Tính A=4/1x3+9/2x4+...+2015^2/2014x2016
C=(1+1/1x3)x(1+1/2x4)x(1+1/3x5)............(1+1/2014x2016)
ting giá trị biểu thức sau :
C=(1+1/1x3)(1+1/2x4)(1+1/3x5)....(1+1/2014x2016)
giúp mình nhanh nhé mình tick cho
Tính giá trị biểu thức sau: A=1/2(1+1/1x3)(1+1/2x4)(1+1/3x5)...(1+1/2015*2017)
Tính : 2/2x4+2/4x6+2/6x8+....+2/2014x2016
2/2x4+ 2/4x6+ 2/6x8+...+2/2014x2016
=1/2-1/4+1/4-1/6+1/6-1/8+...+1/2014-1/2016
=1/2-1/2016
=1008/2016-1/2016
=1007/2016
Tính: 2/2x4+2/4x6+2/6x8+.............2/2014x2016
\(\frac{2}{2x4}+\frac{2}{4x6}+\frac{2}{6x8}+...+\frac{2}{2014x2016}\)
\(=\frac{4-2}{2x4}+\frac{6-4}{4x6}+\frac{8-6}{6x8}+...+\frac{2016-2014}{2014x2016}\)
\(=\frac{4}{2x4}-\frac{2}{2x4}+\frac{6}{4x6}-\frac{4}{4x6}+\frac{8}{6x8}-\frac{6}{6x8}+...+\frac{2018}{2016x2018}-\frac{2016}{2016x2018}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2016}-\frac{1}{2018}\)
\(=\frac{1}{2}-\frac{1}{2018}\)
\(=\frac{504}{1009}\)
Tính tổng :
A =5+10+15+ . . . . . + 2015+2020
B = 2/1x3 + 2/3x5 + 2/5x7 + . . . . . + 2/99x101
C = 1/2x4 + 1/4x6 + 1/6x8 + . . . . . + 1/98x100
Giải nhanh giúp mk nha ! ^.^
a) Số số hạng của dãy A là: (2020-5):2+1 = 404 (số)
Tổng A là: (2020+5)x404:2=409050
b) \(B=\frac{2}{1\times3}+\frac{2}{3\times5}+....+\frac{2}{99\times101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}=\frac{100}{101}\)
c) \(C=\frac{1}{2\times4}+\frac{1}{4\times6}+\frac{1}{6\times8}+...+\frac{1}{98\times100}\)
\(=\frac{1}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+....+\frac{2}{98\times100}\right)\)
\(=\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+....+\frac{1}{98}-\frac{1}{100}\right)\)
\(=\frac{1}{2}\times\left(1-\frac{1}{100}\right)=\frac{1}{2}\times\frac{99}{100}=\frac{99}{200}\)
Vậy .....
A = 5 + 10 + 15 + ... + 2015 + 2020
Số số hạng là : 404
A = 409050
\(B=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{99\cdot101}\)
\(B=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\)
\(B=1-\frac{1}{101}=\frac{101-1}{101}=\frac{100}{101}\)
\(C=\frac{1}{2\cdot4}+\frac{1}{4\cdot6}+\frac{1}{6\cdot8}+...+\frac{1}{98\cdot100}\)
\(C=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{4}\right)+\frac{1}{2}\cdot\left(\frac{1}{4}-\frac{1}{6}\right)+\frac{1}{2}\cdot\left(\frac{1}{6}-\frac{1}{8}\right)+...+\frac{1}{2}\cdot\left(\frac{1}{98}-\frac{1}{100}\right)\)
\(C=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{98}-\frac{1}{100}\right)\)
\(C=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{100}\right)=\frac{1}{2}\cdot\frac{49}{100}=\frac{49}{200}\)
2/2x4+2/4x6+2/6x8..................2/2014x2016
TA có
4-2/2*4+6-4/4*6+8-6/6*8+...+2016-2014/2014*2016
=1/2-1/4+1/4-1/6+...+1/2014-1/2016
=1/2+1/4-1/4+1/6-1/6+...+1/2014-1/2014-1/2016
=1/2-1/2016
=1007/2016
2/2x4+2/4x6+2/6x8+......................+2/2014x2016
=1/2-`1/4+1/4-1/6+1/6-1/8 +..............................+1/2014-1/2016
=1/2-1/2016
=1007/2016
2/2x4+2/4x6+2/6x8+....+2/2014x2016
đặt biểu thức đó là A
ta có A=\(\frac{2}{2x4}+\frac{2}{4x6}+...+\frac{2}{2014x2016}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{12}+...+\frac{1}{2014}-\frac{1}{2016}\)
=\(\frac{1}{2}-\frac{1}{2016}\)
=1007/2016
k nha đúng đấy
2/2x4+2/4x6+2/6x8+ . . . + 2/2014x2016
2/2x4+2/4x6+2/6x8+...+2/2014x2016
= 1/2-1/4+1/4-1/6+...+1/2014-1/2016
= 1/2- 1/2016
= 1007/2016
mk trả lời đầu tiên đó . k nhé ai k mk mk k lại
Bằng 1007/2016 nha bạn k mk nha kết bạn vs lun mk hết lượt rùi