\(x\)x\(x\)-\(\frac{1}{6}\)=\(\frac{5}{18}\)
Tìm \(x\):
1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
\(\frac{2}{\left(x+1\right)\left(x+3\right)}+\frac{5}{\left(x+3\right)+\left(x+8\right)}+\frac{10}{\left(x+8\right)\left(x+18\right)}+\frac{1}{x+18}=\frac{5}{6}\)
Tìm x;y;z
Tìm x:
\(\frac{x}{5}=\frac{1}{2}-\frac{1}{5}\)
\(\frac{1}{3}+\frac{2}{3}xX=\frac{18}{21}\)
\(\frac{3}{4}xX+\frac{x}{6}=\frac{1}{6}\)
\(2xX+3\frac{1}{2}+x=24\frac{1}{4}\)
Tìm x,biết
a)\(|x+\frac{1}{3}|=0\)
b)\(|x+\frac{3}{4}=\frac{1}{2}|\)
c)\(|\frac{5}{18}-x|-\frac{7}{24}=0\)
d)\(\frac{2}{5}-|\frac{1}{2}-x|=6\)
e)\(|\frac{3}{8}-x|+\frac{5}{6}=\frac{7}{4}\)
a, \(\left|x+\frac{1}{3}\right|=0\Leftrightarrow x=-\frac{1}{3}\)
b, \(\left|\frac{5}{18}-x\right|-\frac{7}{24}=0\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{5}{18}-x=\frac{7}{24}\\\frac{5}{18}-x=-\frac{7}{24}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{72}\\x=\frac{41}{72}\end{cases}}\)
c, \(\frac{2}{5}-\left|\frac{1}{2}-x\right|=6\Leftrightarrow\left|\frac{1}{2}-x\right|=-\frac{28}{5}\)vô lí
Vì \(\left|\frac{1}{2}-x\right|\ge0\forall x\)*luôn dương* Mà \(-\frac{28}{5}< 0\)
=> Ko có x thỏa mãn
\(|x+\frac{1}{3}|=0\)
\(< =>x+\frac{1}{3}=0< =>x=-\frac{1}{3}\)
\(|x+\frac{3}{4}|=\frac{1}{2}\)
\(< =>\orbr{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{cases}}\)
\(< =>\orbr{\begin{cases}x=-\frac{1}{4}\\x=-\frac{5}{4}\end{cases}}\)
\(|\frac{5}{18}-x|-\frac{7}{24}=0\)
\(< =>|\frac{5}{18}-x|=\frac{7}{24}\)
\(< =>\orbr{\begin{cases}\frac{5}{18}-x=\frac{7}{24}\\\frac{5}{18}-x=-\frac{7}{24}\end{cases}}\)
\(< =>\orbr{\begin{cases}x=-\frac{1}{72}\\x=\frac{41}{72}\end{cases}}\)
\(\frac{2}{5}-|\frac{1}{2}-x|=6\)
\(< =>\frac{2}{5}-6=|\frac{1}{2}-x|\)
\(< =>\orbr{\begin{cases}\frac{1}{2}-x=-\frac{28}{5}\\\frac{1}{2}-x=\frac{28}{5}\end{cases}}\)
\(< =>\orbr{\begin{cases}x=\frac{61}{10}\\x=-\frac{51}{10}\end{cases}}\)
tìm x biết :
a) \(\frac{6}{7}.x=\frac{18}{23}\)
b) \(2\frac{1}{2}.x=\frac{5}{6}\)
c) \(x:2\frac{3}{4}=9\frac{5}{8}\)
d)\(7\frac{1}{7}.\frac{1}{7}.x=22\frac{1}{8}\)
a/ \(\frac{6}{7}x=\frac{18}{23}\)
\(x=\frac{18}{23}:\frac{6}{7}=\frac{21}{23}\)
b/ \(2\frac{1}{2}x=\frac{5}{6}\)
\(=>\frac{5}{2}x=\frac{5}{6}\)
\(x=\frac{5}{6}:\frac{5}{2}=\frac{1}{3}\)
c/\(x:2\frac{3}{4}=9\frac{5}{8}\)
\(x:\frac{11}{4}=\frac{77}{8}\)
\(x=\frac{77}{8}\cdot\frac{11}{4}=\frac{847}{32}\)
d/\(7\frac{1}{7}\cdot\frac{1}{7}\cdot x=22\frac{1}{8}\)
\(\frac{50}{49}x=\frac{177}{8}\)
\(x=\frac{177}{8}:\frac{50}{49}=\frac{8673}{400}\)
\(a,\frac{6}{7}.x=\frac{18}{23}\) \(\Rightarrow x=\frac{18}{23}:\frac{6}{7}=\frac{18}{23}.\frac{7}{6}=\frac{21}{23}\)
\(b,2\frac{1}{2}.x=\frac{5}{6}\Rightarrow\frac{5}{2}.x=\frac{5}{6}\Rightarrow x=\frac{5}{6}:\frac{5}{2}=\frac{5}{6}.\frac{2}{5}=\frac{1}{3}\)
\(c,x:2\frac{3}{4}=9\frac{5}{8}\Rightarrow x:\frac{11}{4}=\frac{77}{8}\Rightarrow x=\frac{77}{8}.\frac{11}{4}=\frac{847}{32}\)
\(d,7\frac{1}{7}.\frac{1}{7}.x=22\frac{1}{8}\Rightarrow\frac{50}{49}.x=\frac{177}{8}\Rightarrow x=\frac{177}{8}:\frac{50}{49}=\frac{177}{8}.\frac{49}{50}=\frac{8673}{400}\)
TÌM X
\(\frac{1}{6}+\frac{-5}{7}\div x=\frac{-7}{18}\)
1/6 + -5/7 chia x = -7/18
-5/7 chia x = -7/18 - 1/6
-5/7 chia x = -10/18
x = -10/18 nhân -5/7
x = -50/126 = -25/63
XIN LỖI MÁY TÍNH TỚ KHÔNG VIẾT ĐƯỢC DẤU CHIA, CÒN DẤU NHÂN THÌ TỚ VIẾT CHO RÕ
Tìm x \(\frac{-9}{|x-18|}=\frac{5}{-6}\)
\(\left(-9\right).\left(-6\right)=5.|x-18|\)
\(54=5.|x-18|\)
\(|x-18|=\frac{54}{5}\)
\(=>\orbr{\begin{cases}x-18=-\frac{54}{5}\\x-18=\frac{54}{5}\end{cases}}\)
\(=>\orbr{\begin{cases}x=....\\x=...\end{cases}}\)
P/S: bn tự tính nha
\(ĐK:x\ne18\)
Ta có : \(\frac{-9}{|x-18|}=\frac{5}{-6}\Rightarrow\left(-9\right).\left(-6\right)=5.|x-18|\)
\(\Rightarrow5.|x-18|=54\)
\(\Rightarrow|x-18|=54:5=10,8\)
\(\Rightarrow\orbr{\begin{cases}x-18=10,8\\x-18=-10,8\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x=10,8+18=28,8\\x=-10,8+18=7,2\end{cases}}\left(TMĐK\right)\)
Vậy x=28,8 hoặc x=7,2.
