y + \(\frac{11}{12}\)= 17,6 + \(\frac{19}{60}\)
y+11/12=17,6+19/60
y+11/12=215/12
y=215/12-11/12
y=17
Tính nhanh:
\(\frac{10-\frac{1}{10}-\frac{2}{11}-\frac{3}{12}-...-\frac{10}{19}}{\frac{1}{60}+\frac{1}{66}+\frac{1}{72}+...+\frac{1}{114}}\)
$\frac{12}{19}\times \frac{19}{18}+\frac{11}{15}\div \frac{11}{5}=$
`12/19xx19/18+11/15:11/5`
`=2/3+11/15xx5/11`
`=2/3+1/3`
`=3/3`
`=1`
\(E = \frac{7}{19}. \frac{8}{11} + \frac{7}{19}. \frac{3}{11} + \frac{12}{19}\)
E = 7/19 . 8/11 + 7/19 . 3/11 +12/19
= 7/19 . ( 8/11 + 3/11 ) + 12/19
= 7/19 . 11/11 + 12/19
= 7/19 . 1 + 12/19
= 7/19 + 12/19
= 7 + 12 / 19
= 19/19
= 1
A=\(\frac{7}{19}x\frac{8}{11}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{7}{19}.\frac{8}{11}.\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\left(\frac{7}{19}\right)^2.\frac{8}{11}.\frac{11}{3}+\frac{12}{19}\)
\(\Rightarrow A=\left(\frac{7}{19}\right)^2.\frac{8}{3}+\frac{12}{19}\)
\(\Rightarrow A=\frac{392}{1083}+\frac{12}{19}\)
\(\Rightarrow A=\frac{1076}{1083}\)
Ta có 27^5=3^3^5=3^15
243^3=3^5^3=3^15
Vậy A=B
2^300=2^(3.100)=2^3^100=8^100
3^200=3^(2.100)=3^2^100=9^100
Vậy A<B
A=\(\frac{7}{19}x\frac{8}{11}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{56}{209}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{3971}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{1083}+\frac{12}{19}\)
\(A=\frac{1076}{1083}\)
thực hiện phép tính
\(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
\(=\frac{7}{19}.\left(\frac{8}{11}+\frac{3}{11}\right)+\frac{12}{19}\)
\(=\frac{7}{19}.1+\frac{12}{19}\)
\(=1\)
\(\frac{7}{19}\).\(\frac{8}{11}\)+\(\frac{7}{19}\).\(\frac{3}{11}\)+\(\frac{12}{19}\)
=\(\frac{7}{19}\).1+\(\frac{12}{19}\)
=1
hok tốt
Rút gọn
1.\(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
2.\(\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{9}-\frac{4}{11}}\)
\(1\)) \(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)
\(=\frac{7}{19}\left(\frac{8}{11}+\frac{3}{11}\right)+\frac{12}{19}\)
\(=\frac{7}{19}+\frac{12}{19}\)
\(=1\)
\(2\)) \(\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{9}-\frac{4}{11}}\)
\(=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{2\left(\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}\right)}\)
\(=\frac{1}{2}\)
1. \(\frac{7}{19}\times\frac{8}{11}+\frac{7}{19}\times\frac{3}{11}+\frac{12}{19}\)
\(=\frac{7}{19}\left(\frac{8}{11}+\frac{3}{11}\right)+\frac{12}{19}\)
\(=\frac{7}{19}\times1+\frac{12}{19}=\frac{19}{19}=1\)
2. \(\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{9}-\frac{4}{11}}\)
\(=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}}{2\left(\frac{2}{5}+\frac{2}{7}-\frac{2}{9}-\frac{2}{11}\right)}=\frac{1}{2}\)
B=\(\frac{5}{7}.\frac{14}{11}-\frac{5}{7}.\frac{5}{11}-\frac{5}{11}.\frac{2}{7}\)
C=\(1+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+\frac{2}{42}\)
D=\(\frac{0,75-0,6+\frac{3}{19}+\frac{3}{19}}{2,75-2,2+\frac{11}{19}+\frac{11}{91}}\)