2*3^x=10*3^12+8*27^4
tim x : 2 . 3^x= 10 . 3^12+8 . 27^4
2.3x=10.312+8.274
2.3x=10.312+8.312
2.3x=312(10+8)
2.3x=312.18
3x=312.18:2
3x=312.9
3x=312.32
3x=314
=>x=14
2 x 3 mũ x = 10 x 3 mũ 12 + 8 x 27 mũ 4
Tìm x biết:
a) ( 19x + 2 . 5^2 ) : 14 = ( 13 - 8 )^2 - 4^2
b)2 . 3^x = 10 . 3^12 + 8 . 27^4
a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot25\right)\div14=5^2-16\)
\(\left(19x+50\right)\div14=25-16=9\)
\(19x+50=9\cdot14=126\)
\(19x=126-50=76\)
\(x=76\div19=4\)
b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)
\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)
\(2\cdot3^x=18\cdot3^{12}\)
\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)
a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15
bài 1: tìm số nguyên x, biết
a) \(\left(25-2x\right)^3\): 5 - \(3^2\)= \(4^2\) b) 2 x \(3^x\)= \(10\) x \(3^{12}\) + 8 x \(27^4\)
Lời giải:
a.
$(25-2x)^3:5-3^2=4^2$
$(25-2x)^3:5=4^2+3^2=25$
$(25-2x)^3=25.5=5^3$
$\Rightarrow 25-2x=5$
$\Rightarrow 2x=20$
$\Rightarrow x=10$
b.
$2.3^x=10.3^{12}+8.27^4=10.3^{12}+8.3^{12}=18.3^{12}=2.3^{14}$
$\Rightarrow 3^x=3^{14}$
$\Rightarrow x=14$
Tính:
a) 2^5 x 13^12 x 7^8 : 27 x 13^10 x 7^9
b) 2^n x 11 x 3 : 6^n x 3
c) 5^5 x 7 x 9^5 : 15^10
d) 7 x 8^10 x 27^9 - 8 x 9^13 x 2^27 : 7 x 6^26 x 2^2 - 2^4 x 8^3 x 27^9
e) 2^2^1^2015
f) 2015^0^2015^0^2015
Tìm x ,bt ;
a/ (19 . x + 2 . 5^2 ) : 14 = (13 -8 )^2 - 4^2
b/2 .3^x = 10 . 3^12 + 8 . 27^4
\(x\in\left(\infty;-\infty\right)\)
\(\frac{19x+50}{14}=\frac{9}{1}\Rightarrow\left(19x+50\right)1=14.9\)
\(\frac{\left(19x+50\right)1}{19x}=\frac{14.9}{19x}\)
\(\frac{19x+50}{19x}=\frac{14.19}{19x}\)
\(\Rightarrow x=4\)
a, \(\left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\left(19.x+2.25\right)\div14=5^2-4^2\)
\(\left(19.x+2.25\right)\div14=25-16\)
\(\left(19.x+50\right)\div14=9\)
\(\left(19.x+50\right)=9.14\)
\(19.x+50=126\)
\(19.x=126-50\)
\(19.x=76\)
\(\Rightarrow x=76\div19\)
\(\Rightarrow x=4\)
Vậy x = 4
b, \(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)
\(2.3^x=10.3^{12}+8.3^{12}\)
\(2.3^x=\left(10+8\right).3^{12}\)
\(2.3^x=18.3^{12}\)
\(2.3^x=2.3^3.3^{12}\)
\(2.3^x=2.3^{15}\)
\(\Rightarrow x=15\)
Vậy x = 15
ngu...~_~ bài ny mà cx nỏ bt làm : a ) x=4 b ) x=14
Tìm x ,bt ;
a/ (19 . x + 2 . 5^2 ) : 14 = (13 -8 )^2 - 4^2
b/2 .3^x = 10 . 3^12 + 8 . 27^4
a) \(\left(19\cdot x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19\cdot x+50\right):14=9\)
\(19\cdot x+50=9\cdot14\)
\(19\cdot x+50=126\)
\(19\cdot x=126-50\)
\(19\cdot x=76\)
\(x=76:19\)
\(x=4\)
Vậy \(x=4\)
a)
\(\text{( 25 – 2x )³ : 5 – 3^2 = 4^2}\)
\(\text{( 25 – 2x )³ : 5 – 9 = 16}\)
\(\text{( 25 – 2x )³ : 5 = 16 + 9}\)
\(\text{( 25 – 2x )³ : 5 = 25}\)
\(\text{( 25 – 2x )³ = 25 . 5}\)
\(\text{( 25 – 2x )³ = 125}\)
\(\text{( 25 – 2x )³ = 5³}\)
\(\text{25 – 2x = 5}\)
\(\text{2x = 25 – 5}\)
\(\text{2x = 20}\)
\(\text{x = 10}\)
\(\text{________________________________________}\)
b)
\(\text{2.3^x = 10.3^12 + 8.27^4}\)
\(\text{2.3^x = 10.3^12 + 8.(3^3)^4}\)
\(\text{2.3^x = 3^12 . (10+8)}\)
\(\text{2.3^x = 3^12 . 18}\)
\(\text{3^x = 3^12 . 18:2}\)
\(\text{3^x = 3^12 . 9}\)
\(\text{3^x = 3^12 . 3^2}\)
\(\text{3^x = 3^14}\)
\(\text{=> x=14}\)
27 : 3 + ( 8 x 4 - 2,3 x 10 ) + ( 15 x 3 - 12 x 3 )
6,2 x 2 + 6,2 x 3 + 6,2 x 4 - 11,5 - 17,7 - 23,9