A = 1/15 + 1/35 + 1/63 + 1/99 +........1/9999

A = 1/3x5 + 1/5x7 + 1/7x9 + .......+ 1/99x101

A = 1/2 x (1/3 - 1/5 + 1/5 - 1/7 + 1/7 - 1/9 +..... + 1/99 - 1/101)

A = 1/2 X ( 1/3 - 1/99)

A = 1/2 x ( 1/3 - 1/101)

A = 1/2 ( 98/303)

A = 49/303

49 / 303

tick cho mk nha

49/303

tick dum di

A = 1/15 + 1/35 + 1/ 63 + 1/99 + ...+ 1/9999

A     = 1/(3x5) + 1/(5x7) + 1/(7x9) + 1/(9x11) + ... + 1/(99 x 101)

Ax2 = 2/(3x5) + 2/(5x7) + 2/(7x9) + 2/(9x11) + ... + 2/(99 x 101)

Ax2 = 1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + 1/9 – 1/11 + ...+ 1/99 – 1/101

Ax2 = 1/3 – 1/101 = 98/303

A    =  98/303 : 2

A    =  49/303

tớ không chắc nhé 

B = 16/15 . 25/24 . ....... . 10000/9999

   = 4.4/3.5 . 5.5/4.6 . ...... . 100.100/99.101

   = 4.5. ..... .100/3.4. .... .99  .  4.5. ..... .100/5.6. ..... .101

   = 100/3 . 4/101

   = 400/303

Tk mk nha

1+1/35 đâu bn

2A=1/2+1/6+1/12+1/20+1/30+1/42

    =1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7

    =1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7

    =1-1/7

    =6/7

\(\Rightarrow A=\frac{1}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}\right)+\frac{1}{5}\)

\(\Rightarrow A=\frac{1}{2}.\left(\frac{1}{5}-101\right)-\frac{1}{5}=\frac{48}{505}-\frac{1}{5}=-\frac{53}{505}\)

1/2 lấy đou ra z bn?

A=1+18+124+148+180+1120A=1+18+124+148+180+1120

=1+12.4+14.6+16.8+18.10+110.12=1+12.4+14.6+16.8+18.10+110.12

=1+12(12−14+14−16+16−18+18−110+110−112)=1+12(12−14+14−16+16−18+18−110+110−112)

=1+12(12−112)=1+12(12−112)

=1+524=1+524

=2924

Tham khảo thôi nka

2A= 2/8+2/24+2/48+2/80= 2/(2*4)+2/(4*6)+2/(6*8)+2/(8*10)= 1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10= 1/2-1/10= 2/5 =>A= 1/5

\(A=\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{48}+\dfrac{1}{80}=\dfrac{1}{2\times4}+\dfrac{1}{4\times6}+\dfrac{1}{6\times8}+\dfrac{1}{8\times10}\)

\(2A=\dfrac{2}{2\times4}+\dfrac{2}{4\times6}+\dfrac{2}{6\times8}+\dfrac{2}{8\times10}\\ 2A=\dfrac{2}{2}-\dfrac{2}{4}+\dfrac{2}{4}-\dfrac{2}{6}+\dfrac{2}{6}-\dfrac{2}{8}+\dfrac{2}{8}-\dfrac{2}{10}\\ 2A=\dfrac{2}{2}-\dfrac{2}{10}=\dfrac{4}{5}\\ A=\dfrac{2}{5}\)