1/8+1/32+1/128+1/512+1/248
Ai gí em giải cái này cái
tính mấy cái này jup mik
1+1
2+2
4+4
8+8
16+16
32+32
64+64
128+128
256+256
512+512
1024+1024
1 + 1 = 2
2 + 2 = 4
4 + 4 = 8
8 + 8 = 16
16 + 16 = 32
32 + 32 = 64
64 + 64 = 128
128 + 128 = 256
256 + 256 = 512
512 + 512 = 1024
1024 + 1024 = 2048
Các kết quả bạn ghi đều nối kết quả với nhau nên mình không cần tính , chỉ cần tính ở đoạn 1024 cộng 1024 thôi !
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048
1 + 1 = 2 2 + 2 = 4
4 + 4 = 8 8 + 8 = 16
16 + 16 = 32 32 + 32 = 64
64 + 64 = 128 128 + 128 = 256
256 + 256 = 512 512 + 512 = 1024
1024 + 1024 = 2048
bạn tk mik nha
Tính A : 1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512+1/1024
giải chi tiết
Mình nghĩ đây là nâng cao tiểu học
Đặt S = 1/2 + 1/4 + 1/8 + 1/16 + ...
==> 2S = 1 + 1/2 + 1/4 + 1/8 + 1/16 + ...
2S = 1 + S
==> S = 1
Đây cũng là kết quả khi tính theo cấp số nhân khi n --> vô cùng
2A=1+1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512
2A-A=1-1/1024
A=1-1/1024
A=1023/1024
\(=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{10}}\)
\(2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^9}\)
\(2A-A=1-\frac{1}{2^{10}}\)
\(\Rightarrow A=\frac{1}{2^{10}-1}\)\(=\frac{1}{1023}\)
nha
Ai giúp mình làm bài này với!!!!!
1/8+1/32+1/128+1/512+1/2048
\(\frac{1}{8}+\frac{1}{32}+\frac{1}{128}+\frac{1}{512}+\frac{1}{2048}\)
= \(\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}+\frac{1}{2^{11}}\)
= \(\frac{341}{2048}\)
1+1=?
2+2=?
4+4=?
8+8=?
16+16=?
32+32=?
64+64=?
128+128=?
256+256=?
512+512=?
1024+1024=?
2048+2048=?
4096+4096=?
Giải đi
2
4
8
16
32
64
128
256
512
1024
2048
4096
8192
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
64+64=128
128+128=256
512+512=1024
2048+2048=4096
xong
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048
2048+2048=4096
4096+4096=8192
A=1/2+1/8+1/32+1/128+1/512+1/2048
Đề bài: Tính
\(A=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}+\frac{1}{128}+\frac{1}{512}+\frac{1}{2048}\)
\(A=\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}+\frac{1}{2^{11}}\)
\(2^2.A=2+\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\)
\(4A-A=\left(2+\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\right)-\left(\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}+\frac{1}{2^{11}}\right)\)
\(3A=2-\frac{1}{2^{11}}\)
\(\Rightarrow A=\frac{2-\frac{1}{2^{11}}}{3}\)
Vậy \(A=\frac{2-\frac{1}{2^{11}}}{3}\).
ta có
A= 1/2+ 1/8+1/32+1/128+1/512+1/2048
=> A= 1/2 +1/ 2^3 +1/2^5 +1/2^7+1/2^9+1/2^11
=> 2^2 A=2+1/2+1/2^3+1/2^5+1/2^7+1/2^9
=> 2^2A-A= (2+1/2+1/2^3+1/2^5+1/2^7+1/2^9)-(1/2+1/2^3+/2^5+1/2^7+1/2^9+1/2^11)
=> 3A= 2- 1/2^11
=>3A= 4095/2048
=> A= 1365/2048
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
A= 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
A = 1 - 1/2 + 1/2- 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128 + 1/128 - 1/256 - 1/256 - 1/512
A = 1 - 1/512
A = 511/512
Chúc bạn học giỏi nha!
gọi biểu thức đó là A
A=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512
1/512+A=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512+1/512
1/512+A=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/256
1/512+A=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/128
1/512+A=1/2+1/4+1/8+1/16+1/32+1/64+1/64
1/512+A=1/2+1/4+1/8+1/16+1/32+1/32
1/512+A=1/2+1/4+1/8+1/16+1/16
1/512+A=1/2+1/4+1/8+1/8
1/512+A=1/2+1/4+1/4
1/512+A=1/2+1/2
1/512+A=1
A=1-1/512
A=511/512
chắc 100%
Tính nhanh : 1+1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512+/1024
1+1=
2+2=
4+4=
8+8=
16+16=
32+32=
64+64=
128+128=
256+256=
512+512=
1024+1024=
1 + 1 = 2
2 + 2 = 4
4 + 4 = 8
8 + 8 = 16
16 + 16 = 32
32 + 32 = 64
64 + 64 = 128
128 + 128 = 256
256 + 256 = 512
512 + 512 = 1024
1024 + 1024 = 2048
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=265
256+256=512
512+512=1024
1024+1024=2048
Học tốt ^_^
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048