\(2^{24}=(2^3)^8=8^8\)

\(3^{16}=\left(3^2\right)^8=9^8\)

vì \(8^8< 9^8\Rightarrow2^{24}< 3^{16}\)

\(2^{24}=\left(2^3\right)^8=8^8\) 

\(3^{16}=\left(3^2\right)^8=9^8\) 

\(8< 9\) 

\(\Rightarrow8^9< 9^9\) 

\(\Rightarrow2^{24}< 3^{16}\)

Ta có: 104²⁰¹⁵ + 2 < 104²⁰¹⁶ + 2.

=> A = \(\frac{104^{2015}+2}{104^{2016}+2}\)< 1 (1).

Ta có: 104²⁰¹⁶ + 2 > 104²⁰ + 2 > 104²⁰.

=> B = \(\frac{104^{2016}+2}{104^{20}}\) > 1 (2).

Từ (1) và (2) => A < 1 < B => A < B.

Chúc bạn học tốt nhé!

bạn ơi giúp mình sửa mẫu của B thành 104^2017+2 nhé

Thanks bạn nhìu

    A = 8 - 8² + 8 + 8³ + 8⁴+ ......+ 8⁹⁹

        A = ( 8 - 8 ) + ( 8² + 8³ + 8⁴ +......+ 8⁹⁹ )

        A = 8² + 8³ + 8⁴ +......+ 8⁹⁹

       8A = 8³ + 8⁴ + 8⁵ +.......+ 8¹⁰⁰ 

  8A - A = ( 8³ + 8⁴ +...+ 8¹⁰⁰ ) - ( 8² + 8³ + ...+ 8⁹⁹ )

       7A = 8¹⁰⁰ - 8²

    => A = \(\frac{8^{100}-8^2}{7}\)

VẬY, \(A=\frac{8^{100}-8^2}{7}\)

a) 

Ta có : 4²⁸ = (2²)²⁸ = 2⁵⁶

Vì 2⁵⁶ > 2³⁵

=> 4²⁸ > 2³⁵

A=\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2014}{2015}.\frac{2015}{2016}\)

A=\(\frac{1.2.3.4...2015}{2.3.4...2016}=\frac{1}{2016}\)

Hok tốt

A = \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2015}\right).\left(1-\frac{1}{2016}\right)\)

= \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2014}{2015}.\frac{2015}{2016}\)

= \(\frac{1}{2016}\)

Vậy ...

\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)......\left(1-\frac{1}{2015}\right)\left(1-\frac{1}{2016}\right)\)

\(\Rightarrow A=\frac{1.2.3.4....2015}{2.3.4....2016}\)

\(\Rightarrow A=\frac{1}{2016}\)

#hok tốt

Ta có:\(\frac{-157}{623}=\frac{-331441}{132699}\)

           \(\frac{-47}{213}=\frac{-29281}{132699}\)

  Vì \(-331441< -29281\)nên\(\frac{-331441}{132699}< \frac{-29281}{132699}\)

                                                     hay\(\frac{-157}{623}< \frac{-47}{213}\)

              Vậy \(\frac{-157}{623}< \frac{-47}{213}\)

\(\frac{-157}{623}< \frac{-47}{213}\)

|x|+1/5=2

=> |x|=2-1/5

=> |x|=9/5

=> x=±9/5

=>|x|=2-1/5

|x|=9/2

=>x=9/2 hoặc x=-9/2

 |x| + 1/5 = 2

|x|= 2 - 1/5

|x|= 10/5 - 1/5

|x|= 9/5

  Suy ra:

Trường hợp 1 : x= 9/5

Trường hợp 2 : x= -9/5