91.25 - 91.13 - 91.12 = 91.(25 - 13 - 12) = 0

a: \(-472+\left(235-28\right)-\left(35-350\right)\)

\(=-472+235-28-35+350\)

\(=\left(-472-28\right)+\left(235-35\right)+350\)

=-500+350+200

=50

b: \(91\cdot172+91\cdot13-91\cdot85\)

\(=91\cdot\left(172+13-85\right)\)

\(=91\cdot100=9100\)

c: \(798-298:\left[19-2\left(5^2-22\right)^2\right]\cdot1^{2023}\)

\(=798-298:\left[19-2\left(25-22\right)^2\right]\)

\(=798-298:\left[19-2\cdot3^2\right]\)

\(=798-298:\left(19-18\right)\)

=798-298

=500

thiếu r

4,25 . 5 .20

=425

\(425\)

a) = (50-1)^2 = 50^2 - 2.50 + 1 = 2500 - 100 + 1 = 2401

b) = (50+1)^2 = 50^2 + 2.50 + 1 = 2601

c) = 9900

a) \(\left(-48\right)+10+\left(-22\right)+\left(-10\right)\)

\(=\left[\left(-48\right)+\left(-22\right)\right]+\left(-10+10\right)\)

\(=-70+0=-70\)

Tham khảo <3

= -70 

( hihi )

(-48)+(-22)+(10-10)

=-70 +0

=-70

\(a.75^2-50.75+25^2\\ =75^2-2.25.75+25^2\\ =\left(75-25\right)^2=50^2=2500\)

\(b.103.97\\ =\left(100+3\right)\left(100-3\right)\\ =100^2-3^2\\ =9991\)

\(a,75^2-50.75+25^2\\ =75^2-2.75.25+25^2\\ =\left(75+25\right)^2=100^2=10000\\ b,103.97\\ =\left(100+3\right).\left(100-3\right)\\ =100^2-3^2=10000-9=9991\)

a) \(75^2-2\cdot25\cdot75+25^2\)

= \(\left(75+25\right)^2\)

= \(100^2=10000\)
b) \(103\cdot97\)

= \(\left(100+3\right)\left(100-3\right)\)

= \(100^2-3^2\)

= \(10000-9=9991\)

làm giúp😢😢

a) 425.7.4-170.60

=85.5.7.4-85.2.60=85.(5.7.4-2.60)=85.20=1700

b) 8.9.14+6.17.12+19.4.18

=72.14+72.17+72.19=72.(14+17+19)=72.50=3600 

4996+2314+1003=8313

4996 + 2314 + 1003

= ( 4996 + 2314 ) + 1003

= 7310 + 1003

= 8313

4996+2314+1003=8313

Chúc bạn chăm ngoan học giỏi ,vâng lời ông bà , cha mẹ!!!.Kết bạn với mình nha!!!!!!!!!!!

a. Ta có: \(17^2-14.17+49=17^2-2.7.17+7^2=\left(17-7\right)^2=10^2=100\)

b. \(2021^2-2020^2=\left(2021-2020\right)\left(2021+2020\right)=4041\)