Tính 

a ) 1/2 x 1/4 x 1/6 

= 1/8 x 1/6

= 1/48

b ) 1/2 x 1/4 : 1/6

= 1/8:1/6

3/4

c ) 1/2 : 1/4 x 1/6 

= 2 x 1/6

= 1/3

tk mk nha ( nếu đúng )

hihi mơn nha !!!!!!!!!

a, : 1/2 x 1/4 x 1/6 = 1/8 x 1/6 = 1/48

b, ; 1/2 x 1/4 : 1/6 = 1/8 : 1/6 = 6/8 = 3/4

c, 1/2 : 1/4 x 1/6 = 4/2 x 1/6 = 4/12 = 1/3

tích đúng mình giải cho

= 1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5 x 6

= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6)

= 1 - 1/6

= 5/6

nha,mơn nhìu

\(\frac{1}{1}x\frac{1}{2}+\frac{1}{2}x\frac{1}{3}+\frac{1}{3}x\frac{1}{4}+\frac{1}{4}x\frac{1}{5}+\frac{1}{5}x\frac{1}{6}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)

\(=1-\frac{1}{6}=\frac{5}{6}\)

1/2x1/3+1/3-1/4+1/4x1/5

= 1/2-1/3+1/3-1/4+1/4-1/5

=1/2-1/5

=3/10. (1/2x1/3= 1/2x3) 

1/2x1/3+1/3-1/4+1/4x1/5 = 1/2-1/3+1/3-1/4+1/4-1/5 =1/2-1/5 =3/10. (1/2x1/3= 1/2x3)

  1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9

=7/18

`@Fù`

`=1/(1×2)+1/(2×3)+1/(3×4)+...+1/(72×73)`

`=1/1-1/2+1/2-1/3+...+1/72-1/73`

`=1-1/73`

`=72/73`

(1-1/2x1/2)x(1-1/3x1/3)x(1-1/4x1/4)x…x(1-1/2007x1/2007) = ( 1 - 1/4 ) x ( 1 - 1/9 ) x ( 1- 1/16) x .....x ( 1 - 1/4028049) = 3/4 x 8/9 x 15/16 x .....x 4028048 / 4028049 = 3 x 8 x 15 x .....x 4028048 / 4 x 9 x 16 x ......x 4028049 = 1 x 3 x 2 x 4 x 3 x 5 x .....x 2006 x 2008 / 2x2 x 3 x3 x 4 x 4 x .....x 2007 x 2007 = ( 1 x 2 x 3 x .....x 2006) x ( 3 x 4 x 5 x .....x 2008) / ( 2 x 3 x 4 x ....x 2007) x ( 2 x 3 x 4 x ....x 2007) = 2008 / 2007 x 2 = 1004 / 2007

(1-1/2x1/2)x(1-1/3x1/3)x(1-1/4x1/4)x…x(1-1/2007x1/2007)
= ( 1 - 1/4 ) x ( 1 - 1/9 ) x ( 1- 1/16) x .....x ( 1 - 1/4028049)
= 3/4 x 8/9 x 15/16 x .....x 4028048 / 4028049
= 3 x 8 x 15 x .....x 4028048 / 4 x 9 x 16 x ......x 4028049
= 1 x 3 x 2 x 4 x 3 x 5 x .....x 2006 x 2008 / 2x2 x 3 x3 x 4 x 4 x .....x 2007 x 2007
= ( 1 x 2 x 3 x .....x 2006) x ( 3 x 4 x 5 x .....x 2008) / ( 2 x 3 x 4 x ....x 2007) x ( 2 x 3 x 4 x ....x 2007)
= 2008 / 2007 x 2
= 1004 / 2007

Δ=(2m-1)^2-4*2*(m-1)

=4m^2-4m+1-8m+8

=4m^2-12m+9=(2m-3)^2>=0

=>PT luôn có 2 nghiệm

4x1^2+4x2^2+2x1x2=0

=>4[(x1+x2)^2-2x1x2]+m-1=0

=>4[(-2m+1)^2/4-2*(m-1)/2]+m-1=0

=>(2m-1)^2-4(m-1)+m-1=0

=>4m^2-4m+1-3m+3=0

=>4m^2-7m+4=0

=>\(m\in\varnothing\)