A=1²/1.2 .2²/2.3 .3²/3.4 .4²/4.5

=1/2. 2.2/2.3 .3.3/3.4 .4.4/4.5

=1/2.2/3.3.4.4./5

=1/5

\(-5\)

 1+1-1+2-2+3-3+4-4x5:2 = 15

Bằng 2.5 bạn ạ, nhớ k đúng cho mình nhé ^^

\(A=2\sqrt{27}-\sqrt{75}-\sqrt{\frac{4}{3}}\)\(=2\sqrt{9.3}-\sqrt{25.3}-\sqrt{\frac{4.3}{9}}\)\(=2.3\sqrt{3}-5\sqrt{3}-\frac{2}{3}\sqrt{3}\)\(=6\sqrt{3}-5\sqrt{3}-\frac{2}{3}\sqrt{3}\)\(=\frac{1}{3}\sqrt{3}\)\(=\frac{\sqrt{3}}{3}\)

=>1/4:(x-2/3)=2

=>(x-2/3)=1/8

=>x=1/8+2/3=3/24+16/24=19/24

13/4 - 1/4 : ( x - 2/3 )= 5/4

\(\Rightarrow\) 1/4 : ( x- 2/3 ) = 13/4 - 5/4

\(\Rightarrow\) 1/4 : ( x- 2/3)= 2

\(\Rightarrow\) x - 2/3 = 1/4 :2

\(\Rightarrow\) x- 2/3 = 1/8

\(\Rightarrow\) x= 1/8 +2/3 =19/24

Vậy x = 19/24

\(\dfrac{13}{4}-\dfrac{1}{4}\div\left(x-\dfrac{2}{3}\right)=\dfrac{5}{4}\\ \Rightarrow\dfrac{1}{4}\div\left(x-\dfrac{2}{3}\right)=\dfrac{13}{4}-\dfrac{5}{4}\\ \Rightarrow\dfrac{1}{4}\div\left(x-\dfrac{2}{3}\right)=\dfrac{8}{4}=2\\ \Rightarrow x-\dfrac{2}{3}=\dfrac{1}{4}\div2\\ \Rightarrow x-\dfrac{2}{3}=\dfrac{1}{4}\times\dfrac{1}{2}\\ \Rightarrow x-\dfrac{2}{3}=\dfrac{1}{8}\\ \Rightarrow x-\dfrac{16}{24}=\dfrac{3}{24}\\ \Rightarrow x=\dfrac{3}{24}+\dfrac{16}{24}\\ \Rightarrow x=\dfrac{19}{24}\)

Vậy \(x=\dfrac{19}{24}\) 

bằng 250/979

Đặt \(A=1+3^2+3^4+...+3^{100}\)

\(9A=3^2+3^4+3^6+...+3^{102}\)

\(9A-A=\left(3^2+3^4+3^6+...+3^{102}\right)-\left(1+3^2+3^4+...+3^{100}\right)\)

\(8A=3^{102}-1\)

\(A=\frac{3^{102}-1}{8}\)

Vậy \(A=\frac{3^{102}-1}{8}\)

Chúc bạn học tốt ~ 

Đặt A = 1 + 3^2 + 3^4 + 3^6 + ....+ 3^100

3^2A = 3^2 + 3^4 + 3^6 + ..+3^102

8A=3^2A - A = 3¹⁰² - 1

A = 3¹⁰² - 1/8

=. A = 3¹⁰² - 1 /8

Cam on nha

Đáp án : n = 3 ; 6 ; 9 ; 12 ; 15 ; ...

Bạn giải ra hộ mình được ko?

Làm thế nào mà ra n = 3 ; 6 ; 9 ; 12 ; 15 ; ... vậy?

22/3