[2/11.13+2/13.15+2/15.17+2/17.19+2
[2/11.13+2/13.15+2/15.17+2/17.19+2/19.20].462-x=19
Đặt \(A=\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}^{ }\)
\(A=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\)
\(A=\frac{1}{11}-\frac{1}{21}\)
\(A=\frac{10}{231}\)
Thay \(A=\frac{10}{231}\) vào ta có
\(\frac{10}{231}.462-x=19\)
\(20-x=19\)
\(x=20-19\)
\(x=1\)
boi vi\(\frac{10}{231}.462=20\) cho mik dung nha
(2/11.13 + 2/13.15 + 2/15.17 + 2/17.19 + 2/19.21).462-x=19
=(1/11-1/13)+(1/13-1/15)+(1/15-1/17)+(1/17-1/19)+(1/19-1/21)*462-X=19
=(1/11-1/21)*462-X=19
=10/231*462-X=19
=20-X=19
=X=20-19
=X=1
lop nam cung lam duoc
\(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right).462-x=19\)
\(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right)\) ) . 462 - x = 19
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\) . 462 - x = 19
\(\left(\frac{1}{11}-\frac{1}{21}\right)\) . 462 - x = 19
... Chúc bạn học tốt !
\(\left(\frac{2}{11\cdot13}+\frac{2}{13\cdot15}+\frac{2}{15\cdot17}+\frac{2}{17\cdot19}+\frac{2}{19\cdot21}\right)\)\(\cdot462-x=19\)
\(\left(\frac{1}{11\cdot13}+\frac{1}{13\cdot15}+\frac{1}{15\cdot17}+\frac{1}{17\cdot19}+\frac{1}{19\cdot21}\right)\)\(\cdot462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\)\(\cdot462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)\cdot462-x=19\)
\(\frac{10}{231}\cdot462-x=19\)
\(20-x=19\)
\(x=20-19\)
\(x=1\)
2/11.13 +2/13.15+2/15.17 +...+2/53.55
Gọi A = 2/11.13 +2/13.15+2/15.17 +...+2/53.55
=> A = 1/11-1/13+1/13-1/15+...+1/53-1/55
=> A = 1/11-1/55
=> A = 4/55
Đúng 100%
=1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55
=1/11-1/55
=5/55-1/55
=4/55
2 : [ 11.13 ] + 2 : [ 13.15 ] + 2 : [ 15.17 ] + ...+ 2 : [ 209.211]
\(\frac{2}{11.13}+\frac{2}{13.15}+.....+\frac{2}{209.211}\)
\(=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\)\(+.....+\frac{1}{209}-\frac{1}{211}\)
\(=\frac{1}{11}-\frac{1}{211}=\frac{200}{2321}\)
hok tốt
Đặt \(A=\text{2 : [ 11.13 ] + 2 : [ 13.15 ] + 2 : [ 15.17 ] + ...+ 2 : [ 209.211]}\)
\(\Rightarrow A=\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}...+\frac{2}{209.211}\)
\(\Rightarrow A=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{209}-\frac{1}{211}\)
\(\Rightarrow A=\frac{1}{11}-\frac{1}{211}\)
\(\Rightarrow A=\frac{200}{2321}\)
~Study well~
Sai thì thôi nhé :D !
\(2:\left(11.13\right)+2:\left(13.15\right)+2:\left(15.17\right)+...+2:\left(209:211\right)\)
\(=\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{209.211}\)
\(=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{209}-\frac{1}{211}\)
\(=\frac{1}{11}+\left(\frac{1}{13}-\frac{1}{13}\right)+\left(\frac{1}{15}-\frac{1}{15}\right)+...+\left(\frac{1}{209}-\frac{1}{209}\right)-\frac{1}{211}\)
\(=\frac{1}{11}-\frac{1}{211}=\frac{200}{2321}\)
~ Hok tốt ~
tìm x
a:( 2 + 2 + 2 + 2 + 2 )
_________________________________ .462 _x =19
( 11.13 +13.15 +15.17 +17.19 +19.21)
câu hỏi của tôi giống câu A của nguyễn
\(\frac{2+2+2+2+2}{\left(11.13+13.15+15.17+17.19+19.21\right)}.462-X=19\)
\(\Rightarrow\)\(\frac{2}{263}.462-X=19\)
\(\Rightarrow\)\(\frac{924}{263}-X=19\)
\(\Rightarrow\)\(X=\frac{924}{263}-19\)
\(\Rightarrow X=\frac{-4073}{263}\)
( 2/11.13 + 2/13.15 + 2/15.17 + ... + 2/19.21) x 462 - (2104 : ( x + 1,05 ) : 0,1. x = 19
tìm x biết : x-(2/11.13+2/13.15+2/15.17+...+2/53.55)=3/11 giải chi tiết giúp mình . mình cảm ơn❤❤❤
x - (2/11.13 + 2/13.15 + 2/15.17 +...+ 2/53.55) = 3/11
=> x - (1/11 - 1/13 + 1/13 - 1/15 + 1/15 - 1/17 +...+ 1/53 - 1/55) = 3/11
=> x - (1/11 - 1/55) = 3/11
=> x - (5/55 - 1/55) = 3/11
=> x - 4/55 = 15/55
=> x = 15/55 + 4/55
=> x = 19/55