2.|x+183|-2.52=100
Những câu hỏi liên quan
CMR 1.3.5. ... .99 = 51/2.52/2. ... .100/2
so sánh 1.3.5.7.....99 và 51/2.52/2.53/2.....100/2
C=1.3.5.7.....99 và D=51/2.52/2.53/2....100/2
chứng minh rằng:
51/2.52/2.....100/2=1.3.5.....99
chung minh rang
51/2.52/2.....100/2=1.3.5.....99
So sanh : A=1.3.5.7...99 va B =51/2.52/2...100/2
\(A=\frac{1.2.3...........99.100}{2.4.6....100}\)
\(=\frac{1.2.3..............99.100}{1.2.2.2.2.3.........50.2}\)
\(=\frac{1.2.3.......50........99.100}{\left(1.2.3........50\right).2.2.....2}\)
\(=\frac{51.52..........99.100}{2.2............2}\)
\(=\frac{51}{2}.\frac{52}{2}...........\frac{100}{2}\)
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So sanh S=1.3.5.7....99 với D=51/2.52/2.....100/2
So sánh C = 1.3.5.7...99 với D = 51/2.52/2.53/2...100/2
cho A = 1.3.5.7......99
cho B = 51/2.52/2........100/2
so sanh A =1.3.5.7...99 va B=51/2.52/2...100/2
Ta có : \(1\cdot3\cdot5\cdot...\cdot99=\frac{1\cdot2\cdot3\cdot4\cdot...\cdot99\cdot100}{2\cdot4\cdot6\cdot...\cdot100}\)
\(=\frac{1}{2\cdot1}\cdot\frac{2}{2\cdot2}\cdot...\cdot\frac{100}{2\cdot50}=\frac{1\cdot2\cdot3\cdot4\cdot...\cdot100}{1\cdot2\cdot3\cdot...\cdot50\cdot2\cdot2\cdot2\cdot...\cdot2}\)( 50 thừa số 2 )
\(=\frac{51\cdot51\cdot...\cdot100}{2\cdot2\cdot2\cdot...\cdot2}\)\(=\frac{51}{2}\cdot\frac{52}{2}\cdot\frac{53}{2}\cdot...\cdot\frac{100}{2}\)
Vậy A = B
Chúc bn hok tốt !!! ^_^
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