AOB=60 

BOD và AOC = 120 

Ta có \(\widehat{xOM}+\widehat{xON}=40^0+140^0=180^0\) nên M,O,N thẳng hàng

Mà x,O,x' thẳng hàng nên \(\widehat{xON}\) đối đỉnh \(\widehat{x'OM}\)

1 B

2 D

3 D

4 C

5 C

6 D

7 A

8 A

9 D

10 B

11 A

12 A

13 A

14 A

15 A

16 C

17 A

18 A

19 A

20 D

21 D

22 A

23 B

24 B

25 B

26 B

27 D

Gọi giá trị của chữ số sau khi xóa đi số 5 là x (với \(x>0;x\in N\))

Giá trị chữ số ban đầu: \(10x+5\)

Theo bài ra ta có pt:

\(10x+5-x=1796\)

\(\Rightarrow9x=1791\)

\(\Rightarrow x=199\)

Vậy chữ số đó là \(1995\)

gọi số cần tìm là X 

vì hàng đơn vị là 5 và nếu bỏ 5 thì sẽ giảm 1796 đơn vị nên ta có :

10.X+5=X+1796

=> X=199

1 enjoyed

2  Did Marco win

3 did Sarah  buy

4 built

5 spent

6  drives - went

7 waters - didn't water - rained

8 do you go

9  is sleeping

10 weren't - had

#\(HMeisukii\)

#\(yGLinh\)

1 fell

2 found

3 is writing

4 ran

5 wears

1 John is the same height as James

2 This is by far the best restaurant in town

3 My laptop was not as expensive as my new phone

4 The class tomorrow starts a later time than usual

5 This watch is the most expensive I could find

6 This is the first time that I've seen such a nice beach

7 This movie is not as funny as his last one

8 Jill is younger than her sister

Bài nào em hỉ?