\(\frac{3x-1}{3x}=\frac{2x-1}{2x+1}\) Tìm x
Tìm x biết :
a) (3x+1)^2=x^2+2x+1
b) Thực hiện phép tính: \(\frac{1-3x}{2x}\)+ (3x-2).\(\left(\frac{1}{2x-1}-\frac{1}{4x^2-2x}\right)\)
em xl vì em ko bít em chỉ mới lớp 5 thôi
Tìm x biết
\(\frac{2x-1}{3x}=\frac{2x+1}{3x+2}\)
\(\frac{2x-1}{3x}=\frac{2x+1}{3x+2}\)
Nhân chéo, ta được:
\(\left(2x-1\right)\left(3x+2\right)=3x\left(2x+1\right)\)
\(6x^2+4x-3x-2=6x^2+3x\)
\(6x^2-6x^2+4x-3x-3x=2\)
\(-2x=2\)
\(x=-1\)
Giải các phương trình sau:
a) \(x+\frac{2x+\frac{x-1}{5}}{3}=1-\frac{3x-\frac{1-2x}{3}}{5}\)
b) \(\frac{3x-1-\frac{x-1}{2}}{3}-\frac{2x+\frac{1-2x}{3}}{2}=\frac{\frac{3x-1}{2}}{5}\)
khó quá mk mới học lớp 6 nên k giải đc thông cảm cho mk nha
Bài 2: Giải phương trình:
a) \(x+\frac{2x+\frac{x-1}{5}}{3}=1-\frac{3x-\frac{1-2x}{3}}{5}\)
b) \(\frac{3x-1-\frac{x-1}{2}}{3}-\frac{2x+\frac{1-2x}{3}}{2}=\frac{\frac{3x-1}{2}-6}{5}\)
Thực hiện phép cộng các phân thức ko cùng mẫu:
a/\(\frac{x^3+2x}{x^3+1}+\frac{2x}{x^2-x+1}+\frac{1}{x+1}\) b/\(\frac{1-3x}{2x}+\frac{3x-2}{2x-1}+\frac{3x-2}{2x-4x^2}\)
Tự trình bày nha
a) MC : x^3 +1
KQ: (x+1)^3 / (x^3 +1)
b) MC: 2x-4x^2
KQ: -1/(2x)
Tìm x :
a) |3x + 1| + |x - 1| = 2x + 1
b) 2x - 2 |3x +1| = 5x +1
c) \(\frac{1}{\left|x+1\right|}=\frac{-2}{x+3}\)
a,\(\frac{3}{x}+\frac{1}{x+3}+\frac{3}{x+6}+\frac{1}{x+7}=\frac{1}{1-x}\)
b, \(\frac{1}{x-5}+\frac{1}{x-2}+\frac{1}{x-1}+\frac{1}{x}+\frac{1}{x+3}=\frac{3x-3}{4}\)
c,\(\frac{1}{x-3}+\frac{1}{3x+1}+\frac{10x-13}{4x-6}=\frac{1}{x+1}+\frac{1}{2x-1}+\frac{1}{3x+7}\)
d,\(\frac{x^2+x+1}{2x-1}\left(\frac{3x^2-x+5}{4x-2}-3\right)=8\)
e,\(\frac{2x^2-3}{3x-1}\left(2x-\frac{7+4x}{3x-1}\right)=2\)
f,\(\frac{x\left(3x-1\right)\left(3x^2+1\right)\left(6x^2-3x-1\right)}{\left(x+1\right)^3}=\frac{1}{2}\)
g, \(x\left(x^2+2\right)\left(x^2+2x+8+\frac{12}{x-2}\right)=3\left(x-2\right)\)
Tìm nguyên hàm sau:
$\displaystyle\int
\left(3x^2 - \frac{4}{x} + \sin3x - \cos4x + e^{2x+1} + 3^{2x-2} + 3\sqrt{x^4} + \frac{1}{\cos^2x} - \frac{1}{\sin^2x}\right) dx$
\(=\int\left(6x^2-\dfrac{4}{x}+sin3x-cos4x+e^{2x+1}+9^{x-1}+\dfrac{1}{cos^2x}-\dfrac{1}{sin^2x}\right)dx\)
\(=2x^3-4ln\left|x\right|-\dfrac{1}{3}cos3x-\dfrac{1}{4}sin4x+\dfrac{1}{2}e^{2x+1}+\dfrac{9^{x-1}}{ln9}+tanx+cotx+C\)
\(\frac{x^2-x}{x^2-x+1}-\frac{x^2-x+2}{x^2-x-2}=1.\)
\(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
\(\frac{1}{x^2-2x+2}+\frac{1}{x^2-2x+3}=\frac{9}{2\left(x^2-2x+4\right)}\)
\(\frac{1}{x^2-2x+3}+\frac{1}{x^2-2x+2}=\frac{6}{x^2-2x+4}\)