tim x
/x/+/-5/=/-37/ /-6/./x/=/54/ /x/>21
/x/>-3 /x/<-1
x+3=/-3/+//-7/
-2</x/<2
Tim x biet
a) |x| + |-5| =|-37|
b) |-6|.|x|=|54|
a)|x|+|-5|=|-37|
=>|x|+5=37
=>|x|=37-5
=>|x|=32
=>x thuộc{32,-32}
b)|-6|.x=|54|
=>6.|x|=54
=>|x|=54:6
=>|x|=9
=> x thuộc {9,-9}
a,|x|=37-5
|x|=32 => x= -32;32
b,6.|x|=54
|x|=54:6=9
=>x=9 ; -9
a)32 hoặc -32
b)9 hoặc -9, tick mik nha
1tim x ∈ Z thoa man
a)/x/+/-5/=/-37/ b)/-6/./x/=/54/
c)/x/>21 d)/x/<-1
2tim x
a)x+3=/-3/+/-7/ b)-2</x/<2
a) |x| + |-5| = |-37|
<=> |x| + 5 = 37
<=> |x| = 37 - 5 = 32
=> x \(\in\) {32 ; -32}
b)|-6| . |x| = |54|
<=> 6 . |x| = 54
|x| = 54 : 6 = 9
=> x \(\in\){9;-9}
c) |x| > 21
Có |x| \(\ge\) 0 > 21
=> |x| \(\in\) { 22 ; 23 ; 24 ; 25 ; ....}
=> x \(\in\) { 22; -22 ; 23; -23; 24; -24; 25; -25; ....}
Bài 2:
a) 37 x 7 - 17 x 11 + 13 x 37 + 17 x 21
b) 55 x 52 : 54 - 28 : 24
c) 311 x 12 + 312 x 5 - 314
`#040911`
`a)`
\(37 \times 7 - 17 \times 11 + 13 \times 37 + 17 \times 21\)
`= 37 \times (7 + 13) + 17 \times (21 - 11)`
`= 37 \times 20 + 17 \times 10`
`= 10 \times (37 \times 2 + 17)`
`= 10 \times 91`
`= 910`
`b)`
\(5^5 \times 5^2 \div 5^4 - 2^8 \div 2^4\)
`=`\(5^{5+2-4}-2^{8-4}\)
`= 5^3 - 2^4`
`= 125 - 16`
`= 109`
`c)`
\(3^{11}\times12+3^{12}\times5-3^{14}\)
`=`\(3^{11}\times\left(12+3\times5-3^3\right)\)
`=`\(3^{11}\times\left(12+15-27\right)\)
`=`\(3^{11}\times0=0\)
a) = 259 - 187 + 481 + 357
= 910
b) = 57 : 54 - 24
= 53 - 24
= 125 - 16
= 109
Bài 2:
a, 37 x 7 - 17 x 11 + 13 x 37 + 17 x 21
= ( 37 x 7 + 13 x 37) + ( 17 x 21 - 17 x 11)
= 37 x ( 7 + 13) + 17 x ( 21 - 11)
= 37 x 20 + 17 x 10
= 740 + 170
= 910
b, 55 x 52 : 54 - 28 : 24
= 57: 54 - 24
= 53 - 16
= 125 - 16
= 109
c, 311 x 12 + 312 x 5 - 314
311 x ( 12 + 3 x 5 - 133)
= 311 x ( 12 + 15 - 33)
= 311 x ( 27 - 27)
= 311 x 0
= 0
Bài 2: Tính nhanh:
a) 4 x 76 + 76 x 7
b) 4 x 54 + 54 x 2 + 5 x 54
c) 37 + 3 x 37 + 5 x 37 + 2 x 37
a) 4 x 76 + 76 x 7
= (4 + 7) x 76
= 11 x 76
= 836
b) 4 x 54 + 54 x 2 + 5 x 54
= (4 + 4 + 5) x 54
= 13 x 54
= 702
c) 37 + 3 x 37 + 5 x 37 + 2 x 37
= 37 x (3 + 5 + 2)
= 37 x 10
= 370
a) 4 x 76 + 76 x 7
= (4 + 7) x 76
= 11 x 76
= 836
b) 4 x 54 + 54 x 2 + 5 x 54
= (4 + 4 + 5) x 54
= 13 x 54
= 702
c) 37 + 3 x 37 + 5 x 37 + 2 x 37
= 37 x (3 + 5 + 2)
= 37 x 10
= 370
a) 4 x 76 + 76 x 7
= (4 + 7) x 76
= 11 x 76
= 836.
b) 4 x 54 + 54 x 2 + 5 x 54
= (4 + 2 + 5) x 54
= 11 x 54
= 594.
c) 37 + 3 x 37 + 5 x 37 + 2 x 37
= 37 x (3 + 5 + 2 + 1)
= 37 x 11
= 407.
