1/2*1/2+1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6
giup mk nha mai mk phải nộp rồi
ai giup mk vao toi nay mk tik cho 5 lần
Thực hiện phép tính:
(1-1/2^2)(1-1/3^2)(1-1/4^2)(1-1/5^2)...(1-1/2017^2)
Giup mk nha, mai mk nộp bài rồi!
bạn bài này ở đâu vậy trong sách giao khoa à ?
bai nay lam sao hon so nha tinh gia tri bieu thiuc 3/4 + 2 1/5 * 3 3/4 cau hai 11/4 - 2 1/5 chia 3 3/4 giup mk nha mk ko bit lam nan ni nhanh k tik cho
bai 1 tinh nhanh
a . 1/5x6 +1/6x7+ 1/7x8 + 1/8x9 +1/9x10
b . 1/1x2 + 1/2x3 + ....... + 1/99x100
c . 2/3x5 + 2/5x7 + 2/7x8 + 2/8x9
d . 2/3x5 + 2/5x7 + .......+ 2/98x100
bai 2 tinh hop li
9/13 + 14/6 + 1/9 + 4/6 + 7/13 + 17/19
bai 3 dien dau ( > , < , = )
a . 3/4 + 5/2 ....... 5/8 + 2 3/5 ( hon so )
B . 3 1/5 - 8/3 ......... 17/5 - 2 12/5 hon so
c . 2 4/9 + 18/7......... 22/9 + 2 4/7
giup mk nha cac ban , mai mk phai nop bai roi toi nay mk se lay y kien cua cac ban , giup mk nha
b1
a) \(\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\)
\(=\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=\dfrac{1}{5}-\dfrac{1}{10}\)
\(=\dfrac{2}{10}-\dfrac{1}{10}\)
\(=\dfrac{1}{10}\)
b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}\)
\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)
\(=\dfrac{1}{1}-\dfrac{1}{100}\)
\(=\dfrac{99}{100}\)
c) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\)
\(=\dfrac{1}{3}-\dfrac{1}{11}\)
\(=\dfrac{8}{33}\)
d) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{99.101}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\)
\(=\dfrac{1}{3}-\dfrac{1}{101}\)
\(=\dfrac{98}{303}\)
Thu gọn a):\(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right).....\left(2^{32}+1\right)-2^{64}\)
b)\(\left(5+3\right)\left(5^2+3^2\right)\left(5^4+3^4\right)...\left(5^{64}+3^{64}\right)+\frac{5^{128}-3^{128}}{2}\)
các pn júp mk nha, mk tik cho, mk cần ngày mai nộp roài
a) (2+1)(2^2+1)(2^4+1)...(2^32+1)-2^64
=(2+1)(2-1)(2^2+1)(2^4+1)...(2^32+1)-2^64
=(2^2-1)(2^2+1)(2^4+1)...(2^32+1)-2^64
=(2^4-1)(2^4+1)....(2^32+1)-2^64
=......
=(2^32-1)(2^32+1)-2^64
=2^64-1-2^64=-1
b)Đặt A=(5+3)(5^2+3^2)(5^4+3^4)...(5^64+3^64)+(5^128-3^128)/2
đặt B=(5+3)(5^2+3^2)(5^4+3^4)...(5^64+3^64)
\(2B=\left(5-3\right)\left(5+3\right)\left(5^2+3^2\right)\left(5^4+3^4\right)...\left(5^{64}+3^{64}\right)\)
\(2B=\left(5^2-3^2\right)\left(5^2+3^2\right)\left(5^4+3^4\right)...\left(5^{64}+3^{64}\right)\)
\(2B=\left(5^4-3^4\right)\left(5^4+3^4\right)...\left(5^{64}+3^{64}\right)\)
\(2B=.......\)
2B=(5^64-3^64)(5^64+3^64)
2B=5^128-3^128
B=(5^128-3^128)/2 (thế vào đề bài)
=> A=B+(5^128-3^128)/2=(5^128-3^128)/2+(5^128-3^128)/2=\(\frac{2\left(5^{128}-3^{128}\right)}{2}=\left(5^{128}-3^{128}\right)\)
a) A = ( 2-1)(2+1)(22+1)...(232+1)-264
=(22-1)(22+1)(24+1)... -264
=....
=264-1-264=1
câu b tương tự nhá
Giúp mk bài này vs các bạn ơi!!! Mai mk pải nộp rùi!! Bạn nào giải đầy đủ mk tích cho nha!!
