Ta có: \(A=1-2+3-4+5-6+7-8+9\)

\(=(1+9)-(2+8)+(3+7)-(4+6)+5\)

\(=10-10+10-10+5\)

\(=5\)

Vậy  \(A=5\) 

B = 12 - 14 + 16 - 18 + ... + 2008 - 2010

B = -2 + (-2)+ (-2)+ (-2) + ...+ (-2)

B = -2 . 100

B = -200

Bạn muốn kết bạn chứ

(9+1)+(8+2)+(7+3)+(6+4)+10+5

=10+10+10+10+10+5=45

9+3+2+1+7+8+5+10+6+4= (9+1)+(2+8)+(3+7)+(4+6)+5=10+10+10+10+5=10.4+5=40+5=45

(9+1)+(3+7)+(2+8)+(6+4)+10

=10+10+10+10+10

=50

Mình không có ai bài này 

Đây là dạng nâng cao mà

c)

\(\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+....+\left(1-\frac{1}{42}\right)+\left(1-\frac{1}{56}\right)\)

\(\left(1+1+1+....+1+1\right)+\left(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{6\times7}+\frac{1}{7\times8}\right)\)(Có  7 số 1)

\(7+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)

\(7+1-\frac{1}{8}=\frac{63}{8}\)

Gợi ý 1 bài c) còn d) e) cũng làm như vậy nhé

Chúc bạn học tốt !!!

=\(\frac{3}{7}\)

đúng k

khó quá à.

= 195695 

\(M=\frac{1}{2}+\frac{5}{6}+...+\frac{89}{90}=1-\frac{1}{2}+1-\frac{1}{6}+...+1-\frac{1}{90}\)

\(=9-\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{90}\right)\)

\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right)\)

\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=9-\left(1-\frac{1}{10}\right)\)

\(=8+\frac{1}{10}\)

\(=\frac{81}{10}\)

cái này lớp 5 mk  cx làm được,81/10 chắc

hoàng tử bấm máy tính chứ gì?

\(=\frac{8}{10}\)

\(M=\frac{1}{2}+\frac{5}{6}+...+\frac{89}{90}=1-\frac{1}{2}+1-\frac{1}{6}+...+1-\frac{1}{90}\)

\(=9-\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{90}\right)\)

\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right)\)

\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=9-\left(1-\frac{1}{10}\right)\)

\(=8+\frac{1}{10}\)

\(=\frac{81}{10}\)

bt cách lm rùi còn j 

\(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)

\(=\frac{3^2.5^{20}.3^{27}-3.3^{30}.5^{18}}{7.3^{29}.5^{18}-3^{10}.3^{19}.5^{19}}\)

\(=\frac{3^{29}.5^{18}.5^2-3^2.3^{29}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{18}.5}\)

\(=\frac{3^{29}.5^{18}.\left(5^2-3^2\right)}{3^{29}.5^{18}.\left(7-5\right)}\)

\(=\frac{25-9}{2}\)

\(=\frac{16}{2}=8\)

5/6 + 11/12 + 19/20 + ... + 89/90

= 1 - 1/6 + 1 - 1/12 + 1 - 1/20 + ... + 1-1/90

= [1+1+1+1...+1] - [1/2*3 + 1/3*4 + 1/4*5 + ... +1/9*10]

= 8 - [1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + ... + 1/9 - 1/10]

= 8 - [1/2 - 1/10]

= 8 - 2/5

= 38/5

S=1-1/6+1-1/12+...+1-1/90

=8-(1/2.3+1/3.4+...+1/9.10)

=8-(1/2-1/3+1/3-1/4+...+1/9-1/10)

=8-(1/2-1/10)

=8-2/5

=38/5

S=5/6+11/12+19/20+...+89/90

=1-1/6+1-1/12+1-1/20+...+1-1/90

=(1+1+1+...+1)-(1/6+1/12+1/20+...+1/90)

=8-(1/2.3+1/3.4+1/4.5+...+1/9.10)

=8-[(3-2)/2.3+(4-3)/3.4+(5-4)/4.5+...+(10-9)/9.10]

=8-(3/2.3-2/2.3+4/3.4-3/3.4+5/4.5-4/4.5+...+10/9.10-10/9.10]

=8-(1/2-1/3+1/3-1/4+1/4-1/5+...+1/9-1/10)

=8-(1/2-1/10)

=8-2/5

=38/5