biet a=22 nhan 34 voi x,y thuoc N* va a co 9 uoc. Tim a
tim so tu nhien a biet a=2^x.3^y voi x y thuoc N* va a co 15 uoc
cho a =2^x . 3^y voi z,y thuoc N* . biet a co 15 uoc . tim a
mấy bn giúp vs nhá
Tim n thuoc N biet so n co 30 uoc va khi phan tich thanh thua so nguyen to thi co dang n = 2^x × 3^y biet x+y =8
Tim n thuoc N , biet so n co 30 uoc va khi phan tich thanh thua so nguyen to thi co dang n = 2^x × 3^y biet x + y = 8
Bai 1: a)Tim so tu nhien a biet 1960va2002 chia cho a cung co so du la 28
b)Tim 2 sop tu nhien a va b , biet :BCNN(a,b)=300;UCLN(a,b)=15 va a+15=b
Bai 2:a)Tong sau la binh phuong so nao ?
S=1+3+5+7+...+199
b) Cho so ab va so ababab
1)chung to ababab la boi cua ab
2)So 3 va 10101 co phai la uoc cua ababab khong , vi sao?
Bai 3
a)Hay viet them dang sau so 664 ba chu so de nhan duoc sdo co 6 chu so chia het cho 5,9,11
b)Tim so nguyen x thuoc Z biet rang :
(x^2-1)(x^2-4)<0
Bai 4 :tim so nguyen x va y biet: xy-x+2y=3
bai 1:tim n thuoc n de:3(n+2) chia het cho n-2
bai 2chng minh rang cac so sau la cac so nguyen to cung nhau
a) 18n+3 va 21n+4
b)2n+1va3n+1
bai 3:tim hai so biet tong hai so la 90 va uoc chung lon nhat la 15
bai 4:tim so tu nhien n lon nhat co 3 chu so sao cho n :15 du 9va n:35 du 29
bai 5:tim uoc chung lon nhat cua cac so sau:
a)18n+3 va 21n+4
b)9n+13 va 3n+4
bai 6:chung minh: voi moi a,b thuoc nta co
UCLN(a,b)=UCLN (5a+2b,7a+3b)
AI DUNG TRUOC 9H MINH SE TICH CHO.THANHK YOU VERY MUCH!
Cho A thuoc {0.1.2.3.4.5.6.7.8.9.10} biet A co hon 1 phan tu neu x,y,z thuoc A va x<y<z thi z =x.y tim A
tim 2 so tu nhien a va b biet tich cua chung =210 biet rang voi 2 so tu nhien ab, ta co a.b= uoc chung lon nhat
Cho parabol (p) y=1/2×x2 va 2 diem A va B thuoc (p) co hoanh do lan luot la -1; 2. Duong thang (d) co phuong trinh y=mx+n
a) tim toa do hai diem A va B. Tim m va n biet (d) di qua 2 diem A va B
b) tim do dai duong cao OH cua tam giac OAB. biet O la goc toa do
a) xa =-1 =>ya =1/2.(-1)^2 =1/2=> A(-1;1/2)
xb=2 =>yb =1/2.2^2 =2=> B(2;2)
\(\left\{{}\begin{matrix}\dfrac{1}{2}=-m+n\\2=2m+n\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}-2m+2n=1\\2m+n=2\end{matrix}\right.\)=> n=1; m =1/2
b) \(AB=\sqrt{\left(x_b-x_a\right)^2+\left(y_b-y_a\right)^2}=\sqrt{3^2+\left(\dfrac{3}{2}\right)^2}=\sqrt{\dfrac{3^2\left(4^2+1\right)}{4^2}}=\dfrac{3\sqrt{17}}{4}\)\(S\Delta_{AOB}=\dfrac{1}{2}\left(\left|x_a\right|+\left|x_b\right|\right)\left(y_b-y_a\right)=\dfrac{1}{2}\left(1+2\right).\left(2-\dfrac{1}{2}\right)=\dfrac{1}{2}.3.\dfrac{3}{2}=\left(\dfrac{3}{2}\right)^2\)\(S_{\Delta AOC}=\dfrac{1}{2}OH.AB\)
\(OH=2.\dfrac{\dfrac{9}{4}}{\dfrac{3\sqrt{17}}{4}}=\dfrac{6}{\sqrt{17}}=\dfrac{6\sqrt{17}}{17}\)