Bo dau ngoac roi rut gon bieu thuc :
A= a .( 5-b) + b . ( a- 5) - (5a + 3b )
B = ( x-1 ) . (x-2) - ( x2 + x + 8 )
Bo dau ngoac roi rut gon bieu thuc :
a) - ( - 12 + 25 - 36 ) - ( 12 - 36 + 57 )
b) - ( 23 + 5 - 6 + 17 ) + ( 23 - 5 - 83 - 6 )
c) 12 . ( 6 - 7 - 8 ) - 10 . ( 11 + 12 - 13 )
Giup minh voi minh dang can rat gap
a. = 12 - 25 + 36 - 12 + 36 - 57
= (12 - 12) + (36 + 36) - (25 + 57)
= 0 + 72 - 82
= -10
b. = -23 - 5 + 6 - 17 + 23 - 5 - 83 - 6
= (-23 + 23) + (-5 - 5) + (6 - 6) - (17 + 83)
= 0 + (-10) + 0 - 100
= -110
c.?
bo dau ngoac roi thu gon bieu thuc
a( b-c ) - c(b-d) +a(c+d) +bc
Ta có:
a(b-c)-c(b-d)+a(c+d)+bc
=ab-ac-bc+cd+ac+ad+bc
=ab+cd+ad
Hok tốt !!!
a( b-c ) - c(b-d) + a(c+d) +bc
= ab -ac - bc + cd + ac + ad + bc
=ab + cd + ad
Bo dau ngoac roi rut gon bieu thuc :
a) - ( -a + c - d ) - ( c- a + d )
b) - ( a + b - c + d ) + ( a - b - c - d )
c) a( b- c -d ) - a( b + c - d )
Giup minh nhe minh dang can gap
a)= a-c+d-c+a-d
=2a-2c=2(a-c)
b)=-a-b+c-d+a-b-c-d
=-2b-2d
=2.(-b)-2d=2(-b-d)
c)=ab-ac-ad-ab-ac+ad
=-2.ac
Gấp đến mức độ nào vậy . Bài này đơn giản mà
cho bieu thuc A = /x-1/ + 3x-7
a. rut gon bieu thuc
b. tinh A khi x=3;x=-5
Bo dau ngoac va thu gon bieu thuc:
a) (a+b)(2a+b)
b) (2a-b)(a-b)
c) (2a+b)(2a-b)
cho bieu thuc:
A=(6-2/3+1/2)-(5+5/3-3/2)-(3-7/3+5/2)
hay tinh gia tri cua A theo hai cach
cach 1:truoc het tinh gia tri tung bieu thuc trong ngoac
cach 2:bo dau ngoac roi nhom cac so hang thich hop
C1: \(A=\left(\frac{36}{6}-\frac{4}{6}+\frac{3}{6}\right)-\left(\frac{150}{30}+\frac{50}{30}-\frac{45}{30}\right)-\left(\frac{18}{6}-\frac{14}{6}+\frac{15}{6}\right)\)
\(=\frac{35}{6}-\frac{155}{30}-\frac{19}{6}=\frac{35}{6}-\frac{31}{6}-\frac{19}{6}=-\frac{15}{6}=-2\frac{1}{2}\)
C2: \(6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)
\(=\left(6-5-3\right)-\left(\frac{2}{3}+\frac{5}{3}-\frac{7}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2-0-\frac{1}{2}=-2\frac{1}{2}\)
Bo ngoac roi rut gon:-a-(b-a-c)
((12.8)^3*5)/2^9.15^2
rut gon bieu thuc
dau ngoac de toi ngan cach
B1: rut gon bieu thuc
a, (x+y)^2-4(x-y)^2
b, 2(x-y)(x+y)+(x+y)^2+(x-y)^2
B2: tim X
a, (2X-1)^2-4(X+2)^2=9
b, 3(X-1)^2-3X(X-5)=21
B3: Cho bieu thuc
M=(x+3)^3-(x-1)^3+12x(x-1)
a, Rut gon bieu thuc tren
b, Tinh gia tri M tai x=-2/3
c, Tim x de M=16
1)a)=>x2+y2+2xy-4(x2-y2-2xy)
=>x2+y2+2xy-4.x2+4y2+8xy
=>-3.x2+5y2+10xy