Tìm x biêt:
(x-5)4=(x-5)6
tìm a biêt: a x 5 : 6 =25
\(a\times5:6=25\)
\(a\times5=25\times6\)
\(a\times5=150\)
\(a=150:5\)
\(a=30\)
\(a\times5:6=25\\ a\times\dfrac{5}{6}=25\\ a=25:\dfrac{5}{6}\\ a=25\times\dfrac{6}{5}\\ a=30\)
a x 5 : 6 = 25
a x 5 = 25 x 6
a x 5 = 150
a =150 : 5
a = 30
Tìm x biêt x/5+x.2+x/5:1/2=13
x/5 + x2 + x/5:1/2=13
x/5 + x.2 + x/5 x 2 = 13
x/5.(1 + 2 ) + 2x = 13
x/5 .3 +2x = 13
3x/5 + 2x = 13
3x + 10x = 65
13x = 65
x = 65 : 13
x = 5
Tìm số nguyên x biêt( áp dụng quy tắc chuyển vế)
1/ -12+x =5 x- 20
2/ 7 x - 4= 20 +3x
3/ 5x -7 =-21 -2x
4/ x +15 = 20- 4x
5/ 17 -x = 7 - 6 x
1,-12 + x = 5x - 20
-12 + 20 = 5x - x
8 = 4x
x = 2
2, 7x - 4 = 20 + 3x
7x - 3x = 20 + 4
4x = 24
x = 6
3 , 5x - 7 = -21 - 2x
5x + 2x = -21 + 7
7x = -14
x = -14 : 7 = -2
4 , x + 15 = 20 - 4x
x + 4x = 20 - 15
5x = 5
x = 5 : 5 = 1
5, 17 - x = 7 - 6x
-x + 6x = 7 - 17
5x = -10
x = -10 : 5 = -2
Tìm x biêt: 2+4+6+8+...+x=42
Số số hạng là :
\(\left(x-2\right):2+1=x:2-1+1=x:2\) (số hạng)
Tổng trên là :
\(\left(x+2\right).x:2:2=42\)
\(\left(x+2\right).x=42.2.2\)
\(\left(x+2\right).x=168\)
\(\left(x+2\right).x=14.12\)
Vậy x = 14
Tìm x biêt:
a)|3x+1|=|x-5|
b)(2x-5)2=(x+1)2
c)(x-3)(x+4)<0
d)(x+7)(x+2)>0
Tìm x biêt' :
a) 1/2 + 2/3 . x = 4/5
b) | x + 3/4 | - 1/2 = 0
c) ( x + 1/3 )^3 = ( -1/8 )
a) \(\frac{1}{2}+\frac{2}{3}x=\frac{4}{5}\)
\(x=\frac{\left(\frac{4}{5}-\frac{1}{2}\right)}{\frac{2}{3}}\)
\(x=\frac{9}{20}\)
b) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)
\(\left|x+\frac{3}{4}\right|=0+\frac{1}{2}\)
\(\left|x+\frac{3}{4}\right|=\frac{1}{2}\)
\(\Rightarrow\hept{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{-1}{4}\\x=\frac{-5}{4}\end{cases}}}\)
Vậy x=-1/4 hoặc x=-5/4
c) \(\left(x+\frac{1}{3}\right)^3=\frac{-1}{8}\)
\(\Leftrightarrow x+\frac{1}{3}=\frac{-1}{8}=\frac{\left(-1\right)^3}{2^3}=\frac{-1}{2}\)
\(x=\frac{-1}{2}-\frac{1}{3}\)
\(x=\frac{-5}{6}\)
\(\frac{1}{2}+\frac{2}{3}x=\frac{4}{5}\)
\(\frac{2}{3}x=\frac{4}{5}-\frac{1}{2}\)
\(\frac{2}{3}x=\frac{3}{10}\)
\(x=\frac{3}{10}:\frac{2}{3}\)
\(x=\frac{9}{20}\)
b) l x + 3/4 l - 1/2 = 0
l x + 3/4 l = 1/2
TH1 : \(x+\frac{3}{4}\le0\) TH2: \(x+\frac{3}{4}\ge0\)
=> \(x+\frac{3}{4}=-\frac{1}{2}\) => \(x+\frac{3}{4}=\frac{1}{2}\)
\(x=-\frac{1}{2}-\frac{3}{4}\) \(x=\frac{1}{2}-\frac{3}{4}\)
\(x=-\frac{5}{4}\) \(x=-\frac{1}{4}\)
c) ( x + 1/3 )3 = ( -1/8 )
( x + 1/3 ) 3 = ( -1/3 )3
=> x + 1/3 = -1/3
x = -1/3 - 1/3
x = -2/3
Tìm x ,biêt :
3/5 : x = 3
3/5 : x = 3
x = 3/5 : 3
x = 3/5 x 1/3
x = 1/5
3/5 : x = 3
x = 3/5 : 3/1
x = 3/5 x 1/3
x= 3/15
x = 1/5
\(\frac{3}{5}:x=3\)
\(x=\frac{3}{5}:3\)
\(x=\frac{3}{5}.\frac{1}{3}\)
\(x=\frac{1}{5}\)
P/s: dấu (.) là nhân
Tìm x,biêt
a)x+7/x+3=2x+5/2x+1
b)x-2/x-1=x+4/x+7
Giai nhanh giug mình nha
Bài1:tìm x, biết
a)|x|+|x+2|=0 b)|x(x^2-5)|=x
Bài2:tìm giá trị nhỏ nhất
a)|x+3|-|x-5| b)|x+5|+|x+2|+|x-7|+|x-8|
c)|x+3|+|x-2|+|x-5|
Bài3:Tìm Max của
A=|x+5|-|x-2|
Bài 4 : Tìm x biêt: (1-|x|).|1+x|>0