P=(7-4)^(7-5)=9

thay x = 7  vào biểu thức, ta đc:

\(P=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}=3^{2^{1^{13^{12}}}}\)

\(=3^{2^1}=9\)

\(\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}=\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}=1^{13^{12}}=1\)

=> P(1) = \(\left(7-4\right)^{\left(7-5\right)^1}=3^2=9\)

= 9 nha cho mèo ú vài k nha các bạn !!!!!

Thay x = 7 vào p, ta đc:

\(p=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{7+5}}}}\)

     \(=3^{2^{1^{13^{12}}}}=9\)

x = 7 => x - 6 = 1

=> \(\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}=1^{\left(x+6\right)^{\left(x+5\right)}}=1\)

\(\Rightarrow P=\left(x-4\right)^{\left(x-5\right)^1}=\left(7-4\right)^{\left(7-5\right)}=3^2=9\)

\(P=\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}=3^{2^{1^{13^{12}}}}\)

\(=3^{2^1}=3^2=9\)

Thay x = 7 vào biểu thức ta có:

\(\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}\)

\(=3^{2^{1^{13^{12}}}}\) . Vì 1 là số có mũ lên bao nhiêu cũng có kết quả là 1 nên:

\(3^{2^{1^{13^{12}}}}=3^2=9\)

Vậy P = 9

Chúc học tốt!

Thay x=7 vào P ta có:

\(\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}\)

\(=3^{2^{1^{13^{12}}}}=3^{2^1}\)(do \(1^n=1\)với \(n\in N\)*)

\(=3^2=9\)

Chúc bạn học tốt!!!

\(A=\frac{2^{30}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}\)

\(=\frac{2^3\left(2^{27}.5^7+2^{10}.5^{27}\right)}{2^{27}.5^7+2^{10}.5^{27}}\)

\(=2^3=8\)

\(\frac{2^{30}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}+\frac{2^{13}.5^7\left(2^{17}+5^{20}\right)}{2^{10}.5^7\left(2^{17}+5^{20}\right)}=2^3=8\)