5.4-x+2.7=1.05
Những câu hỏi liên quan
5.4 × 2.7 + 7.2 × 1.2 - 1.8 × 2.9
các bạn làm theo biểu thức nhé .Nhớ là tính nhanh
123-5.(x+4)=38
(3.x-2^4).7^3=2.7^4
6^2:4.3+2.5^2
5.4^2-18:3^2
80-(4.5^2-3.2^3)
23.75+25.23+180
2448:[119-(23-6)]
Tim so nhien x biet
(2600+6400)-3.x=1200
[(6.x-72):2-84].28=562
123-5.(x+4)=38
5.(x+4)=123-38
5.(x+4)=85
x+4=85:5
x+4=17
x=17-4
x=13
(3.x-2^4).7^3=2.7^4
(3.x-16).343=2.2401
(3.x-16).343=4802
3.x-16=4802:343
3.x-16=14
3.x=14+16
3.x=30
x=30:3
x=10
6^2:4.3+2.5^2
=36:4.3+2.25
=9.3+2.25
=27+50
=77
5.4^2-18:3^2
=5.16-18:9
=80-2
=78
80-(4.5^2-3.2^3)
=80-(4.25-3.8)
=80-(100-24)
=80-76
=4
23.75+25.23+180
=23.(75+25)+180
=23.100+180
=2300+180
=2480
2448:[119-(23-6)]
=2448:(119-17)
=2448:102
=24
(2600+6400)-3.x=1200
9000-3.x=1200
3.x=9000-1200
3.x=7800
x=7800:3
x=2600
[(6.x-72):2-84].28=562
(6.x-72):2-84=562:28
(6.x-72):2-84=281/14
(6.x-72):2=281/14+84
(6.x-72):2=1457/14
6.x-72=1457/14.2
6.x-72=1457/7
6.x=1457/7+72
6.x=1961/7
x=1961/7:6
x=1961/42
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X x 2.9 + X :10 = 1.05
Tìm x biết x.0,5=1.05-x
X * 3/4 + */5 +1.05 * x =5.8
1.05 : x = 0.02 ( dư 0.01 )
1,05:x=0,02 (dư 0,01)
1,05=0,02.x+0,01
0,02.x=1,05-0,01
0,02.x=1,04
x=1,04:0,02
x=52
Vậy x=52
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Tìm nghiệm nguyên của phương trình (x+y)2(x−1)(y+1)
Đọc tiếp
Tìm nghiệm nguyên của phương trình (x+y)2=(x−1)(y+1)
25 tháng 5 2021 lúc 19:27
tìm x
(2/11*13+2/13*15 + ... 2/19*21)*462 - [0.04/(x+1.05)] /0.12=19
`(2/(11.13)+2/(13.15)+....+2/(19.21)).462-[0,04/(x+1,05):0,12=19`
`=>(1/11-1/13+1/13-1/15+....+1/19-1/21).462-(2/(50(x+1,05)).25/3=19`
`=>(1/11-1/21).462-1/(3(x+1,05))=19`
`=>10/231. 462-1/(3x+3,15)=19`
`=>20-1/(3x+3,15)=19
`=>1/(3x+3,15)=1`
`=>3x+3,15=1`
`=>3x=-2,15`
`=>x=-43/60`
Vậy `x=-43/60`
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Giải:
\(\left(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}\right).462-\left[\dfrac{0,04}{x+1,05}:0,12\right]=19\)
\(\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{\dfrac{25}{x+\dfrac{21}{20}}}:\dfrac{3}{25}\right]=19\)
\(\left(\dfrac{1}{11}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{25.\left(x+\dfrac{21}{20}\right)}:\dfrac{3}{25}\right]=19\)
\(20-\left[\dfrac{25.1}{3.25.\left(x+\dfrac{21}{20}\right)}\right]=19\)
\(\dfrac{1}{3.\left(x+\dfrac{21}{20}\right)}=20-19\)
\(\dfrac{1}{3.x+\dfrac{63}{20}}=1\)
\(1:\left(3.x+\dfrac{63}{20}\right)=1\)
\(3.x+\dfrac{63}{20}=1:1\)
\(3.x+\dfrac{63}{20}=1\)
\(3.x=1-\dfrac{63}{20}\)
\(3.x=\dfrac{-43}{20}\)
\(x=\dfrac{-43}{20}:3\)
\(x=\dfrac{-43}{60}\)
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tìm s
s x 2,9 + s : 10 = 1.05
\(s\cdot2.9+s:10=s\cdot2.9+s\cdot0.1=s\cdot3=1,05\text{ nên }s=0,35\)
