mình làm 2004.2004+2004+1002/(2004+1)(2004+1)-100... = 2004.2004+2004+1002/ 
2004.2004+2004+2004+1-1003 = 
2004.2004+2004+1002/2004.2004+2004+1002 
=1 

mình làm 2004.2004+2004+1002/(2004+1)(2004+1)-100... = 2004.2004+2004+1002/ 
2004.2004+2004+2004+1-1003 = 
2004.2004+2004+1002/2004.2004+2004+1002 
=1 

Nhầm đề rồi bạn ơi bài này tính nhanh sao được!!

Sửa đề:

\(A=\dfrac{2004.2006+3006}{2005.2005-1003}\)

\(A=\dfrac{2004.2005+2004+3006}{2005.2005-1003}\)

\(A=\dfrac{2004.2005+2004+3006}{2004.2005+2005-1003}\)

\(A=\dfrac{2004.2005+5010}{2004.2005+1002}\)

Ta có (2004.2004+3006)/(2005.2005-1003)=(2004.2004+2004+1002)/(2004+1).(2004+1)-1003=(2004.2004+2004+1002)/(2004.2004+2004+2004+1-1003)=(2004.2004+1002)/(2004.2004+1002)=1

Cảm ơn bạn nha!

a)2x3x4x5x7x8x25x125=21000000

b)=\(\frac{1335}{1337}\)

c)=0

a)=21000000

b)=1

c)=0

Tíck cho mik nha

\(A=\dfrac{1995.1994-1}{1993.1995+1994}=\dfrac{1995\left(1993+1\right)-1}{1993.1995+1994}=\dfrac{1995.1993+1995-1}{1993.1995+1994}=\dfrac{1995.1993+1994}{1995.1993-1994}=1\)\(B=\dfrac{2004.2004+3006}{2005.2005-1003}=\dfrac{2004.2004+2004.1+1002}{2005.2005-1003}=\dfrac{2004.2005+1002}{2005.2005-1003}=\dfrac{2004.2005+1002}{2004.2005+2005-1003}=\dfrac{2004.2005+1002}{2004.2005+1002}=1\)\(C=\dfrac{2010.2011-1}{2009.2011+2010}=\dfrac{2009.2011+2011-1}{2009.2011+2010}=\dfrac{2019.2011+2010}{2009.20011+2010}=1\)\(D=\dfrac{2014.2015-1}{2013.2015+2013}=\dfrac{2013.2015+2014-1}{2013.2015+2013}=\dfrac{2013.2015+2013}{2013.2015+2013}=1\)

Câu 1 nhầm đề nha bạn mình sửa:

\(\dfrac{1995.1994-1}{1993.1995+1994}\)

\(=\dfrac{1995.\left(1993+1\right)-1}{1993.1995+1994}\)

\(=\dfrac{1995.1993+1995-1}{1993.1995+1994}\)

\(=\dfrac{1993.1995+1994}{1993.1995+1994}\)

\(=1\)

Câu 2: \(\dfrac{2004.2004+3006}{2005.2005-1003}\)

\(=\dfrac{2004.2004+2004+1002}{\left(2004+1\right).\left(2004+1\right)-1003}\)

\(=\dfrac{2004.2004+2004+1002}{2004.2004+2004+1-1003}\)

\(=\dfrac{2004.2004+2004+1002}{2004.2004+2004+1002}\)

\(=1\)

Câu 3:\(\dfrac{2010.2011-1}{2009.2011+2010}\)

\(=\dfrac{\left(2009+1\right).2011-1}{2009.2011+2010}\)

\(=\dfrac{2009.2011+2011-1}{2009.2011+2010}\)

\(=\dfrac{2009.2011+2010}{2009.2011+2010}\)

= 1

Câu 4:Nhầm để, sửa:

\(\dfrac{2014.2015-1}{2013.2015+2014}\)

\(=\dfrac{\left(2013+1\right).2015-1}{2013.2015+2014}\)

\(=\dfrac{2013.2015+2015-1}{2013.2015+2014}\)

\(=\dfrac{2013.2015+2014}{2013.2015+2014}\)

\(=1\)

\(\frac{2004\times2004+3006}{2005\times2005-1003}=\frac{2004\times2004+3006}{\left(2004+1\right)\times\left(2004+1\right)-1003}\)

\(\frac{2004\times2004+3006}{2004\times\left(2004+1\right)+1\times\left(2004+1\right)-1003}=\frac{2004\times2004+3006}{2004\times2004+2\times2004+1-1003}\)

\(=\frac{2004\times2004+3006}{2004\times2004+3006}=1\)