1. Tìm x, biết:
a.x-(32-37)=3x-(32+x)
b.45-(2x-37)= -x-54
c.42-(3-x)=25-34
d.(25+2x)-34=x-54
2.Tìm x, biết:
a.8x-75=5x+21
b.9x+25= -(2x-58)
c.|2x+1|=|-5|
d.3.(x-2)+4.( -2+x)=6.(x-2)
3. Tính giá trị biểu thức
a.ax+ay+bx+by với a+b= -2 và x+y=17
b.ax-ay+bx-by với a+b=-7 và x-y=-1
Tìm x
11/8 : x - 2/5 + -1/6= -1/5
4/7. x-x. 1/3 + -16/21 = -2/3
-11/12.x + 15/2. ( x + -1/5) = 67/8
\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)
\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)
1)tìm x
a)(1/3-5/6.x)^3+21/54=5/6
b)1/12-1/3(1/2.x-1)^4=1/16
c)(3/5)^x-1+5.(3/5)^x-1=54/25
d)(2/3)^x+(2/3)^x+2=101/243
2) so sánh
a)1/27^11 và 1/81^8
b)1/3^99 và 1/11^21
a) => \(\left(\frac{1}{3}-\frac{5}{6}x\right)^3=\frac{5}{6}-\frac{21}{54}=\frac{24}{54}=\frac{4}{9}\)
=> \(\frac{1}{3}-\frac{5}{6}x=\sqrt[3]{\frac{4}{9}}\) => \(\frac{5}{6}x=\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\) => \(x=\frac{6}{5}.\left(\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\right)\)
b) \(\frac{1}{3}\left(\frac{1}{2}x-1\right)^4=\frac{1}{12}-\frac{1}{16}=\frac{1}{48}\) => \(\left(\frac{1}{2}x-1\right)^4=\frac{3}{48}=\frac{1}{16}\)
=> \(\frac{1}{2}x-1=\frac{1}{2}\) hoặc \(\frac{1}{2}x-1=-\frac{1}{2}\)
=> \(\frac{1}{2}x=\frac{3}{2}\) hoặc \(\frac{1}{2}x=\frac{1}{2}\) => x = 3 hoặc x = 1
c) \(\left(1+5\right).\left(\frac{3}{5}\right)^{x-1}=\frac{54}{25}\) => \(\left(\frac{3}{5}\right)^{x-1}=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)
=> x - 1= 2 => x = 3
d) \(\left(1+\left(\frac{2}{3}\right)^2\right).\left(\frac{2}{3}\right)^x=\frac{101}{243}\) => \(\frac{13}{9}.\left(\frac{2}{3}\right)^x=\frac{101}{243}\)
=> \(\left(\frac{2}{3}\right)^x=\frac{101}{243}:\frac{13}{9}=\frac{101}{351}\) (có lẽ đề sai)
2) \(\frac{1}{27^{11}}=\frac{1}{\left(3^3\right)^{11}}=\frac{1}{3^{33}}\); \(\frac{1}{81^8}=\frac{1}{\left(3^4\right)^8}=\frac{1}{3^{32}}\)
Vì 333 > 332 => \(\frac{1}{3^{33}}\) < \(\frac{1}{3^{32}}\) => \(\frac{1}{27^{11}}\) < \(\frac{1}{81^8}\)
b) \(\frac{1}{3^{99}}=\frac{1}{\left(3^3\right)^{33}}=\frac{1}{27^{33}}
1)tìm x
a)(1/3-5/6.x)^3+21/54=5/6
b)1/12-1/3(1/2.x-1)^4=1/16
c)(3/5)^x-1+5.(3/5)^x-1=54/25
d)(2/3)^x+(2/3)^x+2=101/243
2) so sánh
a)1/27^11 và 1/81^8
b)1/3^99 và 1/11^21
tim x thuoc N biet
10 + 2 . x = 4 .4.4.4.4 : 4.4.4
231 - ( x -6) = 1339 : 13
1818 : ( 6x - 37 ) = 18
21 + ( 25 - x) =50
( x + 13) :5=2
( 2600+6400) - 3x=1200