so sanh a.A=-9/10^2010+-19/10^2011va b= -9/10^2011+-19/10^2010 B.TIM SO Nguyen xy biet x^2+y^2+6y+5=0;2x^2+3y^2+4x=19
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Cac ban giup may.khong quy dong so sanh;A=-9/10^2010+-9/10^2011 va B=-9/10^2011+-19/10^2010
\(A=\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\frac{-9}{10^{2010}}>\frac{-19}{10^{2010}}\)
\(\Rightarrow\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}>\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\Rightarrow A>B\)
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khong quy dong hay so sanh
A=-9/102010+-19/102011 ; B-9/102011+ -19/102010
A=10.(-9)/10^2010+-19/10^2011
=-90/10^2011+-19/10^2011
=-109/10^2011
B=-9/10^2011+10.-19/10^2010
=-9/10^2011+-190/10^2011
=-199/10^2011
Vì -109/10^2011>-199/10^2011
Nên: A>B
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KO QUY DONG MAU HAY SO SANH
\(A=\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
khong quy dong mau so hay so sanh;
A= \(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}};\) B= \(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
A= -9/10^2010 + (-19/10^2011) B= -9/10^2011 + (-19/10^2010) Không quy đồng mẫu số hãy so sánh
\(A=\dfrac{-9\cdot10+\left(-19\right)}{10^{2011}}=\dfrac{-28}{10^{2011}}\)
\(B=\dfrac{-9\cdot10-19}{10^{2011}}=\dfrac{-109}{10^{2011}}\)
=>A>B
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so sánh A= -9\10^2010+ -19\10^2011 ; B = -9\10^2011 + -19\10^2010. Giúp với . <3
A=\(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)
B=\(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
So sanh A va B
KHÔNG QUY ĐỒNG MẪU SỐ HÃY SO SÁNH: A=-9/10^2010+-19/10^2011; B=-9/10^2011+-19/10^2010
hay quy dong mau so so sanh sau : A=\(\dfrac{-9}{10^{2010}}\)+\(\dfrac{-19}{10^{2011}}\)
B =\(\dfrac{-9}{10^{2011}}\)+\(\dfrac{-19}{10^{2010}}\)
giup minh nhanh nha . cam on nhiu
\(A=\dfrac{-9}{10^{2010}}+\dfrac{-19}{10^{2011}}=\dfrac{-90}{10^{2011}}+\dfrac{-19}{10^{2011}}=\dfrac{\left(-90\right)+\left(-19\right)}{10^{2011}}=\dfrac{-109}{10^{2011}}\)\(B=\dfrac{-9}{10^{2011}}+\dfrac{-19}{10^{2010}}=\dfrac{-9}{10^{2011}}+\dfrac{-190}{10^{2011}}=\dfrac{\left(-9\right)+\left(-190\right)}{10^{2011}}=\dfrac{-199}{10^{2011}}\)\(\text{Vì }\dfrac{-109}{10^{2011}}>\dfrac{-199}{10^{2011}}\text{ nên }A>B\)
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