biết làm ở đề bài khác mà bài này khó quá

Trả lời :

\(\frac{y}{4}=\frac{36}{y}\)

\(=>y=12\)

\(\frac{y}{4}=\frac{36}{y}\)

\(\Rightarrow y.y=4.36\)

\(\Rightarrow y^2=144\)

\(\Rightarrow y^2=\left(\pm12\right)^2\)

Vậy \(y=\pm12\)

\(\frac{3}{-x}=\frac{x^2}{9}\)

\(\Rightarrow-x.x^2=3.9\)

\(-x^3=27\)

\(-x^3=3^3\)

\(\Rightarrow-x=3\)

\(\Rightarrow x=-3\)

\(\frac{6}{x}=\frac{y}{7}\)

\(\Rightarrow x.y=6.7\)

\(x.y=56\)

\(\Rightarrow x.y\inƯ\left(56\right)\)

\(\Rightarrow\orbr{\begin{cases}x=56\\y=1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\y=56\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-56\\x=-1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\y=-56\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2\\y=28\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=28\\y=2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-2\\y=-28\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-28\\y=-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\y=14\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=14\\y=4\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-4\\y=-14\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-14\\y=-4\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=7\\y=8\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=8\\y=7\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-7\\y=-8\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-8\\y=-7\end{cases}}\)

Vậy ..

chúc bạn học tốt

\(\dfrac{x}{9}< \dfrac{4}{7}< \dfrac{x+1}{9}\)

=>\(\dfrac{7x}{63}< \dfrac{36}{63}< \dfrac{7x+7}{63}\)

\(\Rightarrow7x< 36< 7x+7\)

\(\Rightarrow x< \dfrac{36}{7}< x+1\)

\(\Rightarrow x< 5\dfrac{1}{7}< x+1\)

\(\Rightarrow x=5\)

tik cho mình nhé

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\(\dfrac{x}{9}\) < \(\dfrac{4}{7}\) < \(x\) + \(\dfrac{1}{9}\)

\(\dfrac{7x}{63}\) < \(\dfrac{36}{63}\) < \(\dfrac{63x}{63}\) + \(\dfrac{7}{63}\)

7\(x\) < 36 < 63\(x\) + 7

⇒\(\left\{{}\begin{matrix}7x< 36\\63x+7>36\end{matrix}\right.\)⇒\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\63x>36-7\end{matrix}\right.\)⇒\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\63x>29\end{matrix}\right.\)⇒\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\x>\dfrac{29}{63}\end{matrix}\right.\)

\(\dfrac{29}{63}\)<  \(x\) < \(\dfrac{36}{7}\) vì \(x\in\) Z nên \(x\in\) { 1; 2; 3; 4; 5}

⇒ \(\dfrac{x}{9}\) = \(\dfrac{1}{9}\); \(\dfrac{2}{9}\); \(\dfrac{3}{9}\); \(\dfrac{4}{9}\);\(\dfrac{5}{9}\)

a, Áp dụng tc dtsbn:

\(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{x+y}{3+4}=\dfrac{14}{7}=2\\ \Rightarrow\left\{{}\begin{matrix}x=6\\y=8\end{matrix}\right.\)

b, Áp dụng tc dstbn:

\(\dfrac{a}{7}=\dfrac{b}{9}=\dfrac{3a-2b}{7\cdot3-2\cdot9}=\dfrac{30}{3}=10\\ \Rightarrow\left\{{}\begin{matrix}a=70\\b=90\end{matrix}\right.\)

c, Gọi 3 phần cần tìm là a,b,c

Áp dụng tc dstbn:

\(\dfrac{a}{2}=\dfrac{b}{3}=\dfrac{c}{4}=\dfrac{a+b+c}{2+3+4}=\dfrac{99}{9}=11\\ \Rightarrow\left\{{}\begin{matrix}a=22\\b=33\\c=44\end{matrix}\right.\)

-2/3

\(-\dfrac{2}{3}\)

\(-\dfrac{3}{7}.\dfrac{14}{9}=-\dfrac{2}{3}\)

bài này dễ mà

                                                            Bài giải

\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)

\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)

\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)

\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)

\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)

\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\) 

\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)

\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)

\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)

\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)

khó cậu ạ

\(\frac{3}{7}\times\frac{1}{3}+\frac{3}{7}\times\frac{4}{3}-\frac{3}{7}\times\frac{1}{9}\)

\(\frac{3}{7}\times\left(\frac{1}{3}+\frac{4}{3}-\frac{1}{9}\right)\)

\(\frac{3}{7}\times\left(\frac{5}{3}-\frac{1}{9}\right)\)

\(\frac{3}{7}\times\left(\frac{45}{27}-\frac{3}{27}\right)\)

\(\frac{3}{7}\times\frac{14}{9}\)

\(\frac{2}{3}\)

\(\frac{7}{15}\times\frac{6}{5}+\frac{3}{5}\times\frac{6}{5}-\frac{17}{30}:\frac{5}{6}\)

\(\frac{7}{15}\times\frac{6}{5}+\frac{3}{5}\times\frac{6}{5}-\frac{17}{30}\times\frac{6}{5}\)

\(\left(\frac{7}{15}+\frac{3}{5}-\frac{17}{30}\right)\times\frac{6}{5}\)

\(\left(\frac{14}{30}+\frac{18}{30}-\frac{17}{30}\right)\times\frac{6}{5}\)

\(\frac{1}{2}\times\frac{6}{5}\)

\(\frac{3}{5}\)

Chúc bạn học tốt !!!