A
Vô cơ
Câu 1: \(V=12,32\left(l\right)\)
Câu 2: \(n_{h^2}=0,075\left(mol\right)\)
Câu 3: \(m=49,25\left(g\right)\)
Câu 4: \(V=1,12\left(l\right)\)
Câu 5: Không có giá trị nào thỏa mãn đề bài.
Câu 6: \(n_{h^2}=0,12\left(mol\right)\)
Câu 7: \(m=53,3\left(g\right)\)
Câu 9: a) \(m_{Mg}=4,8\left(g\right);m_{Fe}=11,2\left(g\right)\)
b) \(C_{M\left(CuSO_4\right)}=1,5\left(M\right)\)
c) \(V_{NO}=6,72\left(l\right)\)
Câu 10: \(a=0,068\left(M\right)\)
Câu 11: \(Cu\left(NO_3\right)_2\)
Câu 12: \(m_{NaBr}=51,5\left(g\right)\)
Câu 13: \(m=15,8\left(g\right)\)
Câu 14: a) \(V=0,448\left(l\right)\)
b) \(m=3,16\left(g\right)\)
Câu 15: \(m=73,37\left(g\right)\)
Câu 16:a) \(m_{Al}=8,1\left(g\right);m_{Fe_xO_y}=16,48\left(g\right)\)
b) \(Fe_2O_3\)
Câu 17 : \(2,5\left(g\right)\)
Câu 18: \(9,85\left(g\right)\)
Câu 19: \(55,1\%\)
Câu 20: Giảm 1,84(g)
Câu 21: \(a=2\left(M\right)\)
Hữu cơ
Câu 1: \(C_2H_6;C_3H_8\)
Câu 3: Giảm \(56,8\left(g\right)\)
Câu 4: \(m=2\)
Câu 5: \(C_3H_4\)
B
Câu 1:
\(n_{No}=\frac{V}{22,4}=0,12\left(mol\right)\)
\(pthh:Fe+4HNO_3\rightarrow Fe\left(NO_3\right)_3+NO+2H_2O\left(1\right)\\ 3FeO+10HNO_3\rightarrow3Fe\left(NO_3\right)_3+NO+5H_2O\left(2\right)\\ 3Fe_3O_4+28HNO_3\rightarrow9Fe\left(NO_3\right)_3+NO+14H_2O\left(3\right)\\ Fe_2O_3+6HNO_3\rightarrow2Fe\left(NO_3\right)_3+3H_2O\left(4\right)\)
Đặt \(n_{Fe}=x\left(mol\right)\left(0< x< \frac{213}{700}\right)\)
\(n_{FeO}=y\left(mol\right)\left(0< y< \frac{71}{300}\right)\\ n_{Fe_3O_4}=z\left(mol\right)\left(0< z< \frac{213}{2900}\right)\\ n_{Fe_2O_3}=t\left(mol\right)\left(0< t< \frac{213}{2000}\right)\)
Theo \(pthh\left(1\right):n_{NO\left(1\right)}=n_{Fe}=x\left(mol\right)\)
\(n_{Fe\left(NO_3\right)_3\left(1\right)}=n_{Fe}=x\left(mol\right)\)
Theo \(pthh\left(2\right):n_{NO\left(2\right)}=\frac{1}{2}n_{FeO}=\frac{y}{3}\left(mol\right)\)
\(n_{Fe\left(NO_3\right)_3\left(2\right)}=n_{FeO}=y\left(mol\right)\)
Theo \(pthh\left(3\right):n_{NO\left(3\right)}=\frac{1}{3}n_{Fe_3O_4}=\frac{z}{3}\left(mol\right)\)
\(n_{Fe\left(NO_3\right)_3\left(3\right)}=3n_{Fe_3O_4}=3z\left(mol\right)\)
Theo \(pthh\left(4\right):n_{NO\left(4\right)}=2n_{Fe_2O_3}=2t\left(mol\right)\)
\(\Rightarrow n_{NO}=n_{NO\left(1\right)}+n_{NO\left(2\right)}+n_{NO\left(3\right)}+n_{NO\left(4\right)}\\ \Rightarrow x+\frac{y}{3}+\frac{z}{3}=0,12\\ \Rightarrow3x+y+z=0,36\)
\(\Rightarrow n_{Fe\left(NO_3\right)_3}=n_{Fe\left(NO_3\right)_3\left(1\right)}+n_{Fe\left(NO_3\right)_3\left(2\right)}+n_{Fe\left(NO_3\right)_3\left(3\right)}+n_{Fe\left(NO_3\right)_3\left(4\right)}\\ =x+y+3z+2t\)
