35) Tính giá trị của các biểu thức
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(B=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Tính giá trị các biểu thức
A=\(\frac{3^{10\ \ }.11+3^{10\ \ }.5}{3^{9\ }.2^{^4}\ }\)
B= \(\frac{2^{10}.13+2^{10\ }.65}{2^8.104}\)
C=\(\frac{72^3.54^2}{108^4}\)
D=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Bài3Tính giá trị biểu thức
a) A=\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
b) B=\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
c) C=\(\frac{72^3.54^2}{108^4}\)
d) D=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
A= 3^10.( 11+5 ) / 3^9. 2^4
A= 3^10. 16 /3 ^9 . 16
A= 3^10/3^9= 3
B= 2^10. ( 13 +65) / 2^8.104
B= 2^10. 78/ 2^8.104
B= 2 ^10.2.39/ 2^8 .2.52
B= 2^11.39/ 2^9.52
B= 2 ^ 2. (39/ 52)
B= 4 . 39/52 = 3
C= (2^3.3^2)^3.( 2.3.3^2 )^2 / (2^2.3^3)^4
C= 2^9.3^6/ 2^2.3^2.3^4
C= 2^9.3^6/ 2^2.3^6
C= 2^9/2^2= 2^5=32
D= 11.3^29-3^30/ 2^2.3^28
D= 3^29.(1- 3)/ 2^2.3^28
D= 3^29.(-2)/ 2^2.3^28
D= 3. (-2/2^2)
D = 3. (-1/2)= -3/2
\(A=\frac{3^{10}.11.3^{10}}{^{ }3^9.2^4}\)
\(B=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(C=\frac{72^3.54^2}{108^4}\)
\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Tính các gtri các biểu thức sau :
a, A = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
b,B=\(^{\frac{72^3.54^2}{108^4}}\)
c,C = \(\frac{11^{22}.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
d, D= \(\frac{\left(3.4.2^{16}\right)}{11.2^{13}.4^{11}-16^9}\)
a, A = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(A=\frac{2^{10}\left(13+65\right)}{2^8.2^2.26}=\frac{2^{10}.78}{2^{10}.26}=\frac{78}{26}=3\)
Vậy A = 3
b, \(B=\frac{72^3.54^2}{108^4}=\frac{72^3.54^2}{\left(54.2\right)^4}=\frac{72^3.54^2}{54^4.2^4}=\frac{72^3}{54^2.2^4}=\frac{\left(8.9\right)^3}{\left(6.9\right)^2.2^4}\)
\(=\frac{\left(2^3\right)^3.9^3}{6^2.9^2.2^4}=\frac{2^9.9^3}{2^2.3^2.9^2.2^4}=\frac{2^9.9^3}{2^6.9^3}=\frac{2^9}{2^6}=2^3=8\)
Vậy B = 8
c, \(C=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}.3^{30}}{2^2.3^{28}}=\frac{11.3^{29}.3.3^{29}}{2^2.3^{28}}=\frac{\left(11-3\right)3^{29}}{2^2.3^{28}}\)
\(=\frac{2^3.3^{29}}{2^2.3^{28}}=2.3=6\)
Vậy C = 6
d, \(D=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{\left(3.2^{18}\right)^2}{11.2^{35}-\left(2^4\right)^9}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{3^2.2^{36}}{\left(11-2\right)2^{35}}=\frac{3^2.2}{9}=2\)
Vậy D = 2
A=\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
B=\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
C=\(\frac{72^3.54^2}{108^4}\)
D=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Gợi ý
bn thực hiện phép tính tử mẫu bình thường , khi ra nhưng số trùng nhau bn gạch ra nháp cho đến nhưng số tối giản là ra nha
chúc bn
học tốt
A = \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
= \(\frac{3^{10}\left(11+5\right)}{3^9.2^4}\)
= \(\frac{3^{10}.16}{3^9.2^4}\)
= \(\frac{3^{10}.2^4}{3^9.2^4}=3\)
B = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
= \(\frac{2^{10}\left(13+65\right)}{2^8.104}\)
= \(\frac{2^{10}.78}{2^8.104}\)
= \(\frac{2^{10}.13.2.3}{2^8.2^3.13}\)
= \(\frac{2^{11}.13.3}{2^{11}.13}=3\)
C = \(\frac{72^3.54^2}{108^4}\)
= \(\frac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{\left(2^2.3^3\right)^4}\)
= \(\frac{2^9.3^6.2^2.3^6}{2^8.3^{12}}\)
= \(\frac{2^{11}.3^{12}}{2^8.3^{12}}\)
= \(2^3=8\)
Tính giá trị của các biểu thức :
a , A = \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
b , B = \(\frac{4^9.36+64^4}{16^4.100}\)
c , C = \(\frac{72^3.54^2}{108^4}\)
d , D = \(\frac{4^6.3^4.9^5}{6^{12}}\)
e , E = \(\frac{2^{13}+2^5}{2^{10}+2^2}\)
f , F = \(\frac{21^2.14.125}{35^5.6}\)
g , G = \(\frac{45^3.20^4.18^2}{180^5}\)
h , H = \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
mấy bn lm giúp mk nha , mk tk cho 3 tk
tính giá trị của biểu thức
A=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Tính giá trị của biểu thức: \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(a=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{\left(2^2.3^{28}\right)}=\frac{11.3^{29}-3.^{30}}{2^2.328}\)
\(=\frac{3^{28}\left(11.3-3^2\right)}{2^2.3^{28}}=\frac{33-9}{4}=6\)
tính giá trị biểu thức
\(\frac{11.3^{22}.3^8-9^{15}}{\left[2.3^{14}\right]^2}\)