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Nguyễn Hoàng Tuấn Tú
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Rin•Jinツ
2 tháng 12 2021 lúc 7:42

9 ngày.

Nguyễn Hoàng Tuấn Tú
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Lưu Hà Giang
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Bùi Thái Sang
3 tháng 12 2017 lúc 11:01

ta có: 

BCNN(5,8,10)

5=5

8=2.2.2

10=2.5

=>BCNN(5,8,10)=2.2.2.5=40

Vậy sau ít nhất 40 ngày cả 3 thuyền cùng cập bến

Phạm Tuấn Đạt
3 tháng 12 2017 lúc 11:06

ta có: 

BCNN(5,8,10)

5=5

8=2.2.2

10=2.5

=>BCNN(5,8,10)=2.2.2.5=40

Vậy sau ít nhất 40 ngày cả 3 thuyền cùng cập bến

Tô Minh Hiếu
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Trần Quang Hiếu
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Không Quan Tâm
20 tháng 7 2016 lúc 9:48

Ta có số ngày cập bến ít nhất của ba thuyền là BCNN( 5;10;8)

8 = 2

10 = 2.5

Suy ra: BCNN(5;10;8)= 40

Vậy sau ít nhất 40 ngày thì cả ba thuyền cùng cập bến

trần nguyễn quang huy
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Võ Như Quỳnh
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OoO cô bé tinh nghịch Oo...
11 tháng 12 2016 lúc 14:18

Ta có số ngày cập bến ít nhất của 3 thuyền là BCNN ( 5;10;8 )

5 = 5

8 = 2^3

10 = 2.5

=> BCNN ( 5;10;8 ) = 40

Vậy sau ít nhất 40 ngày thì cả 3 thuyền cùng cập bến.

Đào Minh Đăng
5 tháng 2 2017 lúc 21:40

40 ngày

Nguyễn Minh Tuấn
3 tháng 8 2018 lúc 19:54

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Nguyen Khanh Huyen
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nguyễn văn dũng
5 tháng 8 2016 lúc 16:22

minh ko biết làm nhưng cứ k mình nhé mình là bạn mà

Pham Tien Dat
27 tháng 10 2016 lúc 21:39

280 ngay

Đỗ Hường
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Trên con đường thành côn...
23 tháng 8 2021 lúc 9:31

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Phía sau một cô gái
23 tháng 8 2021 lúc 9:33

Ta có số ngày cập bến gần nhất của ba thuyền là BCNN( 5; 10; 8 )

\(5=5^1\)

10 = 2 . 5

8 = 2\(^3\)

\(\Rightarrow\) BCNN( 5; 10; 8 ) = \(5^1.2^3\) = 40

Vậy sau ít nhất 40 ngày thì cả ba thuyền cùng cập bến