\(\frac{5-\frac{5}{3}+\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}+\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)

\(=\frac{5\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)

\(=\frac{5}{8}:\frac{15}{16}\)

\(=\frac{2}{3}\)

2/3

Tk mk nha

\(\frac{-7}{15}.\frac{5}{8}-\frac{2}{8}.\frac{7}{15}+\frac{1}{8}.\frac{-23}{15}=\frac{-7}{24}-\frac{7}{60}-\frac{23}{120}=-\frac{3}{5}\)

=-7/24-7/60+-23/120

=(-7/24-7/60)+-23/120

=-49/120+-23/120

=-3/5

tớ bấm máy tính hẳn hoi

\(=\frac{1}{8.15}\left(\left(-7\right).5-2.7+1.\left(-23\right)\right)=\frac{1}{8.15}\left(-35-14-23\right)\)

\(=\frac{1}{8.15}.\left(-72\right)=-\frac{9}{15}=-\frac{3}{5}\)

Lời giải:

$\frac{-3}{8}.\frac{2}{15}+\frac{-3}{8}.\frac{13}{15}+1\frac{3}{8}$

$=\frac{-3}{8}(\frac{2}{15}+\frac{13}{15})+1+\frac{3}{8}$

$=\frac{-3}{8}.\frac{15}{15}+1+\frac{3}{8}=\frac{-3}{8}+1+\frac{3}{8}=1$

Bài này bạn tính thôi

Trình bày ra 

Rồi làm thôi

Áp dụng công thức tính phân số ở Tiểu học

\(\frac{5\times\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\times\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}\div\frac{15\times\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\times\left(1-\frac{1}{11}+\frac{1}{121}\right)}=\frac{5}{8}\div\frac{15}{16}=\frac{2}{3}\)

F=5-5x(1/3+1/9-1/27) /8-8x(1/3+1/9-1/27)

: 15-15x(1/11+1/121) /16-16x(1/11+1/121)

=5-5x1/8-8x1

: 15-15x1/16-16x1

=0:0=0

chắc vậy!

\(=\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}-\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)

\(=\frac{5\left(1-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)

\(=\frac{5}{8}:\frac{15}{16}=\frac{5}{8}.\frac{16}{15}=\frac{2}{3}\)

-575/756                    

Bạn nhóm ra tương tự như 2 bài trước thôi

\(H=\frac{\frac{15}{8}-\frac{15}{6}-\frac{15}{32}+\frac{15}{63}}{3-\frac{3}{2}-\frac{3}{4}+\frac{3}{8}}\)

\(H=\frac{15\left(\frac{1}{8}-\frac{1}{6}-\frac{1}{32}+\frac{1}{63}\right)}{3\left(1-\frac{1}{2}-\frac{1}{4}+\frac{1}{8}\right)}\)

\(H=\frac{15\left[\left(\frac{1}{8}-\frac{1}{32}\right)-\frac{1}{6}+\frac{1}{63}\right]}{3\left[\left(1+\frac{1}{8}\right)-\frac{1}{2}-\frac{1}{4}\right]}\)

\(H=\frac{15\left[\frac{3}{32}-\frac{1}{6}+\frac{1}{63}\right]}{3\left[\frac{9}{8}-\frac{4}{8}-\frac{2}{8}\right]}\)

\(H=\frac{15\left[\frac{-7}{96}+\frac{1}{63}\right]}{3\cdot\frac{3}{8}}\)

\(H=\frac{15\left[\frac{-147}{2016}+\frac{32}{2016}\right]}{\frac{9}{8}}\)

\(H=\frac{15\cdot\frac{-115}{2016}}{\frac{9}{8}}\)

\(H=\frac{15\cdot\frac{-115}{2016}-\frac{2153}{2016}+\frac{2153}{2016}}{\frac{9}{8}}\)

\(H=\frac{15\cdot\frac{-2268}{2016}+\frac{2153}{2016}}{\frac{9}{8}}\)

\(H=\frac{15\cdot\frac{-9}{8}}{\frac{9}{8}}+\frac{\frac{2153}{2016}}{\frac{9}{8}}\)

\(H=\frac{-15\cdot\frac{9}{8}}{\frac{9}{8}}+\frac{\frac{2268}{2016}}{\frac{9}{8}}-\frac{\frac{115}{2016}}{\frac{9}{8}}\)

\(H=-15+1-0,0507054674 \)

\(H=-14-0,0507054674 \)

\(H=-14,0507055\)