(Nhớ k nha!!!)
Bài 18 tìm x
a) x - \(\frac{5}{7}=\frac{1}{9}\)
b) \(\frac{-3}{7}-x=\frac{4}{5}+\frac{-2}{3}\)
c) \(x-\frac{1}{5}=\frac{2}{7}.\frac{-11}{5}\)
d) \(\frac{x}{182}=\frac{-6}{14}.\frac{35}{91}\)
a) \(x-\frac{5}{7}=\frac{1}{9}\Rightarrow x=\frac{1}{9}+\frac{5}{7}\Rightarrow x=\frac{52}{63}\)
b) \(\frac{-3}{7}-x=\frac{4}{5}+\frac{-2}{3}\Rightarrow\frac{-3}{7}-x=\frac{2}{15}\Rightarrow x=\frac{-3}{7}-\frac{2}{15}\Rightarrow x=\frac{-59}{105}\)
c) \(x-\frac{1}{5}=\frac{2}{7}.\frac{-11}{5}\Rightarrow x-\frac{1}{5}=\frac{-22}{35}\Rightarrow x=\frac{-22}{35}+\frac{1}{5}\Rightarrow x=\frac{-3}{7}\)
d) \(\frac{x}{182}=\frac{-6}{14}.\frac{35}{91}\Rightarrow\frac{x}{182}=\frac{-15}{91}\Rightarrow x=\frac{\left(-15\right).182}{91}\Rightarrow x=-30\)
tìm x
a) \(x-\left[\frac{13}{18}x-\frac{24}{108}\right]=\left(\frac{-2}{3}\right)^2\)
b) \(3-7\frac{7}{12}< x< -\frac{5}{9}:\left(\frac{5}{9}-\frac{1}{6}\right)\)
\(\Leftrightarrow\)\(x-\left(\frac{13x}{18}-\frac{4}{18}\right)=\frac{4}{9}\)
\(\Leftrightarrow\)\(\frac{18x}{18}-\frac{13x}{18}+\frac{4}{18}=\frac{4}{9}\)
\(\Leftrightarrow\)\(\frac{5x}{18}=\frac{4}{9}-\frac{4}{18}\)
\(\Leftrightarrow\)\(\frac{5x}{18}=\frac{2}{9}\)
\(\Leftrightarrow\)\(5x=\frac{18.2}{9}\)
\(\Leftrightarrow\)\(5x=4\)
\(\Leftrightarrow\)\(x=\frac{4}{5}\)
tìm x biết
a,\(\left(152\frac{2}{4}-148\frac{3}{8}\right):0,2=x:0,3\)
b,\(\left(85\frac{7}{30}-83\frac{5}{18}\right):2\frac{2}{3}=0,01x:4\)
c,\(\frac{x-1}{x+5}=\frac{6}{7}\)
d,\(\frac{x^2}{6}=\frac{24}{25}\)
e,\(\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
g\(\frac{x-3}{x+5}=\frac{5}{7}\),
a, ( 152 +và 2/4 - 148 và 3/8 ) : 0,2 = x : 0,3
=> 33/8 : 1/5 = x : 3/10
=> x : 3/10 = 165/8
=> x = 99/10
b, ( 85 và 7/30 - 83 và 5/18 ) : 2 và 2/3 = 0,01x : 4
=> 88/45 : 8/3 = 0,01x : 4
=> 0,01x : 4 = 11/15
=> 0,01x = 44/15
=> x = 880/3
c, x - 1/ x + 5 = 6/7
=> 7( x - 1 ) = 6( x + 5 )
=> 7x - 7 = 6x + 30
=> 7x - 6x = 7 + 30
=> x = 37
d, x2/6 = 24/25
=> x2. 25 = 6 . 24
=> x2.25 = 144
=> x2 = 144/25
=> x = ( 12/5)2 hoặc x = ( -12/5)
g, x - 3/ x + 5 = 5/7
=> 7( x - 3 ) = 5 ( x + 5 )
=> 7x - 21 = 5x + 25
=> 7x - 5x = 21 + 25
=> 2x = 46
=> x = 23