a.1*2*3*....*9-1*2*3p...*8-1*2*3*....*8^2
b.1152-(374+1152)+(-65+374)
Bài 1 Tính nhanh
1.2.3...9-1.2.3...8-1.2.3...7.8.8
1152-(374+1152)+(-65+374)
13-12+11+10-9+8-7-6+5-4+3+2-1
tính bằng cách hợp lý (-2017)+(-21+75+2017) ; 1152-(374+1152)+(-65+374) ; 13-12+11+10-9+8-7-6+5-4+3+2-1
tính hợp lí
a,(10^2 +11^2 + 12^2):(13^2+14^2)
b, 1*2*3*.....*9-1*2*3*...*8-1*2*3*...*7*8^2
c, (3*4*2^16)^2 / 11*2^13*4^11-16^9
d,1152-(374+1152)+(-65+374)
b,1×2×3×...×9-1×2×3×...×8-1×2×3×...×7×8^2
=(1×2×3×...×8)×(9-1-8)
=(1×2×3×...×8)×0
=0
tính hợp lí
a) \(1152-\left(374+1152\right)+\left(-65+374\right)\)
b) \(13-12+11+10-9+8-7-6+5-4+3+2-1\)
a) 1152-(374+1152)+(-65+374)
=1152-374-1152-65+374
=(1152-1152)+(-374+374)-65
=-65
a, 1152 - ( 374 + 1152 ) + ( -65 + 374 )
= 1152 - 374 - 1152 - 65 + 374
= ( 1152 - 1152 ) - ( 374 - 374 ) - 65
= 0 - 0 - 65
= -65
b, 13 - 12 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
= ( 13 - 12 ) + 11 + ( 10 - 9 ) + ( 8 - 7 ) - ( 6 - 5 ) - ( 4 - 3 ) + ( 2 - 1 )
= 1 + 11 + 1 + 1 - 1 - 1 + 1
= 13
a) \(=1152-374-1152-65+374\)4
\(=\left(1152-1152\right)+\left(374-374\right)-65\)
\(=-65\)
b) \(=\left(13-12-1\right)+\left(11-7-4\right)+\left(10-9+5-6\right)+\left(8+3+2\right)\)
\(=13\)
Hk tốt
Tính nhanh
a , (3.4.216)2/11.213.411-169
b , 1152-(374+1152)+(-65+374)
c , 13-12+11+10-9+8-7-6+5-4+3+3-1
sao bạn tin nó vậy, nó nói dối ấy
bạn ko thấy à, bạn bảo giải thì nó có giải đâu
Tính hợp lí ( nếu có ) :
a) 1152 - ( 374 + 1152 ) + ( - 65 + 734 )
b) 13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 = 1
Thuc hien cac phep tinh sau một cách hợp lí:
a) (10^2 + 11^2 + 12^2) : (13^2 + 14^2)
b) 1.2.3...9-1.2.3...8-1.2.3...7.8^2
c) (3.4.2^16)^2/11.2^13.4^11-16^9
d) 1152 - (374 + 1152) +(-65 + 374)
e) 13-12+11+10-9+8-7-6+5-4+3+2-1
a.1152 - (374+1152)+(-65+374)
b.13-12+11+10-9+8-7-6+5-4+3+2-1
c. tinh tong S = 1.2 + 2.3 + 3.4 + ..... + 99.100
d. chung minh rang : 1/22+1/32 +1/42 + ..... + 1/1002 < 1
c ) S = 1.2 + 2.3 + 3.4 + .... + 99.100
=> 3S = 1.2.3 + 2.3.3 + 3.4.3 + .... + 99.100.3
=> 3S = 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + .... + 99.100.( 101 - 98 )
=> 3S = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + .... + 99.100.101 - 98.99.100
=> 3S = ( 1.2.3 - 1.2.3 ) + ( 2.3.4 - 2.3.4 ) + .... + ( 98.99.100 - 98.99.100 ) + 99.100.101
=> 3S = 99.100.101 => S = \(\frac{99.100.101}{3}\)
d ) Ta có \(\frac{1}{2^2}<\frac{1}{2.1}=\frac{1}{1}-\frac{1}{2}\)
\(\frac{1}{3^2}<\frac{1}{2.3}=\frac{1}{2}-\frac{1}{3}\)
..........
\(\frac{1}{100^2}<\frac{1}{99.100}=\frac{1}{99}-\frac{1}{100}\)
Vậy \(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+....+\frac{1}{100^2}<\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{99}-\frac{1}{100}\)
\(\Leftrightarrow\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+....+\frac{1}{100^2}<\frac{1}{1}-\frac{1}{100}=\frac{99}{100}<1\)