\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)

giúp tớ nhé 

tớ bị trừ 41 điểm 

cảm ơn trước

cảm ơn huhuh

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=\frac{3^1}{1}=3\)

\(\frac{81^{12}.3^{17}}{27^{10}.9^{15}}\)

= \(\frac{9^{13}.3^{17}}{3^{13}.9^{15}}\)

=  \(\frac{3^4}{9^2}\)

= \(\frac{81}{81}\)

= 1

\(A=\frac{\left(9^2\right)^{11}.3^{17}}{\left(3^3\right)^{10}.9^{15}}=\frac{9^{22}.3^{17}}{3^{30}.9^{15}}=\frac{9^7}{3^{12}}=9\)

\(\left(\frac{1}{4}\right)^{44}.\left(\frac{1}{2}\right)^{12}=\left(\left(\frac{1}{2}\right)^2\right)^{44}.\left(\frac{1}{2}\right)^{12}=\left(\frac{1}{2}\right)^{88}.\left(\frac{1}{2}\right)^{12}=\left(\frac{1}{2}\right)^{100}\)

\(\frac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{17}.3^{44}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)

3^12.(3^4)^11/(3^3)^10.(3^2)^15=3^12.3^44/3^30.3^30=3^56/3^30

=3^17.9^22/3^30.9^15=9^7/3^13=3^14/3^13=3^1=3

giùm nhé bạn

\(\frac{2^{15}.9^4}{6^3.8^3}\)=\(\frac{2^{15}.\left(3^2\right)^3}{\left(2.3\right)^3.\left(2^3\right)^3}\)=\(\frac{2^{15}.3^6}{2^3.3^3.2^9}\)=\(\frac{2^{15}.3^6}{2^{12}.3^3}\)=\(2^3.3^3\)=8.27=216

1. Từ bé đến lớn: \(\frac{3}{10};\frac{8}{15};\frac{9}{6};\frac{13}{5};\frac{16}{3}\)

2. 

a, Ta có: \(\frac{24}{36}=\frac{6}{9}\)  ;  \(\frac{15}{27}=\frac{5}{9}\)

Vì \(\frac{6}{9}>\frac{5}{9}\)nên \(\frac{24}{36}>\frac{15}{27}\)

P/s: Các câu còn lại tương tự :>

\(3^{17}.81^{11}:27^{10}.9^{15}\)

=\(3^{17}.\left(3^4\right)^{11}:\left(3^3\right)^{10}.\left(3^2\right)^{15}\)

=\(3^{17}.3^{44}:3^{30}.3^{30}\)

=\(3^{17+44-30+30}\)

=\(3^{61}\)