Tính giá trị biểu thức :
A=2/3 + 5/5 ÷ 5 - 1/18 × (-3)^2
B=3×{5 × [(5^2+2^3)÷11]÷16}2015
C=(1+1/1×3)×(1+1/2×4)×(1+1/3×5)×....×(1+1/2014×2016)
https://dethihsg.com/de-thi-hoc-sinh-gioi-phong-gđt-hoang-hoa-2014-2015/
Tính bằng 2 cách:
A= (3-1/4+2/3) - (5+1/3-6/5) - (6-7/4+3/2)
Giúp mk nghen! Mai mk phải nộp bài rùi!!!
\(A=3-\frac{1}{4}+\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(=3-6-5+\frac{7-1}{4}+\frac{2-1}{3}-\frac{3}{2}+\frac{6}{5}=-8+\frac{3}{2}+\frac{1}{3}-\frac{3}{2}+\frac{6}{5}=-8+\frac{1}{3}+\frac{6}{5}=-\frac{97}{15}\)
Tính :
a) A= 2/1*4+2/4*7+2/7*10+...+2/31*34
b)B= 3/1+3/3+3/6+...+3/210
c)C=3/2*3*4+3/3*4*5+3/4*5*6+...+3/100*101*102
d)D=5/1+2+5/1+2+3+5/1+2+3+4+...+5/1+2+3+4+.....+100
nhanh hộ mk nha
chiều nay mk phải nộp cho cô rùi
a) \(A=\frac{2}{1.4}+\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{31.34}\)
\(A=\frac{2}{3}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{31}-\frac{1}{34}\right)\)
\(A=\frac{2}{3}.\left(1-\frac{1}{34}\right)\)
\(A=\frac{2}{3}\cdot\frac{33}{34}=\frac{11}{17}\)
b) \(B=\frac{3}{1}+\frac{3}{3}+\frac{3}{6}+...+\frac{3}{210}\)
\(B=\frac{6}{2}+\frac{6}{6}+\frac{6}{12}+...+\frac{6}{420}\) ( 3/1 = 6/2; 6/6=3/3;..)
\(B=\frac{6}{1.2}+\frac{6}{2.3}+\frac{6}{3.4}+...+\frac{6}{20.21}\)
\(B=6.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{20}-\frac{1}{21}\right)\)
\(B=6.\left(1-\frac{1}{21}\right)=6\cdot\frac{20}{21}=\frac{40}{7}\)
(1/1*1/2+1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6)*10-x=0
Giải ra giúp mk nha mk tik
Làm như zậy bạn nhé ^_^"
Đặt :
\(A=\left(\frac{1}{1}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+\frac{1}{5}.\frac{1}{6}\right)\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{5.6}\)( mik lười viết bạn thông cảm nhé !!! )
\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)
\(A=\frac{1}{1}-\frac{1}{6}\)
\(A=\frac{5}{6}\)
Thay A vào biểu thức :
Ta có : \(\frac{5}{6}.10-x=0\)
=> \(\frac{25}{3}=x+0\)
=> \(x=\frac{25}{3}\)
(1/1*1/2+1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6)*10-x=0
=> (1/1.2+1/2.3+1/3.4+1/4.5+1/5.6)*10-x=0
=> (1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6)*10-x=0
=> (1-1/6)*10-x=0
=> 5/6*10-x=0
=> 25/3-x =0
=> x=0+25/3
=> x=25/3
Vậy x=25/3
-5/3-(5/12-3/4)<X<11/6-(1/3+1/4)
GIÚP MK VỚI MAI MK PHẢI NỘP RÙI AI NHANH MK TICK CHO NHÉ
\(\dfrac{-5}{3}-\left(\dfrac{5}{12}-\dfrac{3}{4}\right)< x< \dfrac{11}{6}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)\)
\(\Rightarrow\left\{{}\begin{matrix}x>\dfrac{-5}{3}-\left(\dfrac{5}{12}-\dfrac{3}{4}\right)\\x< \dfrac{11}{6}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>\dfrac{-5}{3}-\dfrac{5}{12}+\dfrac{3}{4}\\x< \dfrac{11}{6}-\dfrac{1}{3}-\dfrac{1}{4}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>\dfrac{-20}{12}-\dfrac{5}{12}+\dfrac{9}{12}\\x< \dfrac{22}{12}-\dfrac{4}{12}-\dfrac{3}{12}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>-\dfrac{4}{3}\\x< \dfrac{5}{4}\end{matrix}\right.\Rightarrow x\in\left\{-\dfrac{4}{3};\dfrac{5}{4}\right\}}\)