Tính B= \(\frac{1}{16}\)+ \(\frac{6}{16.26}\)+\(\frac{6}{26.36}\)+...........+\(\frac{6}{2006.2016}\)
Tính giá trị biểu thức B=\(\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+....+\frac{6}{2006.2016}\)
nhân với 1/6 cả 2 vế rồi nhân cả 2 vế với 10
\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+\frac{6}{36.46}+.....+\frac{6}{2006.2016}\)
ai nhanh giup minh di roi minh cho nick "lien quan mobile" rank vang
B=1/16+ 6/16.26+ 6/26.36+ ..................+ 6/2006.2016
B=1/16+ 6. (1/16.26+ 1/26.36 +.................+ 1/2006.2016)
10B=1/16+6.(1/16- 1/2016)
10B=7.1/16 - 1/336
10B=7/16 - 1/336
10B=73/168
B=73/1680
làm hơi tắt bạn cố hiểu nhé
tớ là "nam tử hán đại trượng phu" nên tớ hứa là tớ làm .Kết bạn với tớ đi,tớ nhắn tin cho
\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+\frac{6}{36.46}+...+\frac{6}{2006.2016}\)Tính giá trị biểu thức
\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+\frac{6}{36.46}+...+\frac{6}{2006.2016}\) =\(B=\frac{1}{16}+\frac{3}{5}\left(\frac{10}{16.26}+\frac{10}{26.36}+\frac{10}{36.46}+...+\frac{10}{2006.2016}\right)\)
\(B=\frac{1}{16}+\frac{3}{5}\left(\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}+\frac{1}{36}-\frac{1}{46}+...+\frac{1}{2006}-\frac{1}{2016}\right)\)
\(B=\frac{1}{16}+\frac{3}{5}\left(\frac{1}{16}-\frac{1}{2016}\right)\)
đến đây thì ổn rồi
Tính a)
\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+\frac{6}{26.46}+.....+\frac{6}{2006.2016}\)
b) Cho x , y , z khác 0 và x - y - z = 0.Tính \(B=\left(1-\frac{z}{x}\right)\left(1-\frac{x}{y}\right)\left(1+\frac{y}{z}\right)\)
x-y-z=0=>x=y+z
=>z=x-y;=>y=x-z
\(=>B=\left(1-\frac{z}{x}\right)\left(1-\frac{x}{y}\right)\left(1-\frac{y}{z}\right)=\left(1-\frac{x-y}{x}\right)\cdot\left(1-\frac{y+z}{y}\right)\cdot\left(1+\frac{x-z}{z}\right)\)
Câu a cậu ghi sai đầu bài rồi hay sao í! phải là \(\frac{6}{36.46}\) chứ
Ta có x-y-z=0 suy ra x=z+y;y=x-z;-z=y-x
B=(1-z/x)(1-x/y)(1+y/z)
B=((x-z)/x)((y-x)/y)((z+y)/z)
B=(y/x)(-z/y)(x/z)
B=(-z.y.x)/(z.y.x)
B=-1
tính B= 1/16 + 6/16.26 + 6/26.36 + 6/36.46 + .....+ 6/2006.2016
\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+....+\frac{6}{2006.2016}\)
\(=\frac{6}{6.16}+\frac{6}{16.26}+\frac{6}{26.36}+....+\frac{6}{2006.2016}\)
\(=\frac{6}{10}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+...+\frac{1}{2006}-\frac{1}{2016}\right)\)
\(=\frac{3}{5}\left(\frac{1}{6}-\frac{1}{2016}\right)\)
\(=\frac{67}{672}\)
\(B=\frac{1}{16}+\frac{6}{16\cdot26}+\frac{6}{26\cdot36}+...+\frac{6}{2006\cdot2016}\)
\(B=\frac{1}{16}+6\left(\frac{1}{16\cdot26}+\frac{1}{26\cdot36}+...+\frac{1}{2006\cdot2016}\right)\)
\(B=\frac{1}{16}+6\left[\frac{1}{10}\left(\frac{10}{16\cdot26}+\frac{10}{26\cdot36}+...+\frac{10}{2006\cdot1016}\right)\right]\)
\(B=\frac{1}{16}+6\left[\frac{1}{10}\left(\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}+...+\frac{1}{2006}-\frac{1}{2016}\right)\right]\)
\(B=\frac{1}{16}+6\left[\frac{1}{10}\left(\frac{1}{16}-\frac{1}{2016}\right)\right]\)
\(B=\frac{1}{16}+6\cdot\left[\frac{1}{10}\cdot\frac{125}{2016}\right]\)
\(B=\frac{1}{16}+6\cdot\frac{26}{4032}\)
\(B=\frac{1}{16}+\frac{25}{672}\)
\(B=\frac{57}{672}\)
Tính giá trị của biểu thức
a. B= \(\frac{1}{16}\)+\(\frac{6}{16.26}\)+\(\frac{6}{26.36}\)+.....+\(\frac{6}{2006}\)
tính \(A=\frac{\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}}{\frac{33}{6.16}-\frac{63}{16.26}+\frac{93}{26.36}}\)
\(\frac{15.\left(\frac{1}{616}.\frac{1}{6.16}.\frac{1}{6.16}\right)}{33.\left(\frac{1}{6.16}.\frac{1}{6.16}.\frac{1}{6.16}\right)}=\frac{15}{35}\)
Tính A=\(\frac{\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}}{\frac{33}{6.16}-\frac{63}{16.26}+\frac{93}{26.36}}\)
\(A=\frac{\frac{3}{2}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}{\frac{33}{10}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}=\frac{\frac{3}{2}}{\frac{33}{10}}=\frac{3}{2}:\frac{33}{10}=\frac{5}{11}\)
Thực hiện phép tính sau :
\(A=\frac{\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}}{\frac{33}{6.16}-\frac{63}{16.26}+\frac{93}{26.36}}\)
kết quả là :
A= \(\frac{39}{926}\)
đs...