Ta có: x + 5 < 7 ⇔ x < 7 – 5 ⇔ x < 2

Vậy tập nghiệm của bất phương trình là: {x|x < 2}

\(a,2-x=17-\left(-5\right)\)

\(\Rightarrow2-x=17+5\)

\(\Rightarrow2-x=22\)

\(\Rightarrow x=2-22\)

\(\Rightarrow x=-20\)

Vay...

\(b,11-\left(15+11\right)=x-\left(25-9\right)\)

\(\Rightarrow11-26=x-16\)

\(\Rightarrow-15=x-16\)

\(\Rightarrow-15+16=x\)

\(\Rightarrow x=1\)

\(c,9-25=\left(7-x\right)-\left(25+7\right)\)

\(\Rightarrow-16=7-x-32\)

\(\Rightarrow-16=-x-25\)

\(\Rightarrow x=-25+16\)

\(\Rightarrow x=-9\)

Vay \(x=-9\)

em ko biết

Có bị lạc đề ko dzậy?!

Phần e, 17-{-x-[-x-(-x)]}=-16 nha mn, chỗ này thiếu:))

x-(17-8) = 5+(10-3x)

x-9=5+10-3x

x+3x=5+10+9

x+3x=24

4x=24

x=24/4

x=6

vậy x=6

1,-12 + x = 5x - 20

-12 + 20 = 5x - x

8 = 4x

x = 2

2, 7x - 4 = 20 + 3x

7x - 3x = 20 + 4

4x = 24

x  = 6

3 , 5x - 7 = -21 - 2x

5x + 2x  = -21 + 7

7x = -14

x = -14 : 7 = -2

4 , x + 15  = 20 - 4x

x + 4x = 20 - 15

5x = 5

x = 5 : 5 = 1

5, 17 - x = 7 - 6x

-x + 6x = 7 - 17

5x = -10

x = -10 : 5 = -2

\(x=\dfrac{7}{25}+\dfrac{-1}{5}=\dfrac{7}{25}-\dfrac{1}{5}=\dfrac{2}{25}.\\ x=\dfrac{5}{11}+\dfrac{4}{-9}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{1}{99}.\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\Leftrightarrow\dfrac{5}{9}+x=-\dfrac{1}{3}.\Leftrightarrow x=-\dfrac{8}{9}.\)

\(x=\dfrac{7}{25}+-\dfrac{1}{5}=>\dfrac{7}{25}+-\dfrac{5}{25}=>x=\dfrac{2}{25}\)

\(x=\dfrac{5}{11}+\dfrac{4}{-9}=>\dfrac{-45}{-99}+\dfrac{44}{-99}=>x=\dfrac{-1}{-99}=\dfrac{1}{99}\)

\(\dfrac{5}{9}-\dfrac{x}{-1}=-\dfrac{1}{3}=>-\dfrac{1}{3}-\dfrac{5}{9}=>\dfrac{x}{-1}=-\dfrac{8}{9}=>x=-\dfrac{8}{9}\)

\(x=\dfrac{7}{25}+\dfrac{-1}{5}\\ \Rightarrow x=\dfrac{7}{25}+\dfrac{-5}{25}\\ \Rightarrow x=\dfrac{2}{25}\\ x=\dfrac{5}{11}+\dfrac{4}{-9}\\ \Rightarrow x=\dfrac{-45}{-99}+\dfrac{44}{-99}\\ \Rightarrow x=\dfrac{45}{99}+\dfrac{44}{99}\\ \Rightarrow x=\dfrac{95}{99}\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{5}{9}-\dfrac{-1}{3}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{5}{9}-\dfrac{-3}{9}\\ \Rightarrow\dfrac{x}{-1}=\dfrac{8}{9}\Rightarrow x\cdot9=-1\cdot8=-8\\ \Rightarrow x\cdot9=-8\\ \Rightarrow x=\dfrac{-8}{9}\)

3 + (-2) +x =5

      (-2) +x = 5-3

      (-2) +x =2

              x =2 - (-2)

              x= 4

 Vậy x = 4

tk nhé

3+(-2)+x=5

1+x=5

x=5-1

x=4

k nha

hi

a) \(2x+5=\left(-10\right)-x\)

\(2x+x=-10-5\)

\(3x=-15\)

\(x=-15\div3\)

\(x=-5\)

\(5^2+125x=0\)

\(25+125x=0\)

\(125x=0-25\)

\(125x=-25\)

\(x=-25\div125\)

\(x=-\frac{1}{5}\)

\(7x^2-21x+5=5\)

\(7x^2-21x=5-5\)

\(7x^2-21x=0\)

\(7\left(x^2-3x\right)=0\)

\(7\left(x-3\right).x=0\)

\(\hept{\begin{cases}x-3=0\\x=0\end{cases}\Rightarrow\hept{\begin{cases}x=3\\x=0\end{cases}}}\)

Vậy \(x\in\left\{3;0\right\}\)