Tìm tất cả các số nguyên n biết :
a, \(\frac{1}{9}=27^n=3^n\)
b, \(2^{-1}\times2^n+4\times2^n=9\times2^5\)
c, \(\left(\frac{4}{9}\right)^n=\left(\frac{3}{2}\right)^{-5}\)
d, \(\left(\frac{0}{0,125}\right)^n=128\)
Những câu hỏi liên quan
Viết các biểu thức sau dưới dạng \(a^n\)(a thuộc Q, n thuộc N)
a) \(9\times3^3\times\frac{1}{81}\times3^2\)
b) \(4\times2^5\div\left(2^3\times\frac{1}{16}\right)\)
c) \(3^2\times2^5\times\left(\frac{2}{3}\right)^2\)
d) \(\left(\frac{1}{3}\right)^2\times\frac{1}{9}\times9^2\)
Bài 1:
a) (-0,25) . 0,45 . 0,4 . (-0,125) . 0,55 . (-8)
b) [ 20,83 . 0,2 + (-9,17 . 0,2) ] : [ 2,47 . 0,5 - (-3,53 . 0,5) ]
c) \(\frac{(9\frac{3}{4}\div5,2+3,4\times2\frac{7}{34})\div(-1\frac{9}{16})}{\left(-0,31\right).8\frac{2}{5}-5,61\div\left(-27\frac{1}{2}\right)}\)
Cho B= \(\frac{1\times2}{1\times2\times3}+\frac{1\times2}{1\times2\times4}+\frac{1\times2}{1\times2\times3\times4}+\frac{1\times2}{1\times2\times3\times4\times5}+....+\frac{1\times2}{n,giao}\left(n\in N,n\ge3\right)\)
chứng tỏ B nhỏ hơn 3
Tìm m,ninZ:
2^{-1}times2^n+4times2^n9times2^5
2^m-2^n1984
dfrac{1}{9}times27^n3^n
left(dfrac{4}{9}right)^nleft(dfrac{3}{2}right)^{-5}
left(dfrac{1}{3}right)^mdfrac{1}{81}
-dfrac{512}{343}left(-dfrac{8}{7}right)^n
Đọc tiếp
Tìm m,n\(\in\)Z:
\(2^{-1}\times2^n+4\times2^n=9\times2^5\)
\(2^m-2^n=1984\)
\(\dfrac{1}{9}\times27^n=3^n\)
\(\left(\dfrac{4}{9}\right)^n=\left(\dfrac{3}{2}\right)^{-5}\)
\(\left(\dfrac{1}{3}\right)^m=\dfrac{1}{81}\)
\(-\dfrac{512}{343}=\left(-\dfrac{8}{7}\right)^n\)
a) \(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\Rightarrow2^n\cdot\left(2^{-1}+4\right)=9\cdot2^5\)
\(\Rightarrow2^n\cdot4,5=288\)
\(\Rightarrow2^n=64\)
\(\Rightarrow n=6\)
b) \(2^m-2^n=1984\)
\(\Rightarrow2^n\cdot\left(2^{m-n}-1\right)=2^6\cdot31\)
\(\Rightarrow\left\{{}\begin{matrix}2^n=2^6\\2^{m-n}-1=31\end{matrix}\right.\)
\(\Rightarrow n=6\)
\(\Rightarrow2^{m-n}=32\Rightarrow m-n=5\Rightarrow m=11\)
Đúng 0
Bình luận (0)
Tính giá trị biểu thức:a. frac{20^5times5^{10}}{100^5}b. frac{left(0,9right)^5}{left(0,3right)^6}c. frac{6^3+3times6^2+3^3}{-13}d. frac{4^6times9^5+6^9times120}{8^4times3^{12}-6^{11}}e. left(2^{-1}+3^{-1}right):left(2^{-1}-3^{-1}right)+left(2^{-1}times2^0right)times2^3f. left(frac{-1}{3}right)^{-1}-left(frac{-3}{5}right)^6+left(frac{1}{2}right)^2:2
Đọc tiếp
Tính giá trị biểu thức:
a. \(\frac{20^5\times5^{10}}{100^5}\)
b. \(\frac{\left(0,9\right)^5}{\left(0,3\right)^6}\)
c. \(\frac{6^3+3\times6^2+3^3}{-13}\)
d. \(\frac{4^6\times9^5+6^9\times120}{8^4\times3^{12}-6^{11}}\)
e. \(\left(2^{-1}+3^{-1}\right):\left(2^{-1}-3^{-1}\right)+\left(2^{-1}\times2^0\right)\times2^3\)
f. \(\left(\frac{-1}{3}\right)^{-1}-\left(\frac{-3}{5}\right)^6+\left(\frac{1}{2}\right)^2:2\)
a. \(\frac{20^5.5^{10}}{100^5}\)
\(=\frac{20^5.\left(5^2\right)^5}{100^5}\)
\(=\frac{20^5.25^5}{100^5}\)
\(=\frac{500^5}{100^5}\)
\(=\left(\frac{500}{100}\right)^5\)
\(=5^5=3125\)
