\(\frac{42}{25}\div\frac{x}{5}=\frac{6}{5}\)

\(\frac{x}{5}=\frac{42}{25}\div\frac{6}{5}\)

\(\frac{x}{5}=\frac{42}{25}\times\frac{5}{6}\)

\(\frac{x}{5}=\frac{7}{5}\)

\(x=7\)

\(\frac{42}{25}:\frac{x}{5}=\frac{6}{5}\) 

\(\frac{x}{5}=\frac{42}{25}:\frac{6}{5}\) 

\(\frac{x}{5}=\frac{42}{25}.\frac{5}{6}\) 

\(\frac{x}{5}=\frac{7}{5}\) 

\(\Rightarrow x=7\) 

Vậy \(x=7\)

\(\frac{42}{25}:\frac{x}{5}=\frac{6}{5}\)

\(\frac{x}{5}=\frac{42}{25}:\frac{6}{5}\)

\(\frac{x}{5}=\frac{42}{25}.\frac{5}{6}\)

\(\frac{x}{5}=\frac{7}{5}\)

\(\Rightarrow x:5=\frac{7}{5}\)

\(\Rightarrow x=\frac{7}{5}.5\)

\(\Rightarrow x=7\)

a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)

                \(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{14}\)

                \(\frac{3}{x-1}=\frac{3}{7}\)

\(\Rightarrow x-1=7\)

              \(x=7+1\)

       Vậy \(x=8\)

b.\(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)

           \(\frac{2x+1}{5}=\frac{42}{25}:\frac{6}{5}\)

           \(\frac{2x+1}{5}=\frac{7}{5}\)

\(\Rightarrow2x+1=7\)

             \(2x=7-1\)

             \(2x=6\)

               \(x=6:2\)

\(x=3\)

a.\(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)

             \(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{14}=\frac{3}{7}\)

           \(\Rightarrow x-1=7\)

                \(x=7+1=8\)

      VẬY, \(x=8\)

b. \(\frac{42}{25}:\frac{2x+1}{5}=\frac{6}{5}\)

            \(\frac{2x+1}{5}=\frac{42}{25}:\frac{6}{5}=\frac{7}{5}\)

          \(\Rightarrow2x+1=7\)

                        \(2x=7-1=6\)

                          \(x=6:2=3\)

            VẬY, \(x=3\)

a ) \(\frac{11}{14}-\frac{3}{x-1}=\frac{5}{14}\)

\(\frac{3}{x-1}=\frac{11}{14}-\frac{5}{4}\)

\(\frac{3}{x-1}=\frac{6}{14}=\frac{3}{7}\)

\(=>x-1=7=>x=7+1=8\)

b ) \(\frac{42}{25}\div\frac{2x+1}{5}=\frac{6}{5}\)

\(\frac{2x+1}{5}=\frac{42}{25}\div\frac{6}{5}\)

\(\frac{2x+1}{5}=\frac{210}{150}=\frac{7}{5}\)

\(2x=7-1=6=>x=6\div2=3\)

a) 42 x 5 : 6 - 12 = 23

b) 25- 40 x 3 : 8 = 10

a) x = 23

b) x =10

a=23

b=10

\(\left(x+50\%\right):\frac{7}{8}=\frac{5}{7}\)

\(\Rightarrow\left(x+\frac{1}{2}\right)=\frac{5}{7}.\frac{7}{8}\)

\(\Rightarrow x+\frac{1}{2}=\frac{5}{8}\)

\(\Rightarrow x=\frac{5}{8}-\frac{1}{2}\)

\(\Rightarrow x=\frac{1}{8}\)
Vậy...

Mình làm tiếp bài của bạn " I have a crazy idea "

b) \(\frac{25-x}{3}=\frac{15}{2}\)

Áp dụng tỉ lệ thức:

\(\left(25-x\right).2=15.3\)

\(\Rightarrow25-x=\frac{15.3}{2}=\frac{45}{2}\Leftrightarrow x=25-\frac{45}{2}=\frac{5}{2}\)

c) \(x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-\frac{1}{20}-\frac{1}{30}-\frac{1}{42}=1\)

\(\Rightarrow x-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)=1\)

\(\Rightarrow x-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)=1\)

\(\Rightarrow x-\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{6}-\frac{1}{7}\right)=1\)

