So sánh ( không quy đồng):
a. \(\frac{55553}{55557}va\frac{555554}{555559}\)
b.\(\frac{2003}{2004}+\frac{2004}{2005}+\frac{2006}{2004}\)và 3
So sánh:
\(A=\frac{2003}{2004}+\frac{2005}{2006};B=\frac{2003+2004}{2004+2005}\)
so sánh A và B
A = \(\frac{2003}{2004}+\frac{2004}{2005}\)và B = \(\frac{2003+2004}{2004+2005}\)
\(B=\frac{2003+2004}{2004+2005}=\frac{2003}{2004+2005}+\frac{2004}{2004+2005}\)
Ta có: \(\frac{2003}{2004}>\frac{2003}{2004+2005}\)
\(\frac{2004}{2005}>\frac{2004}{2004+2005}\)
\(\frac{2003}{2004}+\frac{2004}{2005}>\frac{2003+2004}{2004+2005}\)
\(A>B\)
Vậy A>B
\(\text{ Bài giải}\)
\(A=\frac{2003}{2004}+\frac{2004}{2005}=0,999500998 + 0,999501247=1.99900225\)
\(B=\frac{2003+2004}{2004+2005}=\frac{4007}{4009}=0,999501122\)
\(\text{Vì : }1,99900224>0,999501122\text{ nên }A>B\)
\(\text{Vậy : }A>B\)
so sánh A và B
A=\(\frac{20032}{2004}+\frac{2004}{2005}\)và B = \(\frac{2003+2004}{2004+2005}\)
\(A=\frac{20032}{2004}+\frac{2004}{2005}=9,99600798+0,999501247=10,9955092\)
\(B=\frac{2003+2004}{2004+2005}=\frac{4007}{4009}\)
\(\text{Vì : }10,9955092>1\text{ mà }\frac{4007}{4009}< 1\text{ nên }10,9955092>\frac{4007}{4009}\)
\(\text{Vậy : }A>B\)
giải giùm mình với:
So sánh A và B, biết
\(A=\frac{2003+2004}{2004+2005}\)
\(B=\frac{2003}{2004+2005}\)+\(\frac{2004}{2004+2005}\)
Không lm tính, hãy so sánh: A= \(\frac{2004}{2005}\)+ \(\frac{2005}{2006}\) và B= \(\frac{2004+2005}{2005+2006}\)
Ta có :
\(B=\frac{2004+2005}{2005+2006}=\frac{2004}{2005+2006}+\frac{2005}{2005+2006}< \frac{2004}{2005}+\frac{2005}{2006}=A\)
\(\Rightarrow\)\(B< A\) hay \(A>B\)
Vây \(A>B\)
Chúc bạn học tốt ~
Câu này chắc chắn bằng vì hay phân số điều y chan mà
So sành \(\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}\)với 8
=1+1/2001+1+1/2002+1+1/2003+...+1+1/2008=8+1/2001+1/2002+1/2003+...+1/2008>8
\(\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>8\)
Ta có:
2002/2001=1+1/2001
2003/2002=1+1/2002
2004/2003= 1+ 1/2003
2005/2004= 1+ 1/2004
2006/2005=1+ 1/2005
2007/2006= 1+ 1/2006
2008/2007=1 + 1/2007.
2009/2008=1+ 1/2008.
=> 2002/2001+2003/2002+2004?2003+2005/2004+2006/2005+ 2007/2006+ 2008/2007+ 2009/2008= 1+1+1+1+1+1+1+1+1/2001+1/2002+1/2003+1/2004+1/2005+1/2006+1/2007+1/2008>8.
Nhớ k đúng cho mình nha!! Thanks!!!
So sanh cac phan so sau: \(\frac{2003}{2004};\frac{2004}{2005};\frac{2005}{2006}\)
so sánh A=\(\frac{2004^{2003}+1}{2004^{2004}+1}\) và B=\(\frac{2004^{2004}+1}{2004^{2005}+1}\)
so sánh A=\(\frac{2004^{2003}+1}{2004^{2004}+1}\) và B=\(\frac{2004^{2004}+1}{2004^{2005}+1}\)
\(2004A=\frac{2004^{2004}+2004}{2004^{2004}+1}=1+\frac{2003}{2004^{2004}+1}\)
\(2004B=\frac{2004^{2005}+2004}{2004^{2005}+1}=1+\frac{2003}{2004^{2005}+1}\)
\(\frac{2003}{2004^{2004}+1}>\frac{2003}{2004^{2005}+1}\)
\(\Rightarrow2004A>2004B\)
\(\Rightarrow A>B\)
2004A=\(\frac{2004^{2004}+2004}{2004^{2004}+1}\)
\(\frac{2004^{2004}+2004}{2004^{2004}+1}-1=\frac{2003}{2004^{2004}+1}\)
2004B=\(\frac{2004^{2005}+2004}{2004^{2005}+1}\)
\(\frac{2004^{2005}+2004}{2004^{2005}+1}-1=\frac{2003}{2004^{2005}+1}\)
Ta thấy :\(\frac{2003}{2004^{2004}+1}>\frac{2003}{2004^{2005}+1}\)
=> \(2004A>2004B\)
Vậy \(A>B\)