B= 4^6 .9^5+6^9 .120
8^4 .3^12b-6^11
Những câu hỏi liên quan
Tính giá trị các biểu thức sau:
a) A = 2^15 .9^4/6^6 .8^3
b) B = 4^6 .9^5 + 6^9 .120/-8^4 .3^12 - 6^11
c) C = 4^5 .9^4 - 2 .6^9/2^10 .3^8 + 6^8 .20
Cách giải chi tiết.
4^6*9^5+6^9*120/8^4*3^12-6^11
`Answer:`
`(4^6 . 9^5 + 6^9 . 120)/(8^4 . 3^12 - 6^11)`
`= (2^12 . 3^10 + 2^9 . 3^9 . 2^3 . 3 . 5)/(2^12 . 3^12 - 2^11 . 3^11)`
`= (2^12 . 3^10 + 2^12 . 3^10 . 5)/(2^11 . 3^11(2 . 3 - 1))`
`= (2^12 . 3^10 (1 + 5))/(2^11 . 3^11 . 5)`
`= (2 . 6)/(3 . 5)`
`= 4/5`
4^6 . 9^5 + 6^9 .120 / 8^4 . 3^12 - 6^11
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\) đề là như thế này à hay là sao ???
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4^6 . 9^5 +6^9 . 120 / 8^4 . 3^12 - 6^11
10×4^6×9^5+6^9×120
8^4×3^12-6^11
\(\frac{10.4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2.5.\left(2.2\right)^6.\left(3.3\right)^5+\left(2.3\right)^9.3.40}{\left(2.2.2\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2.5.2^6.2^6.3^5.3^5+2^9.3^9.3.40}{2^4.2^4.2^4.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{13}.5.3^{10}+2^{12}.5.3^{10}}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.5.3^{10}.\left(2+1\right)}{2^{11}.3^{11}\left(2.3-1\right)}=\frac{2^{12}.5.3^{11}}{2^{11}.5.3^{11}}=2\)
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4^6 . 4^5 + 6^9 . 120 / 8^4 . 3^12 - 6^11
\(\dfrac { 4^6 . 9^5 + 6^9 . 120 } { 8^4 . 3^{12} - 6^{11}}\)
=(22)6.(32)5+(2.3)9.23.3.5/(23)4.312-(2.3)11
=212.310+29.39.23.3.5/212.312-211.311
=212.310+212.310.5/211.311(2.3-1)
=212.310(1+5)/211.311.5
=2.6/3.5
=4/5
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(4^6 nhân 9^5 +6^9 nhân 120) : (8^4 nhân 3^12 - 6^11)
4^6 .9^5 + 6^9 . 120 phần 8^4 .3^12 -66^11
Mình nghĩ đề đúng là :
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}+2^9.3^9.3.5.2^3}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}\)
\(=\frac{2^{12}.3^{10}.6}{2^{11}.3^{11}.5}\)
\(=\frac{2^{13}.3^{11}}{2^{11}.3^{11}.5}\)
\(=\frac{2^2}{5}\)
\(=\frac{4}{5}\)
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