\(\frac{4x-8}{x+5}\)* \(\frac{25-^2}{2x-^2}\)thuc hien phep tinh nay ai giai giup mk vs
thuc hien phep tinh \(\frac{4x-8}{x+5}\)* \(\frac{25-x^2}{2x-x^2}\)
\(\frac{4x-8}{x+5}\)* \(\frac{25-x^x}{2x-x^2}\)
\(=\)\(\frac{4\left(x-2\right)\left(5-x\right)\left(5+x\right)}{\left(x+5\right)x\left(2-x\right)}\)
\(=\)\(\frac{-4\left(5-x\right)}{x}\)\(=\)\(\frac{x-20}{x}\)
THUC HIEN PHEP TINH:\(\frac{^{x^2}}{5x+25}-\frac{10-2x}{x}+\frac{5x+50}{5x+x^2}\)
LAM ON GIUP MINH VS LAM HOAI MA NO CU SAI T.T
\(\frac{x^2}{5x+25}-\frac{10-2x}{x}+\frac{5x+50}{5x+x^2}=\frac{x^2}{5\left(x+5\right)}-\frac{10-2x}{x}+\frac{5x+50}{x\left(x+5\right)}\)
\(=\frac{x^3}{5x\left(x+5\right)}-\frac{5\left(x+5\right)\left(10-2x\right)}{5x\left(x+5\right)}+\frac{5\left(5x+50\right)}{5x\left(x+5\right)}\)
\(=\frac{x^3+10x^2+25x}{5x\left(x+5\right)}=\frac{x\left(x+5\right)^2}{5x\left(x+5\right)}=\frac{x+5}{5}\)
Giup mk giai phep tinh nay vs
\(\frac{6}{2-\sqrt{10}}-\frac{2\sqrt{5}-5\sqrt{2}}{\sqrt{2}-\sqrt{5}}+\sqrt{41+4\sqrt{10}}\)
khong thuc hien phep tinh,hay tim y trong tung phep tinh sau day(nho giai thich do nha)
y+17,28=17,28\(\frac{18}{9}\)x y =2y:6=0\(5\frac{2}{8}\):y=\(5\frac{2}{8}\)1.y+17,28=17,28
=>y=0
2.18/9x y=2 (chịu)
3.y:6=0
=>y=0
4.\(5\frac{2}{8}:y=5\frac{2}{8}\)
=>\(\frac{5}{4}:y=\frac{5}{4}\)
=>y=1
Nhớ k mk nha
Cai nay de lam, giup bn mk nhe
Thuc hien phep tinh : 5^7:5^4+(-2).21 - |-46|
5^7 : 5^4 + (-2) . 21 - |-46| =5^3 + (-42) - 46 =125 + (-88) = 37
5^7:5^4+(-2).21-I-46I
=5^3+(-42)-46
=125+(-42)-46
=83-46
=37
tk
1.Thuc hien phep tinh sau:
a,(3x^2-4x+5)(2x^2-4)-2x(3x^3-4x^2+8)
b,(1-3x+x^2)(2-4x)+2x(2x^2+5)
a ) \(\left(3x^2-4x+5\right)\left(2x^2-4\right)-2x\left(3x^3-4x^2+8\right)\)
\(=\left(3x^2-4x+5\right).2x^2-4\left(3x^2-4x+5\right)-6x^4+8x^3-16x\)
\(=6x^4-8x^3+10x^2-12x^2+16x-20-6x^4+8x^3-16x\)
\(=\left(6x^4-6x^4\right)+\left(8x^3-8x^3\right)-\left(12x^2-10x^2\right)+\left(16x-16x\right)-20\)
\(=-2x^2-20\)
b ) \(\left(1-3x+x^2\right)\left(2-4x\right)+2x\left(2x^2+5\right)\)
\(=2\left(1-3x+x^2\right)-4x\left(1-3x+x^2\right)+4x^3+10x\)
\(=2-6x+2x^2-4x+12x^2-4x^3+4x^3+10x\)
\(=\left(4x^3-4x^3\right)+\left(12x^2+2x^2\right)+\left(10x-6x-4x\right)+2\)
\(=14x^2+2\)
Giup mk not bai nay , dang gap !
Thuc hien phep tinh:
a, (x -2) ^3 -x(x+1)(x-1) + 6x(x -3)
b, (x-2)(x^2 - 2x +4)(x+2)(x^2 +2x + 4)
Thanks moi ng nha !
Thuc hien cac phep tinh
a) \(\frac{4x^2}{5y^2}:\frac{6x}{5y}:\frac{2x}{3y}\)
b) \(\frac{x^2-4}{3x+12}.\frac{x+4}{2x-4}\)
c) \(\frac{x^2-36}{2x+10}.\frac{3}{6-x}\)
a) \(\frac{4x^2}{5y^2}.\frac{5y}{6x}.\frac{3y}{2x}=\frac{4x^2.5y.3y}{5y^2.6x.2x}=1\)
b)\(\frac{\left(x-2\right)\left(x+2\right)}{3\left(x+4\right)}.\frac{x+4}{2\left(x-2\right)}=\frac{x+2}{6}\)
c) \(\frac{\left(x-6\right)\left(x+6\right)}{2\left(x+5\right)}.\frac{-3}{x-6}=\frac{-3\left(x+6\right)}{2\left(x+5\right)}\)
Tim x: 3.2^x+2^x=16
(3x-2)^2+1/4=1/2
Thuc hien phep tinh: 5.(-0,2)^2+3/8.(9/2-2,5)^2-(-1/5)
Mn giup mk nha
Please