F=2+4+6+8+16+...+2048+4096
2+4+6+8+16+...+2048+4096
số số hạng là:
(4096 - 2) : 2 + 1 = 2048
Tổng trên là:
(4096 + 2) . 2048 : 2 = 4196352
1+1=?
2+2=?
4+4=?
8+8=?
16+16=?
32+32=?
64+64=?
128+128=?
256+256=?
512+512=?
1024+1024=?
2048+2048=?
4096+4096=?
Giải đi
2
4
8
16
32
64
128
256
512
1024
2048
4096
8192
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
64+64=128
128+128=256
512+512=1024
2048+2048=4096
xong
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048
2048+2048=4096
4096+4096=8192
1/2+1/4+1/8+1/16+..........................+1/2048+1/4096
bn tham khảo tại link này nhé :
https://olm.vn/hoi-dap/question/656309.html
https://olm.vn/hoi-dap/question/656309.html
1/2+1/4+1/8+1/16+1/32+...+1/2048+1/4096
Đặt A=1/2+1/4+1/8+1/16+1/32+...+1/2048+1/4096
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{12}}\)
\(2A=2\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)
\(2A=1+\frac{1}{2}+...+\frac{1}{2^{11}}\)
\(2A-A=\left(1+\frac{1}{2}+...+\frac{1}{2^{11}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)
\(A=1-\frac{1}{2^{12}}\)
Tính S = 1+1/2+1/4+1/8+1/16+........+1/2048+1/4096
Ta co: 2S=2+1+1/2+1/4+...+1/2048
2S-S=2+1+1/2+1/4+...+1/2048-1-1/2-1/4-...-1/2048-1/4096
\(\Rightarrow\)S=2-1/4096 =8191/4096
1 + 2 + 4 + 8 + 16 + 32 + ... + 1024 + 2048 + 4096 =?
KHẨN CẤP! KHẨN CẤP!
Đặt \(A=1+2+4+.........+4096\)
\(2A=2+4+8+......+8192\)
\(\Rightarrow2A-A=8192-1\)
\(\Rightarrow A=8191\)
Đặt \(S=1+2+4+...+1024+2048+4096\)
\(S=1+2^1+2^2+2^3+....+2^{10}+2^{11}+2^{12}\)
\(2S=2+2^2+2^3+....+2^{11}+2^{12}+2^{13}\)
\(2S-S=\left(2+2^2+2^3+....+2^{12}+2^{13}\right)-\left(1+2+2^2+....+2^{11}+2^{12}\right)\)
\(S=2^{13}-1=8192-1=8191\)
A=1+2+4+8+16+.....+1024+2048+4096
2A= 2+4+8+16+32+....+2048+4096+8192
2A-A=A=2+4+8+16+32+....+4096+8192-(1+2+4+8+16+...+1024+2048+4096)
A=8192-1
A=8191 k nha
A = 2+4+8+16+...+1024+2048+4096
A=...
GIẢI bằng ba cách
1 + 2 + 4 + 8 + 16 + +...+1024 + 2048 + 4096
GIÚP MÌNH NHÉ!
AI GIẢI ĐƯỢC LÀ LÀM NÊN KỲ TÍCH ĐẤY!
Đặt
\(S=1+2+4+...+2048+4096\)
\(S=1+2^1+2^2+...+2^{11}+2^{12}\)
\(2S=2+2^2+2^3+...+2^{12}+2^{13}\)
\(2S-S=\left(2+2^2+2^3+...+2^{13}\right)-\left(1+2+2^2+..+2^{12}\right)\)
\(S=2^{13}-1=8192-1=8191\)
Gọi A=1+2+4+8+16+...+1024+2048+4096
2A=2+4+8+16+32+...+2048+4096+8192
2A-A=(2+4+8+16+32+...+2048+4096+8192)-(1+2+4+8+16+...+1024+2048+4096)
A=8192-1
A=8191
Đặt A = 1 + 2 + 4 + 8 + 16 +...+ 1024 + 2048 + 4096
A = 1 + 2 + 22 + 23 + 24 +.... + 210 + 211 + 212
2A = 2 + 22 + 23 + 24 + 25 + ..... + 211 + 212 + 213
2A - A = (2 + 22 + 23 + 24 + .... + 211 + 212 + 213) - (1 + 2 + 22 + 23 + 24 +.....+ 210 + 211 + 212)
=> A = 213 - 1
=> A = 8192 - 1 = 8191
Ủng hộ mk nha !!! ^_^
Tính tổng :
A = 8 + 16 + 32 + 64 + ... + 2048 + 4096
Kết quả A=8184
Thấy đúng thì k cho mình nhé.
A=8+16+32+64+...+2048+4096
2A=8+16+32+64+...+8192
=>2A-A=8192-1
=>A=8191
số số hạng là : (4096-8):8+1=512
tổng là :A=(4096+8)x512/2=1050624
=> A=1050624