Ta có : 1x2x3x...x9-1x2x3x...x8-1x2x3x...x8^2

=1x2x3x...x8x(9-1-8)

=1x2x3x...x8x0

=0

Nhớ  k cho mik nha !!!

ý bạn là nhân đa thức với đa thức hay sao ạ?

1. TÍNH 

`5/7 xx 4 : 5/9 = 5/7 xx 4 xx 9/5 = 20/7 xx 9/5 = 36/7`

`4/9 : 2 xx 5/7 = 4/9 xx 1/2 xx 5/7 = 2/9 xx 10/63 `

`8 xx 2/3 : 1/2= 8xx 2/3 xx 2/1 = 8 xx 2/3 xx 2 = 16/3 xx 2=32/3`

a, 1 x 2 x 3 x ... x 8 x 9 - 1 x 2 x 3 x ... x 8 - 1 x 2 x 3 x ... x 7 x 8 x 8 

= 1 x 2 x 3 x ... x 8 ( 9 - 1 - 8 ) = 1 x2 x 3 x ... x 8 . 0 = 0 

Bài post của vuong hien duc

a, 1.2.3...9-1.2.3...8-1.2.3...7.8²

= 1.2.3...7.8(9-1-8) = 0

b,\(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}=\frac{3.2^2.2^{16}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\) \(=\frac{3.2^{18}}{11.2^{13}.2^{22}-2^{36}}=\frac{3.2^{18}}{11.2^{35}-2^{36}}\)\(=\frac{3.2^{18}}{2^{35}\left(11-2\right)}=\frac{3.2^{18}}{2^{35}.9}=\frac{1}{2^{17}.3}\)

a)

(x*211)+(1+2+...+211)=23632

(x*211)+22366=23632

x*211=23632-22366

x*211=1266

x=1266:211

x=6

Vậy x=6

a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)

b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)

\(\dfrac{-5}{6}-\left(\dfrac{-3}{8}+\dfrac{1}{10}\right)\)
\(\dfrac{-5}{6}-\dfrac{-3}{8}-\dfrac{1}{10}\)