) = 100 d) ( X - 2 ) x 9 X - 4) = 0
`#040911`
`a)`
`6 \times x - 5 = 613`
`=> 6 \times x = 613 + 5`
`=> 6 \times x = 618`
`=> x = 618 \div 6`
`=> x = 103`
Vậy, `x = 103`
`b)`
`12 \times x + 3 \times x = 30`
`=> x \times (12 + 3) = 30`
`=> x \times 15 = 30`
`=> x = 30 \div 15`
`=> x = 2`
Vậy, `x = 2`
`c)`
`125 - 25 \times (x - 1) = 100`
`=> 25 \times (x - 1) = 125 - 100`
`=> 25 \times (x - 1) = 25`
`=> x - 1 = 25 \div 25`
`=> x - 1 = 1`
`=> x = 1 + 1`
`=> x = 2`
Vậy, `x = 2`
`d)`
`(x - 2) \times (9x - 4) = 0?`
`=>`
TH1: `x - 2 = 0`
`=> x = 0 + 2`
`=> x = 2`
TH2: `9x - 4 = 0`
`=> 9x = 4`
`=> x = 4/9`
Vậy, `x \in {2; 4/9}.`
\(a,6x-5=613\\ \Leftrightarrow6x=618\\ \Leftrightarrow x=103\\ b,12x+3x=30\\ \Leftrightarrow15x=30\\ \Leftrightarrow x=2\\ c,125-25\left(x-1\right)=100\\ \Leftrightarrow25\left(x-1\right)=25\\ \Leftrightarrow x-1=1\\ \Leftrightarrow x=2\\ d,\left(x-2\right)\cdot\left(9x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{4}{9}\end{matrix}\right.\)
25 x 4 x 32 + 16 x 2 x 50
----------------------------------
100 x 6 x 8 x2
\(\frac{25x4x32+16x2x50}{100x6x8x2}=\frac{100x16x2+16x100}{100x6x16}=\frac{100x16\left(2+1\right)}{100x16x6}=\frac{3}{6}=\frac{1}{2}.\)
~~ học tốt nhé ~~~
25 x 4 x 32 + 16 x 2 x 50 =321600
100 x 6 x 8 x2 =14400
hok tốt
{ 25 x [ 100 : 4 - 1 ( 38 x 2 - 6 ) ] }
Trả lời
{25.[100:4-1(38.2-6)]}
={25.[100:4-1(76-6)]}
={25.[100:4-1.70]}
={25.[25-70]}
={25.(-45)}
=-1125.
\(\left\{25\times\left[100:4-1\left(38\times2-6\right)\right]\right\}\)
\(=\left\{25\times\left[100:4-1\left(76-6\right)\right]\right\}\)
\(=\left\{25\times\left[100:4-1\times70\right]\right\}\)
\(=\left\{25\times\left[100:4-70\right]\right\}\)
\(=\left\{25\times\left[25-70\right]\right\}\)
\(=\left\{25\times\left(-45\right)\right\}\)
\(=-1125\)
{ 25 x [ 100 : 4 - 1 . ( 38 x 2 - 6 ) ] }
= { 25 x [ 25 - 1. 70 ] }
= { 25 x ( - 45 ) }
= - 1125
8. Bỏ dấu ngoặc rồi tính:
a) ( 17 – 229) + ( 17 - 25 + 229) ; b) ( 125 – 679 + 145) – ( 125 – 679 )
9. Tìm x biết: a) 15 – ( 4 – x) = 6 ; b) - 30 + ( 25 – x) = - 1 ;
c) x – ( 12 – 25) = -8 ; d) ( x – 29 ) – ( 17 – 38 ) = - 9
10. Tìm số nguyên x biết: a) x – 5 = - 1 ; b) x + 30 = - 4; c) x – ( - 24) = 3 ; d) 22 – ( - x ) = 12; e) ( x + 5 ) + ( x – 9 ) = x + 2 ; f) ( 27 – x ) + ( 15 + x ) = x – 24 .
BÀi 1: a) 5 + (-7) + 9 + (-11) +... +25 + (-27)
b) (-100) + 112 + ( -114 ) +... + (-198) + 200
BÀi 2 : Tìm các số nguyên x rồi tính tổng của chúng
a) -14 nhỏ hơn hoặc bằng x < 23
b) -15<x<30
c) -6 <x + (-3) <-4
Cho f(x) = x^8-101.x^7 +101.x^6 - 101.x^5+...+ 101.x^2 - 101.x + 25
Tìm f(100)