\(\Rightarrow x-\left(\frac{1}{1}-\frac{1}{7}\right)=1\Leftrightarrow x-\frac{6}{7}=1\Leftrightarrow x=1+\frac{6}{7}=\frac{13}{7}\)

\(\frac{5}{14}\frac{5}{14}\) LÀ NHÂN À

Mình lỡ đánh nhầm 2 lần \(\frac{5}{14}\)nha :)) chỉ 1 lần thôi

\(\frac{x-199}{6}+\frac{x-199}{12}+\frac{x-199}{20}+\frac{x-199}{30}+\frac{x-199}{42}=\frac{5}{14}\)

\(\left(x-199\right)\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)=\frac{5}{14}\)

\(\left(x-199\right)\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)=\frac{5}{14}\)

\(\left(x-199\right)\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{5}{14}\right)\)

\(\left(x-199\right)\left(\frac{1}{2}-\frac{1}{7}\right)=\frac{5}{14}\)

\(\left(x-199\right).\frac{5}{14}=\frac{5}{14}\)

\(\Leftrightarrow x-199=1\)

\(\Leftrightarrow x=200\)

\(\Leftrightarrow\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\times\frac{x}{3}=\frac{5}{21}\)

\(\Leftrightarrow\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\times\frac{x}{3}=\frac{5}{21}\)

\(\Leftrightarrow\left(\frac{1}{2}-\frac{1}{7}\right)\times\frac{x}{3}=\frac{5}{21}\)

\(\Leftrightarrow\frac{5}{14}\times\frac{x}{3}=\frac{5}{21}\)

\(\Leftrightarrow\frac{x}{3}=\frac{2}{3}\)

\(\Leftrightarrow x=2\)

\(\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right).\frac{x}{3}=\frac{5}{21}\)

\(\Rightarrow\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right).\frac{x}{3}=\frac{5}{21}\)

\(\Rightarrow\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}\right).\frac{x}{3}=\frac{5}{21}\)

\(\Rightarrow\left(\frac{1}{2}-\frac{1}{7}\right).\frac{x}{3}=\frac{5}{21}\)

\(\Rightarrow\left(\frac{7}{14}-\frac{2}{14}\right).\frac{x}{3}=\frac{5}{21}\)

\(\Rightarrow\frac{5}{14}.\frac{x}{3}=\frac{5}{21}\)

\(\Rightarrow\frac{x}{3}=\frac{5}{21}:\frac{5}{14}\)

\(\Rightarrow\frac{x}{3}=\frac{2}{3}\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

Đặt \(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)

\(\Rightarrow A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\)

\(\Rightarrow A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}\)

\(\Rightarrow A=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)

\(\Leftrightarrow\frac{5}{14}.\frac{4}{3}x=\frac{5}{14}\)

\(\Rightarrow\frac{4}{3}.x=\frac{5}{21}:\frac{5}{14}\)

\(\Rightarrow x=2\)

a, x=15

b,x=7

a) \(\frac{24}{x}\div\frac{8}{3}=\frac{3}{5}\)

\(\frac{24}{x}\cdot\frac{3}{8}=\frac{3}{5}\)

\(\frac{24}{x}=\frac{3}{5}\div\frac{3}{8}\)

\(\frac{24}{x}=\frac{24}{15}\)

Vậy x = 15

b) Tương tự

\(\frac{24}{x}:\frac{8}{3}=\frac{3}{5}\)

\(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\)

\(\frac{24}{x}=\frac{8}{5}\)

\(\frac{24}{x}=\frac{24}{15}\)

\(=>x=15\)

vay \(x=15\)

b) \(\frac{42}{25}:\frac{x}{5}=\frac{6}{5}\)

\(\frac{x}{5}=\frac{42}{25}:\frac{6}{5}\)

\(\frac{x}{5}=\frac{42}{25}.\frac{5}{6}\)

\(\frac{x}{5}=\frac{7}{5}\)

\(=>x=7\)

vay \(x=7\)

a, Câu hỏi của Nguyễn Ánh Ngân - Toán lớp 6 - Học toán với OnlineMath

b, Câu hỏi của Vũ Xuân Hiếu - Toán lớp 6 | Học trực tuyến

c)$x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-\frac{1}{20}-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}=\frac{5}{24}$