33^2x/11^2x=81
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tìm x biết: 33^2x : 11^2x =81
\(\Rightarrow\left(\dfrac{33}{11}\right)^{2x}=81\Rightarrow3^{2x}=3^4\Rightarrow x=2\)
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Tìm x 33x:11x-1=80
812x.27x=911
a) 33x:11x-1=80
3x=81
3x=34
x4
b) 812x.27x=911
(34)2x.(33)x=(32)11
38x.33x=322
38x+3x=322
311.x=322
11.x=22
x=2
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Tìm x 33x:11x-1=80
812x.27x=911
Tìm số nguyên x, biết: a) 12 + (2x - 11) = 53; b) 21 - (-6+ 3x) = 9 c) - (2x + 4) + 11 = -27; d) 33 - (33 - x) = 0
32^2x/11^2x=81
"/" là "phần"
\(\frac{32^{2x}}{11^{2x}}=81\)
Thu gọn biểu thức
VD: A= 3x + 5x + 8
A= 8x + 8
1. 6x + 4x2 + 6x2 +4x + 2
2. 18x + 5y + 12z + 2x + 6z + 15y + 2z + 3
3. 5x2 + 8y2 + 2x + 15x2 + 2y2 + 7
5 tháng 3 2023 lúc 20:40
1)x^3-16x
2)x^4-2x^3
3)(2x-11)(x^2-1)
4)x^3-36x
5)2x+19
1)
x^3 -16x=0`
`<=>x(x^2 -16)=0`
\(< =>\left[{}\begin{matrix}x=0\\x^2-16=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x^2=16\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=4\\x=-4\end{matrix}\right.\)
b)
`x^4 -2x^3=0`
`<=>x^3 (x-2)=0`
\(< =>\left[{}\begin{matrix}x^3=0\\x-2=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
3)
`(2x-11)(x^2 -1)=0`
\(< =>\left[{}\begin{matrix}2x-11=0\\x^2-1=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}2x=11\\x^2=1\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=1\\x=-1\end{matrix}\right.\)
4)
`x^3 -36x=0`
`<=>x(x^2 -36)=0`
\(< =>\left[{}\begin{matrix}x=0\\x^2-36=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x^2=36\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=6\\x=-6\end{matrix}\right.\)
5)
`2x+19=0`
`<=>2x=-19`
`<=>x=-19/2`
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tim so nghuyen x biet:
a, 12+(2x-11)=53
b, 21-(-6+3x)=9
c, -(2x+4)+11=-27
d, 33-(33-x)=0
a) 12+(2x-11)=53
(2x-11) = 53-12
2x-11= 41
2x=41+11
2x=52
x= 52:2
x=26
Vậy...
\(b,21-\left(-6+3x\right)=9\)
\(\Rightarrow21+6-3x=9\)
\(\Rightarrow27-3x=9\)
\(\Rightarrow3x=18\)
\(\Rightarrow x=6\)
c, -(2x+4)+11=-27
=>-2x-4+11=-27
=>-2x+7=-27
=>-2x = -34
=>x=17
d, 33-(33-x)=0
=>33-33+x=0
=>x=0