\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)

\(\frac{10}{3}x=-30\)

\(x=-9\)

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)

\(\frac{10}{3}x=-30\)

\(x=-9\)

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(\frac{10}{3}x=-13,25-16\frac{3}{4}\)

\(\frac{10}{3}x=-30\)

\(x=-9\)

nhân chéo là đc:

3(x+2)=-4(x-5)

3x+6=-4x+20

3x+4x=20-6

7x     =14

 x      =2

Vậy x=2

\(\frac{3}{4}+\frac{1}{5}:\frac{7}{10}\)

\(=\frac{3}{4}+\frac{2}{7}\)

\(=\frac{29}{28}\)

\(\frac{3}{4}\)+    \(\frac{1}{5}\):    \(\frac{7}{10}\)=    \(\frac{3}{4}\)+    \(\frac{2}{7}\)

                                         =    \(\frac{28}{28}\)=    1

3/4 + 1/5 : 7/10 = 3/4 + 2/7 = 21/28 + 8/28 = 29/28

\(4\left(x+1\right)^2=\sqrt{2\left(x^4+x^2+1\right)}\)

\(\Leftrightarrow16\left(x+1\right)^4=2\left(x^4+x^2+1\right)\)

\(\Leftrightarrow\left(x^2+3x+1\right)\left(7x^2+11x+7\right)=0\)

\(\sqrt{\frac{x+56}{16}+\sqrt{x-8}}=\frac{x}{8}\)

\(\Leftrightarrow2\sqrt{x+56+16\sqrt{x-8}}=x\)

\(\Leftrightarrow2\sqrt{\left(\sqrt{x-8}+8\right)^2}=x\)

\(\Leftrightarrow2\sqrt{x-8}+16=x\)

\(\Leftrightarrow x=24\)

1) Tìm x

\(\frac{11}{2}.x+\frac{1}{3}.x=1\)

\(\Rightarrow x\left(\frac{11}{2}+\frac{1}{3}\right)=1\)

\(\Rightarrow x\left(\frac{33}{6}+\frac{2}{6}\right)=1\)

\(\Rightarrow x.\frac{35}{6}=1\)

\(\Rightarrow x=\frac{6}{35}\)

2) So sánh

\(\frac{59}{40}< \frac{50}{31}\)( cái này bạn quy đồng là ra, mik chỉ ghi kq, bạn tự tính )

3)\(\frac{1}{3}+\frac{4}{7}-\frac{5}{14}-\frac{1}{2}-\frac{2}{3}\)

\(=\left(\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{4}{7}-\frac{5}{14}\right)-\frac{1}{2}\)

\(=-\frac{1}{3}+\frac{3}{14}-\frac{1}{2}\)

\(=-\frac{13}{21}\)

1)\(\frac{11}{2}.x+\frac{1}{3}.x=1\)

\(x.\left(\frac{11}{2}+\frac{1}{3}=1\right)\)

\(x.\frac{35}{6}=1\)

\(x=1:\frac{35}{6}\)

\(x=\frac{6}{35}\)

2) Ta có:

\(\frac{59}{40}=\frac{1829}{1240}\)

\(\frac{50}{31}=\frac{2000}{1240}\)

Vì \(2000>1829\Rightarrow\frac{2000}{1240}>\frac{1829}{1240}\Rightarrow\frac{50}{31}>\frac{59}{40}\)

3)\(\frac{1}{3}+\frac{4}{7}-\frac{5}{14}-\frac{1}{2}-\frac{2}{3}\)

\(=\left(\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{4}{7}-\frac{5}{14}-\frac{1}{2}\right)\)

\(=-\frac{1}{3}+\left(\frac{8}{14}-\frac{5}{14}-\frac{7}{14}\right)\)

\(=\frac{-1}{3}+\frac{-4}{14}\)

\(=\frac{-1}{3}+\frac{-2}{7}\)

\(=\frac{-7}{21}+\frac{-6}{21}\)

\(=\frac{-13}{21}\)

(2/3×x-1/3)=2/3+1/3

(2/3×x-1/3)=3/3

2/3×x=3/3+1/3

2/3×x=4/3

x=4/3:3/2

x=4/3×2/3

x=8/9

Cảm ơn mn lần nx ạ

= 10/3.x+ 67/4=-53/4

   10/3.x=-53/4-67/4

   10/3.x=-30

   x=-30:10/3

   x=-9

\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)

\(\Leftrightarrow\frac{x+2004}{2000}+\frac{x+2004}{2001}=\frac{x+2004}{2002}+\frac{x+2004}{2003}\)

\(\Leftrightarrow\left(x+2004\right)\left(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}\right)\)

Dễ thấy: \(\left(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}\right)\ne0\Rightarrow x+2004=0\Leftrightarrow x=-2014\)

x = -2014

ti-ck nha

.........

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)\left(x+1\right)=0\)

\(\Rightarrow x+1=0\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0\right)\)

\(x=-1\)

Vậy \(x=-1\)

b) \(\left(2,4.x-36\right)\div1\frac{5}{7}=-1\)

\(\left(2,4.x-36\right)=-1.\frac{12}{7}\)

\(2,4.x-36=-\frac{12}{7}\)

\(2,4.x=-\frac{12}{7}+36\)

\(2,4.x=\frac{240}{7}\)

\(x=\frac{240}{7}\div2,4\)

\(x=\frac{100}{7}\)

a) \(\frac{3}{x-5}=\frac{-4}{x+2}\)

\(\Rightarrow3.\left(x+2\right)=-4.\left(x-5\right)\)

\(\Rightarrow3x+6=-4x+20\)

\(\Rightarrow7x=14\)

\(\Rightarrow x=2\)

Câu c tương tự nhé.