b. \(\frac{\left(0,9\right)^5}{\left(0,3\right)^6}\)
\(=\frac{\left(0,9\right)^5}{\left(0,3\right)^5.0,3}\)
\(=\left(\frac{0,9}{0,3}\right)^5.\frac{1}{0,3}\)
\(=3^5.\frac{1}{0,3}\)
\(=810\)
c. \(\frac{6^3+3.6^2+3^3}{-13}\)
\(=\frac{\left(3.2\right)^3+3.\left(3.2\right)^2+3^3}{-13}\)
\(=\frac{3^3\left(2^3+2^2+1\right)}{-13}\)
\(=\frac{3^3.13}{-13}\)
\(=\left(-3\right)^3\)
\(=-27\)
Đúng 0
Bình luận (0)
bài 1: Tìm x,y biết rằng: x+(-frac{31}{12})^2left(frac{49}{12}right)^2-xy^2 bài 2: tìm x biết:a.5^x.left(5^3right)^2625 b.left(frac{12}{25}right)^xleft(frac{5}{3}right)^{-2}-left(-frac{3}{5}right)^4 c.left(-frac{3}{4}right)^{3x-1}frac{256}{81} d.172x^2-7^9:98^32^{-3}Bài 3: Tìm x varepsilonN biết:a.8 2^xle2^9times2^{-5} b.27 81^3:3^x 243 left(frac{2}{5}right)^xleft(frac{5}{2}right)^{-3}timesleft(-frac{2}{5}right)^2c.
Đọc tiếp
bài 1: Tìm x,y biết rằng:
\(x+(-\frac{31}{12})^2=\left(\frac{49}{12}\right)^2-x=y^2\)
bài 2: tìm x biết:
a.\(5^x.\left(5^3\right)^2=625\) b.\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\) c.\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
d.\(172x^2-7^9:98^3=2^{-3}\)
Bài 3: Tìm x \(\varepsilon\)N biết:
a.\(8< 2^x\le2^9\times2^{-5}\) b.\(27< 81^3:3^x< 243\) \(\left(\frac{2}{5}\right)^x>\left(\frac{5}{2}\right)^{-3}\times\left(-\frac{2}{5}\right)^2\)c.
Bài 1:
Ta có: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x\)
\(\Leftrightarrow2x=\frac{1440}{144}=10\)
\(\Rightarrow x=5\)
Khi đó: \(y^2=\left(\frac{49}{12}\right)^2-5=\frac{1681}{144}\)
=> \(\hept{\begin{cases}y=\frac{41}{12}\\y=-\frac{41}{12}\end{cases}}\)
Tính
a)\(A=\frac{\left(3\times2^{20}+7\times2^{19}\right)\times52}{\left(13\times8^4\right)^2}\)
b)\(B=\frac{2^{19}\times27^3+15\times4^9\times9^4}{6^9\times2^{10}+12^{10}}\)
Tìm x
\(\frac{\left(1,16-x\right)\times5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right)\times2\frac{2}{17}}=\frac{3}{4}\)
Ta co:
\(\left[\left(\frac{29}{25}-x\right).\frac{21}{4}\right]:\left[\left(\frac{95}{9}-\frac{29}{4}\right).\frac{36}{17}\right]=\frac{3}{4}\)
\(\left[\left(\frac{29}{25}-x\right).\frac{21}{4}\right]:\left(\frac{119}{36}.\frac{36}{17}\right)=\frac{3}{4}\)
\(\left[\left(\frac{29}{25}-x\right).\frac{21}{4}\right]:7=\frac{3}{4}\)
\(\left(\frac{29}{25}-x\right).\frac{21}{4}=\frac{3}{4}.7=\frac{21}{4}\)
\(\frac{29}{25}-x=\frac{21}{4}:\frac{21}{4}=1\)
\(x=\frac{29}{25}-1=\frac{4}{25}\)
Đúng 0
Bình luận (0)
giúp mình với
1, tính
a, \(2^5+8\left[\left(-2\right)^3:\frac{1}{2}\right]^0-\left(\frac{1}{2}\right)^3\times2+\left(-2\right)^3\)
b, \(\frac{7}{15}-\frac{9}{19}-\frac{-8}{15}-\frac{10}{19}\)
c, \(1\frac{1}{3}:\frac{4}{5}+2\frac{2}{3}:\frac{4}{5}\)
a) \(2^5+8\left[\left(-2\right)^3:\frac{1}{2}\right]^0-\left(\frac{1}{2}\right)^3\times2+\left(-2\right)^3\)
\(=32+8\times1-\frac{1}{8}\times2+\left(-8\right)\)
\(=32+8-\frac{1}{4}+\left(-8\right)\)
\(=40-\frac{1}{4}+\left(-8\right)\)
\(=39\frac{3}{4}+\left(-8\right)\)
\(=31\frac{3}{4}\)
b vaf c mai minhf lamf, ht