Ta có:

\(S=10^2+20^2+30^2+....+140^2+150^2\)

\(=1^2.10^2+2^2.10^2+3^2.10^2+...+14^2.10^2+15^2.10^2\)

\(=10^2\left(1^2+2^2+3^2+...+14^2+15^2\right)\)

\(=100.1240\)

\(=124000\)

Vậy \(S=124000\)

Giải:

\(S=10^2+20^2+30^2+...+140^2+150^2\)

\(\Leftrightarrow S=10^2\left(1^2+2^2+3^2+...+14^2+15^2\right)\)

\(\Leftrightarrow S=100.1240\)

\(\Leftrightarrow S=124000\)

Vậy giá trị của biểu thức S là 124000.

Bài 2:

\(a,45+170+25+30\)

\(=\left(45+25\right)+\left(170+30\right)\)

\(=60+200=260\)

Bài 3:

\(a,\left(x-6\right).5=150\)

\(x-6=150:5\)

\(x-6=30\)

\(x=30+6\)

\(x=36\)

\(b,2^5.\left(3x-2\right)=2^3.2^6\)

\(2^5.\left(3x-2\right)=2^{3+6}\)

\(2^5.\left(3x-2\right)=2^9\)

\(3x-2=2^9:2^5\)

\(3x-2=2^4=16\)

\(3x=16+2\)

\(3x=22\)

\(x=22:3\)

\(x\approx7,3\)

\(c,100-7.\left(x-5\right)=51\)

\(7.\left(x-5\right)=100-51\)

\(7.\left(x-5\right)=49\)

\(x-5=49:7\)

\(x-5=7\)

\(x=7+5\)

\(x=12\)

Phần d) bạn thiếu dữ liệu ạ.

Giúp với ạ 

Giúp với ạ 

1)

a) -(2+5) = -2 - 5 = -7

b) +(-3+6) = -3 + 6 = 3

c) (-50+3) = -50 + 3 = -47

d) -(-2+3) = 2 - 3 = -1

e) -(10-3) = -10 + 3 = -7

f) -(-3)-(-3+1) = 3 + 3 - 1 = 5

g) (-5)+(-2+10) = -5 - 2 + 10 = 3

2)

a) -50+120+(-150)-20+30

= -(50 + 20) + (120 + 30 - 150)

= -70

b) 265-70+(-65)-30+15

= (265 - 65) - (70 + 30) + 15

= 200 - 100 + 15 = 115

c) -17+185-183+(-85)-63

= (185 - 85) - (183 + 17) - 63

= 100 - 200 - 63 = -163

d) -30+60+(-170)-260+19

= -(170 + 30) - (260 - 60) + 19

= -200 - 200 + 19 = -381

1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+9+8+9+10+12+13+14+15+16+17+18+19+20+30+1000000=10000274

10000274

10000274 nha

`1/2+2/4+3/6+4/8+5/10+6/12`

`=1/2+1/2+1/2+1/2+1/2+1/2`

`=1/2*6=3`

`1/3+1/4+1/5+8/10+20/15+20/30`

`=(1/3+1/4)+(1/5+4/5)+(4/3+2/3)`

`=7/12+1+2`

`=7/12+3=43/12`

\(\dfrac{1}{2}+\dfrac{2}{4}+\dfrac{3}{6}+\dfrac{4}{8}+\dfrac{5}{10}+\dfrac{6}{12}\)
\(=\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}\)
\(=\dfrac{1}{2}\times6=3\)
\(------\)
\(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{8}{10}+\dfrac{20}{15}+\dfrac{20}{30}\)
\(=\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{4}{5}+\dfrac{4}{3}+\dfrac{2}{3}\)
\(=\left(\dfrac{1}{3}+\dfrac{4}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\dfrac{1}{4}\)
\(=\dfrac{7}{3}+1+\dfrac{1}{4}\)
\(=\dfrac{28}{12}+\dfrac{12}{12}+\dfrac{3}{12}\)
\(=\dfrac{43}{12}\)

`=1/2+1/2+1/2+1/2+1/2+1/2= 1/2 \times 6=3`

`----`

`=1/3+1/4+1/5+4/5+4/3+2/3 =(4/3+2/3+)+(1/5+4/5)+1/3+1/4=2+1+1/3+1/4=3+1/3+1/4=43/12`

\(S=2^2+4^2+....+20^2=?\)

\(=\left(2.1\right)^2+\left(2.2\right)^2+\left(2.3\right)^2+....+\left(2.10\right)^2\)

\(=2^2.1^2+2^2.2^2+2^2.2^3+...+2^2.10^2\)

\(=2^2.\left(1^2+2^2+3^2+...+10^2\right)\)

\(=2^2.385\)

\(=4.385\)

\(=1540\)

S=2²+4²+...+20²

=> 1/2 .S=1²+2²+...+10²

=> 1/2 .S=385

=> S = 385 . 2

=> S = 770

P=(1.3)²+...+(10.3)

   =3²(1²+...+10²)

   =9.385 = 3465

Mọi người giúp em với em đang cần gấp!!

Câu 1:

\(a,=43\cdot\left(27+93\right)+3111+3363=43\cdot120+6474=11634\\ b,=11^2+2^{15}\cdot2^3:2^{17}=121+2=123\\ c,=11^2+7^2-9=121+49-9=151\)

Câu 2:

\(a,\Rightarrow x-\dfrac{3}{2}=5^2=25\\ \Rightarrow x=25+\dfrac{3}{2}=\dfrac{53}{2}\\ b,\Rightarrow7x=30-2=28\\ \Rightarrow x=4\)

b. S=(2+4+6+...+19+20)^2

P=(3+6+9+...+30)^2