\(-2\left(2x-8\right)+3\left(4-2x\right)=-72-5\left(3x-7\right)\)

\(\Leftrightarrow-4x-16+12-6x=-72-15x+35\)

\(\Leftrightarrow-10x-4=-37-15x\)

\(\Leftrightarrow-10x+15x=-37+4\)

\(\Leftrightarrow5x=-33\)

\(\Leftrightarrow x=\frac{-33}{5}\)

                                                                    Bài giải

a, \(-2\left(2x-8\right)+3\left(4-2x\right)=-72-5\left(3x-7\right)\)

\(-4x+8+12-6x=-72-15x+7\)

\(-10x+20=-65-15x\)

\(-10x+15x=-65-20\)

\(5x=-85\)

\(x=-85\text{ : }5\)

\(x=-17\)

b, \(3\left|2x^2-7\right|=33\)

\(\left|2x^2-7\right|=33\text{ : }3\)

\(\left|2x^2-7\right|=11\)

\(\Rightarrow\orbr{\begin{cases}2x^2-7=-11\\2x^2-7=11\end{cases}}\Rightarrow\orbr{\begin{cases}2x^2=-4\text{ ( loại ) }\\2x^2=18\end{cases}}\Rightarrow\text{ }x^2=9\text{ }\Rightarrow\text{ }x=\pm3\)

\(\Rightarrow\text{ }x=\pm3\)

cho mk cách lm nha

dễ mà

a) -2(2x - 8) + 3(4 - 2x) = -72  - 5(3x - 7)

=> -4x + 18 + 12 - 6x = -72 - 15x + 35

=> -10x + 15x = -37 - 30

=> 5x = -37

=> x = -7,4

b) 3|2x² - 7| = 33

=> |2x² - 7| = 11

=> \(\orbr{\begin{cases}2x^2-7=11\\2x^2-7=-11\end{cases}}\)

=> \(\orbr{\begin{cases}2x^2=18\\2x^2=-4\left(loại\right)\end{cases}}\)

=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)

tự làm nha !!!

chúc bạn học tốt

b)

\(3\left(2x^2-7\right)=33\)

\(\Leftrightarrow2x^2-7=11\)

\(\Leftrightarrow2x^2=18\)

\(\Leftrightarrow x^2=9\)

\(\Leftrightarrow x=\pm3\)

a) -2(2x - 8) + 3(4 - 2x) = -72 - 5(3x - 7)

=> -4x + 16 + 12 - 6x = -72 - 15x + 35

=> -10x + 28 = -37 - 15x

=> -10x + 15x = -37 - 28

=> 5x = -65

=> x = -65 : 5

=> x = -13

b) 3(2x² - 7) = 33

=> 2x² - 7 = 33 : 3

=> 2x² - 7 = 11

=> 2x² = 11 + 7

=> 2x² = 18

=> x² = 18 : 2

=> x² = 9

=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)

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