Ta có: \(m_{Fe}+m_{FeO}+m_{Fe_3O_4}+m_{Fe_2O_3}=17,04\)
\(\Rightarrow56x+72y+232z+160t=17,04\\ \Rightarrow80\left(x+y+3z+2t\right)-8\left(3x+y+z\right)=17,04\\ \Rightarrow80n_{Fe\left(NO_3\right)_3}-8n_{NO}=17,04\\ \Rightarrow80n_{Fe\left(NO_3\right)_3}-8\cdot0,36=17,04\\ \Rightarrow80n_{Fe\left(NO_3\right)_3}=19,92\\ \Rightarrow n_{Fe\left(NO_3\right)_3}=0,249\)
\(\Rightarrow m_{Fe\left(NO_3\right)_3}=n\cdot M=0,249\cdot242=60,258\left(g\right)\)
Câu 2:
| A | \(CaO\) | P | \(CO_2\) |
| B | \(HCl\) | X | \(NaOH\) |
| C | \(CaCl_2\) | Q | \(NaHCO_3\) |
| D | \(AgNO_3\) | Y | \(Ba\left(OH\right)_2\) |
| E | \(Ca\left(NO_3\right)_2\) | R | \(Na_2CO_3\) |
| F | \(K_2CO_3\) | Z | \(Ca\left(OH\right)_2\) |
\(pthh:CaCO_3\xrightarrow[t^o]{}CaO+CO_2\left(1\right)\\ CaO+2HCl\rightarrow CaCl_2+H_2O\left(2\right)\\ CaCl_2+2AgNO_3\rightarrow Ca\left(NO_3\right)_2+2AgCl\left(3\right)\\ Ca\left(NO_3\right)_2+K_2CO_3\rightarrow CaCO_3+2KNO_3\left(4\right)\\ NaOH+CO_2\rightarrow NaHCO_3\left(5\right)\\ 2NaHCO_3+Ba\left(OH\right)_2\rightarrow Na_2CO_3+BaCO_3+2H_2O\left(6\right)\\ Na_2CO_3+Ca\left(OH\right)_2\rightarrow CaCO_3+2NaOH\left(7\right)\)
Đề thi thêm
Câu 1:
| A | \(Fe\) |
| B | \(FeCl_2\) |
| C | \(Fe\left(OH\right)_2\) |
| D | \(Fe_2O_3\) |
\(pthh:Fe+2HCl\rightarrow FeCl_2+H_2\left(1\right)\\ FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaCl\left(2\right)\\4 Fe\left(OH\right)_2+O_2\overset{t^o}{\rightarrow}2Fe_2O_3+4H_2O\\ Fe_2O_3+3H_2\overset{t^O}{\rightarrow}2Fe+3H_2O\)
Câu 2:
| A | \(\left(-C_6H_{10}O_5-\right)_n\) | X | \(H_2O\) | ||||
| B | \(C_6H_{12}O_6\) | ||||||
| \(C_1\) | \(C_2H_5OH\) | \(Y_1\) | \(O_2\) | \(C_2\) | \(CO_2\) | \(Y_2\) | \(Ca\left(OH\right)_2\) |
| \(D_1\) | \(CH_3COOH\) | \(Z_1\) | \(CuO\) | \(D_2\) | \(CaCO_3\) | \(Z_2\) | \(HCl\) |
| \(E_1\) | \(\left(CH_3COO\right)_2Ca\) | \(E_2\) | \(CaCl_2\) | ||||
| F | \(CaSO_4\) | T | \(H_2SO_4\) |
\(pthh:\left(-C_6H_{10}O_5-\right)_n+nH_2O\text{ }\underrightarrow{H^+}\text{ }nC_6H_{12}O_6\left(1\right)\\ C_6H_{12}O_6\xrightarrow[enzim]{30-35^oC}2C_2H_5OH+2CO_2\left(2\right)\\ C_2H_5OH+O_2\xrightarrow[]{men\text{ giấm}}CH_3COOH+H_2O\left(3\right)\)\(2CH_3COOH+Ca\left(OH\right)_2\rightarrow\left(CH_3COO\right)_2Ca+2H_2O\left(4\right)\\ \left(CH_3COO\right)_2Ca+H_2SO_4\rightarrow CaSO_4+2CH_3COOH\left(5\right)\\ CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\left(6\right)\)\(CaCO_3+2HCl\rightarrow CaCl_2+CO_2+H_2O\left(7\right)\\ CaCl_2+H_2SO_4\rightarrow CaSO_4+2HCl\left(8\right)\)