x^2 - 7xy + 10y^2 
= (x^2 - 2xy) - (5xy - 10y^2) 
= x(x - 2y) - 5y( x - 2y) 
= (x - 5y)(x - 2y) 

mik mới học lớp 7 thôi!

Ta có : x³ - 3x² + 1 - 3x

= x³ - 2x² - x - (x² - 2x - 1) 

= x(x² - 2x - 1) - (x² - 2x - 1) 

= (x² - 2x - 1) (x - 1) 

= x^2 - 7xy + 10y^2
= x^2 - 2xy -5xy + 10y^2
= x( x - 2y ) - 5y( x - 2y )
= ( x - 2y )( x - 5y )

x² – 7xy + 10y2 

= x² – 2xy – 5xy + 10y²

= x(x – 2y) – 5y(x – 2y)

= (x – 2y)(x – 5y)

\(a,x^2\left(x-2\right)-4x+8\\ =\left(x^2-4\right)\left(x-2\right)\\ =\left(x-2\right)^2\left(x+2\right)\\ b,x^2+7xy+10y^2\\ =x^2+2xy+5xy+10y^2\\ =x\left(x+2y\right)+5y\left(x+2y\right)\\ =\left(x+5y\right)\left(x+2y\right)\)

$=x^2-2xy-5xy+10y^2\\=x(x-2y)-5y(x-2y)\\=(x-5y)(x-2y)$

\(x^2+4x-y^2+4\)

\(=\left(x^2+4x+4\right)-y^2\)

\(=\left(x^2+2\right)^2-y^4\)

\(=\left(x^2+y^2+2\right)\left(x^2-y^2+2\right)\)

\(\left(x^2+4x+4\right)-y^2\)

\(=\left(x+2\right)^2-y^2\)

\(=\left(x+2+y\right)\left(x+2-y\right)\)

.

hk tôt

mới lớp 1 thôi

Làm tử tế giúp mình đi,,,,,,,

mk ghi kết quả, ko phân tích đc thì ib

1)  \(x^3+x^2y-4x-4y=\left(x-2\right)\left(x+2\right)\left(x+y\right)\)

2)  \(x^3-3x^2+1-3x=\left(x+1\right)\left(x^2-4x+1\right)\)

3) \(3x^2-6xy+3y^2-12z^2=3\left(x-y-2z\right)\left(x-y+2z\right)\)

4) \(x^2-2x-15=\left(x+3\right)\left(x-5\right)\)

5)  \(2x^2+3x-5=\left(x-1\right)\left(2x+5\right)\)

6)  \(2x^2-18=2\left(x-3\right)\left(x+3\right)\)

7) \(x^2-7xy+10y^2=\left(x-2y\right)\left(x-5y\right)\)

8) \(x^3-2x^2+x-xy^2=x\left(x-y-1\right)\left(x+y-1\right)\)